我有一些HTML菜单，当用户单击这些菜单的头部时，我会完全显示这些菜单。当用户在菜单区域外单击时，我希望隐藏这些元素。
jQuery是否可以实现这样的功能？
$("#menuscontainer").clickOutsideThisElement(function() {
// Hide the menus
});
当前回答
外部点击插件！
用法：
$('.target-element').outsideClick(function(event){
//code that fires when user clicks outside the element
//event = the click event
//$(this) = the '.target-element' that is firing this function
}, '.excluded-element')
它的代码：
(function($) {
//when the user hits the escape key, it will trigger all outsideClick functions
$(document).on("keyup", function (e) {
if (e.which == 27) $('body').click(); //escape key
});
//The actual plugin
$.fn.outsideClick = function(callback, exclusions) {
var subject = this;
//test if exclusions have been set
var hasExclusions = typeof exclusions !== 'undefined';
//switches click event with touch event if on a touch device
var ClickOrTouchEvent = "ontouchend" in document ? "touchend" : "click";
$('body').on(ClickOrTouchEvent, function(event) {
//click target does not contain subject as a parent
var clickedOutside = !$(event.target).closest(subject).length;
//click target was on one of the excluded elements
var clickedExclusion = $(event.target).closest(exclusions).length;
var testSuccessful;
if (hasExclusions) {
testSuccessful = clickedOutside && !clickedExclusion;
} else {
testSuccessful = clickedOutside;
}
if(testSuccessful) {
callback.call(subject, event);
}
});
return this;
};
}(jQuery));
根据此答案改编https://stackoverflow.com/a/3028037/1611058
其他回答
如果有人好奇这里是javascript解决方案（es6）：
window.addEventListener('mouseup', e => {
if (e.target != yourDiv && e.target.parentNode != yourDiv) {
yourDiv.classList.remove('show-menu');
//or yourDiv.style.display = 'none';
}
})
和es5，以防万一：
window.addEventListener('mouseup', function (e) {
if (e.target != yourDiv && e.target.parentNode != yourDiv) {
yourDiv.classList.remove('show-menu');
//or yourDiv.style.display = 'none';
}
});
$（'html'）.click（function（）{//隐藏菜单（如果可见）});$（'#menucontainer'）.click（函数（事件）{event.stopPropagation（）；});<script src=“https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js“></script><html><button id=“#menucontainer”>确定</button></html>
假设您想要检测用户在外部或内部单击的div是否具有id，例如：“我的特殊小部件”。
收听身体点击事件：
document.body.addEventListener('click', (e) => {
if (isInsideMySpecialWidget(e.target, "my-special-widget")) {
console.log("user clicked INSIDE the widget");
}
console.log("user clicked OUTSIDE the widget");
});
function isInsideMySpecialWidget(elem, mySpecialWidgetId){
while (elem.parentElement) {
if (elem.id === mySpecialWidgetId) {
return true;
}
elem = elem.parentElement;
}
return false;
}
在这种情况下，您不会破坏页面中某些元素的正常点击流，因为您没有使用“stopPropagation”方法。
我很惊讶没有人真正承认这一事件：
var button=document.getElementById（'button'）；button.addEventListener（'click'，函数（e）{e.target.style.backgroundColor=“绿色”；});button.addEventListener（'焦点'，函数（e）{e.target.style.backgroundColor=''；});<!DOCTYPE html><html><head><meta charset=“utf-8”></head><body><button id=“button”>单击</button></body></html>
用纯JavaScript编写的方法
let menu = document.getElementById("menu");
document.addEventListener("click", function(){
// Hide the menus
menu.style.display = "none";
}, false);
document.getElementById("menuscontainer").addEventListener("click", function(e){
// Show the menus
menu.style.display = "block";
e.stopPropagation();
}, false);
