当通过lambda表达式传入时，是否有更好的方法来获得属性名?
这是我目前拥有的。
eg.
GetSortingInfo<User>(u => u.UserId);
它只在属性为字符串时才将其转换为成员表达式。因为不是所有的属性都是字符串，我必须使用object，但它会为那些返回一个unaryexpression。
public static RouteValueDictionary GetInfo<T>(this HtmlHelper html,
Expression<Func<T, object>> action) where T : class
{
var expression = GetMemberInfo(action);
string name = expression.Member.Name;
return GetInfo(html, name);
}
private static MemberExpression GetMemberInfo(Expression method)
{
LambdaExpression lambda = method as LambdaExpression;
if (lambda == null)
throw new ArgumentNullException("method");
MemberExpression memberExpr = null;
if (lambda.Body.NodeType == ExpressionType.Convert)
{
memberExpr =
((UnaryExpression)lambda.Body).Operand as MemberExpression;
}
else if (lambda.Body.NodeType == ExpressionType.MemberAccess)
{
memberExpr = lambda.Body as MemberExpression;
}
if (memberExpr == null)
throw new ArgumentException("method");
return memberExpr;
}
当涉及到Array.Length时，有一个边缘情况。虽然'Length'被公开为属性，但您不能在任何前面提出的解决方案中使用它。
using Contract = System.Diagnostics.Contracts.Contract;
using Exprs = System.Linq.Expressions;
static string PropertyNameFromMemberExpr(Exprs.MemberExpression expr)
{
return expr.Member.Name;
}
static string PropertyNameFromUnaryExpr(Exprs.UnaryExpression expr)
{
if (expr.NodeType == Exprs.ExpressionType.ArrayLength)
return "Length";
var mem_expr = expr.Operand as Exprs.MemberExpression;
return PropertyNameFromMemberExpr(mem_expr);
}
static string PropertyNameFromLambdaExpr(Exprs.LambdaExpression expr)
{
if (expr.Body is Exprs.MemberExpression) return PropertyNameFromMemberExpr(expr.Body as Exprs.MemberExpression);
else if (expr.Body is Exprs.UnaryExpression) return PropertyNameFromUnaryExpr(expr.Body as Exprs.UnaryExpression);
throw new NotSupportedException();
}
public static string PropertyNameFromExpr<TProp>(Exprs.Expression<Func<TProp>> expr)
{
Contract.Requires<ArgumentNullException>(expr != null);
Contract.Requires<ArgumentException>(expr.Body is Exprs.MemberExpression || expr.Body is Exprs.UnaryExpression);
return PropertyNameFromLambdaExpr(expr);
}
public static string PropertyNameFromExpr<T, TProp>(Exprs.Expression<Func<T, TProp>> expr)
{
Contract.Requires<ArgumentNullException>(expr != null);
Contract.Requires<ArgumentException>(expr.Body is Exprs.MemberExpression || expr.Body is Exprs.UnaryExpression);
return PropertyNameFromLambdaExpr(expr);
}
现在看用法示例:
int[] someArray = new int[1];
Console.WriteLine(PropertyNameFromExpr( () => someArray.Length ));
如果PropertyNameFromUnaryExpr没有检查ArrayLength， "someArray"将被打印到控制台(编译器似乎生成了对支持Length字段的直接访问，作为优化，甚至在调试中，因此是特殊情况)。
我已经完成了类似于下面方法的INotifyPropertyChanged实现。在这里，属性存储在基类中的字典中，如下所示。当然，使用继承并不总是可取的，但是对于视图模型，我认为它是可以接受的，并且在视图模型类中给出了非常干净的属性引用。
public class PhotoDetailsViewModel
: PropertyChangedNotifierBase<PhotoDetailsViewModel>
{
public bool IsLoading
{
get { return GetValue(x => x.IsLoading); }
set { SetPropertyValue(x => x.IsLoading, value); }
}
public string PendingOperation
{
get { return GetValue(x => x.PendingOperation); }
set { SetPropertyValue(x => x.PendingOperation, value); }
}
public PhotoViewModel Photo
{
get { return GetValue(x => x.Photo); }
set { SetPropertyValue(x => x.Photo, value); }
}
}
稍微复杂一些的基类如下所示。它处理从lambda表达式到属性名的转换。注意，这些属性实际上是伪属性，因为只使用了名称。但是它对于视图模型和视图模型上的属性引用来说是透明的。
