从lambda表达式中检索属性名称

当通过lambda表达式传入时，是否有更好的方法来获得属性名? 这是我目前拥有的。

eg.

GetSortingInfo<User>(u => u.UserId);

它只在属性为字符串时才将其转换为成员表达式。因为不是所有的属性都是字符串，我必须使用object，但它会为那些返回一个unaryexpression。

public static RouteValueDictionary GetInfo<T>(this HtmlHelper html, 
    Expression<Func<T, object>> action) where T : class
{
    var expression = GetMemberInfo(action);
    string name = expression.Member.Name;

    return GetInfo(html, name);
}

private static MemberExpression GetMemberInfo(Expression method)
{
    LambdaExpression lambda = method as LambdaExpression;
    if (lambda == null)
        throw new ArgumentNullException("method");

    MemberExpression memberExpr = null;

    if (lambda.Body.NodeType == ExpressionType.Convert)
    {
        memberExpr = 
            ((UnaryExpression)lambda.Body).Operand as MemberExpression;
    }
    else if (lambda.Body.NodeType == ExpressionType.MemberAccess)
    {
        memberExpr = lambda.Body as MemberExpression;
    }

    if (memberExpr == null)
        throw new ArgumentException("method");

    return memberExpr;
}

当前回答

我在ObjectStateEntry上创建了一个扩展方法，以便能够以类型安全的方式标记(实体框架POCO类的)属性，因为默认方法只接受字符串。这是我从属性中获取名称的方式:

public static void SetModifiedProperty<T>(this System.Data.Objects.ObjectStateEntry state, Expression<Func<T>> action)
{
    var body = (MemberExpression)action.Body;
    string propertyName = body.Member.Name;

    state.SetModifiedProperty(propertyName);
}

2011-02-03 09:34:47

其他回答

我也在玩同样的东西，然后做了这个。它还没有完全测试过，但似乎处理了值类型的问题(你遇到的unaryexpression问题)

public static string GetName(Expression<Func<object>> exp)
{
    MemberExpression body = exp.Body as MemberExpression;

    if (body == null) {
       UnaryExpression ubody = (UnaryExpression)exp.Body;
       body = ubody.Operand as MemberExpression;
    }

    return body.Member.Name;
}

2010-05-26 20:04:42

我发现了另一种方法，就是让源和属性具有强类型，并显式地推断lambda的输入。不确定这是否是正确的术语，但这是结果。

public static RouteValueDictionary GetInfo<T,P>(this HtmlHelper html, Expression<Func<T, P>> action) where T : class
{
    var expression = (MemberExpression)action.Body;
    string name = expression.Member.Name;

    return GetInfo(html, name);
}

然后像这样叫它。

GetInfo((User u) => u.UserId);

瞧，它起作用了。

2009-03-23 05:39:54

这可能是最优的

public static string GetPropertyName<TResult>(Expression<Func<TResult>> expr)
{
    var memberAccess = expr.Body as MemberExpression;
    var propertyInfo = memberAccess?.Member as PropertyInfo;
    var propertyName = propertyInfo?.Name;

    return propertyName;
}

2019-11-25 09:28:45

这是另一个答案:

public static string GetPropertyName<TModel, TProperty>(this HtmlHelper<TModel> htmlHelper,
                                                                      Expression<Func<TModel, TProperty>> expression)
    {
        var metaData = ModelMetadata.FromLambdaExpression(expression, htmlHelper.ViewData);

        return metaData.PropertyName;
    }

2015-01-02 00:44:29

这是卡梅隆提出的方法的更新。第一个参数不是必需的。

public PropertyInfo GetPropertyInfo<TSource, TProperty>(
    Expression<Func<TSource, TProperty>> propertyLambda)
{
    Type type = typeof(TSource);

    MemberExpression member = propertyLambda.Body as MemberExpression;
    if (member == null)
        throw new ArgumentException(string.Format(
            "Expression '{0}' refers to a method, not a property.",
            propertyLambda.ToString()));

    PropertyInfo propInfo = member.Member as PropertyInfo;
    if (propInfo == null)
        throw new ArgumentException(string.Format(
            "Expression '{0}' refers to a field, not a property.",
            propertyLambda.ToString()));

    if (type != propInfo.ReflectedType &&
        !type.IsSubclassOf(propInfo.ReflectedType))
        throw new ArgumentException(string.Format(
            "Expresion '{0}' refers to a property that is not from type {1}.",
            propertyLambda.ToString(),
            type));

    return propInfo;
}

您可以执行以下操作:

var propertyInfo = GetPropertyInfo<SomeType>(u => u.UserID);
var propertyInfo = GetPropertyInfo((SomeType u) => u.UserID);

扩展方法:

public static PropertyInfo GetPropertyInfo<TSource, TProperty>(this TSource source,
    Expression<Func<TSource, TProperty>> propertyLambda) where TSource : class
{
    return GetPropertyInfo(propertyLambda);
}

public static string NameOfProperty<TSource, TProperty>(this TSource source,
    Expression<Func<TSource, TProperty>> propertyLambda) where TSource : class
{
    PropertyInfo prodInfo = GetPropertyInfo(propertyLambda);
    return prodInfo.Name;
}

您可以:

SomeType someInstance = null;
string propName = someInstance.NameOfProperty(i => i.Length);
PropertyInfo propInfo = someInstance.GetPropertyInfo(i => i.Length);

2014-09-25 03:39:18

从lambda表达式中检索属性名称

推荐文章

最新文章

标签