我有一些HTML菜单,当用户单击这些菜单的头部时,我会完全显示这些菜单。当用户在菜单区域外单击时,我希望隐藏这些元素。

jQuery是否可以实现这样的功能?

$("#menuscontainer").clickOutsideThisElement(function() {
    // Hide the menus
});

当前回答

只是一个警告,使用这个:

$('html').click(function() {
  // Hide the menus if visible
});

$('#menucontainer').click(function(event){
  event.stopPropagation();
});

它阻止RubyonRails UJS驱动程序正常工作。例如,link_to“click”、“/url”、:method=>:delete将不起作用。

这可能是一种变通方法:

$('html').click(function() {
  // Hide the menus if visible
});

$('#menucontainer').click(function(event){
  if (!$(event.target).data('method')) {
    event.stopPropagation();
  }
});

其他回答

这是我的代码:

// Listen to every click
$('html').click(function(event) {
    if ( $('#mypopupmenu').is(':visible') ) {
        if (event.target.id != 'click_this_to_show_mypopupmenu') {
            $('#mypopupmenu').hide();
        }
    }
});

// Listen to selector's clicks
$('#click_this_to_show_mypopupmenu').click(function() {

  // If the menu is visible, and you clicked the selector again we need to hide
  if ( $('#mypopupmenu').is(':visible') {
      $('#mypopupmenu').hide();
      return true;
  }

  // Else we need to show the popup menu
  $('#mypopupmenu').show();
});

标准HTML:

用<标签>包围菜单并获取焦点状态更改。

http://jsfiddle.net/bK3gL/

另外:您可以通过Tab展开菜单。

解决方案1

不要使用event.stopPropagation(),因为它会产生一些副作用,只需定义一个简单的标志变量并添加一个if条件。我对此进行了测试,工作正常,没有任何stopPropagation的副作用:

var flag = "1";
$('#menucontainer').click(function(event){
    flag = "0"; // flag 0 means click happened in the area where we should not do any action
});

$('html').click(function() {
    if(flag != "0"){
        // Hide the menus if visible
    }
    else {
        flag = "1";
    }
});

解决方案2

只有一个简单的if条件:

$(document).on('click', function(event){
    var container = $("#menucontainer");
    if (!container.is(event.target) &&            // If the target of the click isn't the container...
        container.has(event.target).length === 0) // ... nor a descendant of the container
    {
        // Do whatever you want to do when click is outside the element
    }
});

外部点击插件!

用法:

$('.target-element').outsideClick(function(event){
    //code that fires when user clicks outside the element
    //event = the click event
    //$(this) = the '.target-element' that is firing this function 
}, '.excluded-element')

它的代码:

(function($) {

//when the user hits the escape key, it will trigger all outsideClick functions
$(document).on("keyup", function (e) {
    if (e.which == 27) $('body').click(); //escape key
});

//The actual plugin
$.fn.outsideClick = function(callback, exclusions) {
    var subject = this;

    //test if exclusions have been set
    var hasExclusions = typeof exclusions !== 'undefined';

    //switches click event with touch event if on a touch device
    var ClickOrTouchEvent = "ontouchend" in document ? "touchend" : "click";

    $('body').on(ClickOrTouchEvent, function(event) {
        //click target does not contain subject as a parent
        var clickedOutside = !$(event.target).closest(subject).length;

        //click target was on one of the excluded elements
        var clickedExclusion = $(event.target).closest(exclusions).length;

        var testSuccessful;

        if (hasExclusions) {
            testSuccessful = clickedOutside && !clickedExclusion;
        } else {
            testSuccessful = clickedOutside;
        }

        if(testSuccessful) {
            callback.call(subject, event);
        }
    });

    return this;
};

}(jQuery));

根据此答案改编https://stackoverflow.com/a/3028037/1611058

 <div class="feedbackCont" onblur="hidefeedback();">
        <div class="feedbackb" onclick="showfeedback();" ></div>
        <div class="feedbackhide" tabindex="1"> </div>
 </div>

function hidefeedback(){
    $j(".feedbackhide").hide();
}

function showfeedback(){
    $j(".feedbackhide").show();
    $j(".feedbackCont").attr("tabindex",1).focus();
}

这是我想出的最简单的解决方案。