public class PropertyChangedNotifierBase<T> : INotifyPropertyChanged
{
readonly Dictionary<string, object> _properties = new Dictionary<string, object>();
protected U GetValue<U>(Expression<Func<T, U>> property)
{
var propertyName = GetPropertyName(property);
return GetValue<U>(propertyName);
}
private U GetValue<U>(string propertyName)
{
object value;
if (!_properties.TryGetValue(propertyName, out value))
{
return default(U);
}
return (U)value;
}
protected void SetPropertyValue<U>(Expression<Func<T, U>> property, U value)
{
var propertyName = GetPropertyName(property);
var oldValue = GetValue<U>(propertyName);
if (Object.ReferenceEquals(oldValue, value))
{
return;
}
_properties[propertyName] = value;
RaisePropertyChangedEvent(propertyName);
}
protected void RaisePropertyChangedEvent<U>(Expression<Func<T, U>> property)
{
var name = GetPropertyName(property);
RaisePropertyChangedEvent(name);
}
protected void RaisePropertyChangedEvent(string propertyName)
{
if (PropertyChanged != null)
{
PropertyChanged(this, new PropertyChangedEventArgs(propertyName));
}
}
private static string GetPropertyName<U>(Expression<Func<T, U>> property)
{
if (property == null)
{
throw new NullReferenceException("property");
}
var lambda = property as LambdaExpression;
var memberAssignment = (MemberExpression) lambda.Body;
return memberAssignment.Member.Name;
}
public event PropertyChangedEventHandler PropertyChanged;
}
我最近做了一件非常类似的事情来创建一个类型安全的OnPropertyChanged方法。
下面是一个方法，它将返回表达式的PropertyInfo对象。如果表达式不是属性，则抛出异常。
public PropertyInfo GetPropertyInfo<TSource, TProperty>(
TSource source,
Expression<Func<TSource, TProperty>> propertyLambda)
{
Type type = typeof(TSource);
MemberExpression member = propertyLambda.Body as MemberExpression;
if (member == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a method, not a property.",
propertyLambda.ToString()));
PropertyInfo propInfo = member.Member as PropertyInfo;
if (propInfo == null)
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a field, not a property.",
propertyLambda.ToString()));
if (type != propInfo.ReflectedType &&
!type.IsSubclassOf(propInfo.ReflectedType))
throw new ArgumentException(string.Format(
"Expression '{0}' refers to a property that is not from type {1}.",
propertyLambda.ToString(),
type));
return propInfo;
}
使用源参数，编译器可以对方法调用进行类型推断。您可以执行以下操作
var propertyInfo = GetPropertyInfo(someUserObject, u => u.UserID);
public string GetName<TSource, TField>(Expression<Func<TSource, TField>> Field)
{
return (Field.Body as MemberExpression ?? ((UnaryExpression)Field.Body).Operand as MemberExpression).Member.Name;
}
这个函数处理成员表达式和一元表达式。区别在于，如果你的表达式表示值类型，你将得到一个UnaryExpression，而如果你的表达式表示引用类型，你将得到一个MemberExpression。所有内容都可以转换为对象，但值类型必须被装箱。这就是UnaryExpression存在的原因。参考。
出于可读性考虑(@Jowen)，这里有一个扩展的等效内容:
public string GetName<TSource, TField>(Expression<Func<TSource, TField>> Field)
{
if (object.Equals(Field, null))
{
throw new NullReferenceException("Field is required");
}
MemberExpression expr = null;
if (Field.Body is MemberExpression)
{
expr = (MemberExpression)Field.Body;
}
else if (Field.Body is UnaryExpression)
{
expr = (MemberExpression)((UnaryExpression)Field.Body).Operand;
}
else
{
const string Format = "Expression '{0}' not supported.";
string message = string.Format(Format, Field);
throw new ArgumentException(message, "Field");
}
return expr.Member.Name;
}
