当通过lambda表达式传入时,是否有更好的方法来获得属性名? 这是我目前拥有的。

eg.

GetSortingInfo<User>(u => u.UserId);

它只在属性为字符串时才将其转换为成员表达式。因为不是所有的属性都是字符串,我必须使用object,但它会为那些返回一个unaryexpression。

public static RouteValueDictionary GetInfo<T>(this HtmlHelper html, 
    Expression<Func<T, object>> action) where T : class
{
    var expression = GetMemberInfo(action);
    string name = expression.Member.Name;

    return GetInfo(html, name);
}

private static MemberExpression GetMemberInfo(Expression method)
{
    LambdaExpression lambda = method as LambdaExpression;
    if (lambda == null)
        throw new ArgumentNullException("method");

    MemberExpression memberExpr = null;

    if (lambda.Body.NodeType == ExpressionType.Convert)
    {
        memberExpr = 
            ((UnaryExpression)lambda.Body).Operand as MemberExpression;
    }
    else if (lambda.Body.NodeType == ExpressionType.MemberAccess)
    {
        memberExpr = lambda.Body as MemberExpression;
    }

    if (memberExpr == null)
        throw new ArgumentException("method");

    return memberExpr;
}

当前回答

当涉及到Array.Length时,有一个边缘情况。虽然'Length'被公开为属性,但您不能在任何前面提出的解决方案中使用它。

using Contract = System.Diagnostics.Contracts.Contract;
using Exprs = System.Linq.Expressions;

static string PropertyNameFromMemberExpr(Exprs.MemberExpression expr)
{
    return expr.Member.Name;
}

static string PropertyNameFromUnaryExpr(Exprs.UnaryExpression expr)
{
    if (expr.NodeType == Exprs.ExpressionType.ArrayLength)
        return "Length";

    var mem_expr = expr.Operand as Exprs.MemberExpression;

    return PropertyNameFromMemberExpr(mem_expr);
}

static string PropertyNameFromLambdaExpr(Exprs.LambdaExpression expr)
{
         if (expr.Body is Exprs.MemberExpression)   return PropertyNameFromMemberExpr(expr.Body as Exprs.MemberExpression);
    else if (expr.Body is Exprs.UnaryExpression)    return PropertyNameFromUnaryExpr(expr.Body as Exprs.UnaryExpression);

    throw new NotSupportedException();
}

public static string PropertyNameFromExpr<TProp>(Exprs.Expression<Func<TProp>> expr)
{
    Contract.Requires<ArgumentNullException>(expr != null);
    Contract.Requires<ArgumentException>(expr.Body is Exprs.MemberExpression || expr.Body is Exprs.UnaryExpression);

    return PropertyNameFromLambdaExpr(expr);
}

public static string PropertyNameFromExpr<T, TProp>(Exprs.Expression<Func<T, TProp>> expr)
{
    Contract.Requires<ArgumentNullException>(expr != null);
    Contract.Requires<ArgumentException>(expr.Body is Exprs.MemberExpression || expr.Body is Exprs.UnaryExpression);

    return PropertyNameFromLambdaExpr(expr);
}

现在看用法示例:

int[] someArray = new int[1];
Console.WriteLine(PropertyNameFromExpr( () => someArray.Length ));

如果PropertyNameFromUnaryExpr没有检查ArrayLength, "someArray"将被打印到控制台(编译器似乎生成了对支持Length字段的直接访问,作为优化,甚至在调试中,因此是特殊情况)。

其他回答

这可能是最优的

public static string GetPropertyName<TResult>(Expression<Func<TResult>> expr)
{
    var memberAccess = expr.Body as MemberExpression;
    var propertyInfo = memberAccess?.Member as PropertyInfo;
    var propertyName = propertyInfo?.Name;

    return propertyName;
}

使用c# 7模式匹配:

public static string GetMemberName<T>(this Expression<T> expression)
{
    switch (expression.Body)
    {
        case MemberExpression m:
            return m.Member.Name;
        case UnaryExpression u when u.Operand is MemberExpression m:
            return m.Member.Name;
        default:
            throw new NotImplementedException(expression.GetType().ToString());
    }
}

例子:

public static RouteValueDictionary GetInfo<T>(this HtmlHelper html, 
    Expression<Func<T, object>> action) where T : class
{
    var name = action.GetMemberName();
    return GetInfo(html, name);
}

[更新]c# 8模式匹配:

public static string GetMemberName<T>(this Expression<T> expression) => expression.Body switch
{
    MemberExpression m => m.Member.Name,
    UnaryExpression u when u.Operand is MemberExpression m => m.Member.Name,
    _ => throw new NotImplementedException(expression.GetType().ToString())
};

我在ObjectStateEntry上创建了一个扩展方法,以便能够以类型安全的方式标记(实体框架POCO类的)属性,因为默认方法只接受字符串。这是我从属性中获取名称的方式:

public static void SetModifiedProperty<T>(this System.Data.Objects.ObjectStateEntry state, Expression<Func<T>> action)
{
    var body = (MemberExpression)action.Body;
    string propertyName = body.Member.Name;

    state.SetModifiedProperty(propertyName);
}

我正在使用一个扩展方法的前c# 6项目和名称()的目标c# 6。

public static class MiscExtentions
{
    public static string NameOf<TModel, TProperty>(this object @object, Expression<Func<TModel, TProperty>> propertyExpression)
    {
        var expression = propertyExpression.Body as MemberExpression;
        if (expression == null)
        {
            throw new ArgumentException("Expression is not a property.");
        }

        return expression.Member.Name;
    }
}

我称之为:

public class MyClass 
{
    public int Property1 { get; set; }
    public string Property2 { get; set; }
    public int[] Property3 { get; set; }
    public Subclass Property4 { get; set; }
    public Subclass[] Property5 { get; set; }
}

public class Subclass
{
    public int PropertyA { get; set; }
    public string PropertyB { get; set; }
}

// result is Property1
this.NameOf((MyClass o) => o.Property1);
// result is Property2
this.NameOf((MyClass o) => o.Property2);
// result is Property3
this.NameOf((MyClass o) => o.Property3);
// result is Property4
this.NameOf((MyClass o) => o.Property4);
// result is PropertyB
this.NameOf((MyClass o) => o.Property4.PropertyB);
// result is Property5
this.NameOf((MyClass o) => o.Property5);

它可以很好地处理字段和属性。

从。net 4.0开始,你可以使用ExpressionVisitor来查找属性:

class ExprVisitor : ExpressionVisitor {
    public bool IsFound { get; private set; }
    public string MemberName { get; private set; }
    public Type MemberType { get; private set; }
    protected override Expression VisitMember(MemberExpression node) {
        if (!IsFound && node.Member.MemberType == MemberTypes.Property) {
            IsFound = true;
            MemberName = node.Member.Name;
            MemberType = node.Type;
        }
        return base.VisitMember(node);
    }
}

下面是如何使用这个访问者:

var visitor = new ExprVisitor();
visitor.Visit(expr);
if (visitor.IsFound) {
    Console.WriteLine("First property in the expression tree: Name={0}, Type={1}", visitor.MemberName, visitor.MemberType.FullName);
} else {
    Console.WriteLine("No properties found.");
}