如何删除没有唯一行id存在的重复行?
我的座位是
col1 col2 col3 col4 col5 col6 col7
john 1 1 1 1 1 1
john 1 1 1 1 1 1
sally 2 2 2 2 2 2
sally 2 2 2 2 2 2
我想留下以下重复删除后:
john 1 1 1 1 1 1
sally 2 2 2 2 2 2
我尝试了一些查询，但我认为他们取决于有一个行id，因为我没有得到想要的结果。例如:
DELETE
FROM table
WHERE col1 IN (
SELECT id
FROM table
GROUP BY id
HAVING (COUNT(col1) > 1)
)
当前回答
DECLARE @TB TABLE(NAME VARCHAR(100));
INSERT INTO @TB VALUES ('Red'),('Red'),('Green'),('Blue'),('White'),('White')
--**Delete by Rank**
;WITH CTE AS(SELECT NAME,DENSE_RANK() OVER (PARTITION BY NAME ORDER BY NEWID()) ID FROM @TB)
DELETE FROM CTE WHERE ID>1
SELECT NAME FROM @TB;
--**Delete by Row Number**
;WITH CTE AS(SELECT NAME,ROW_NUMBER() OVER (PARTITION BY NAME ORDER BY NAME) ID FROM @TB)
DELETE FROM CTE WHERE ID>1;
SELECT NAME FROM @TB;
其他回答
试着使用:
SELECT linkorder
,Row_Number() OVER (
PARTITION BY linkorder ORDER BY linkorder DESC
) AS RowNum
FROM u_links
哦，哇，我觉得准备这些答案太愚蠢了，他们就像专家的答案，包括所有的CTE和临时表等。
为了让它工作，我所做的只是使用MAX聚合ID列。
DELETE FROM table WHERE col1 IN (
SELECT MAX(id) FROM table GROUP BY id HAVING ( COUNT(col1) > 1 )
)
注意:您可能需要多次运行它来删除重复，因为这一次只会删除一组重复的行。
DELETE from search
where id not in (
select min(id) from search
group by url
having count(*)=1
union
SELECT min(id) FROM search
group by url
having count(*) > 1
)
要在SQL Server中删除表中的重复行，请执行以下步骤:
使用GROUP BY子句或ROW_NUMBER()函数查找重复的行。 使用DELETE语句删除重复的行。
设置一个示例表
DROP TABLE IF EXISTS contacts;
CREATE TABLE contacts(
contact_id INT IDENTITY(1,1) PRIMARY KEY,
first_name NVARCHAR(100) NOT NULL,
last_name NVARCHAR(100) NOT NULL,
email NVARCHAR(255) NOT NULL,
);
插入的值
INSERT INTO contacts
(first_name,last_name,email)
VALUES
('Syed','Abbas','syed.abbas@example.com'),
('Catherine','Abel','catherine.abel@example.com'),
('Kim','Abercrombie','kim.abercrombie@example.com'),
('Kim','Abercrombie','kim.abercrombie@example.com'),
('Kim','Abercrombie','kim.abercrombie@example.com'),
('Hazem','Abolrous','hazem.abolrous@example.com'),
('Hazem','Abolrous','hazem.abolrous@example.com'),
('Humberto','Acevedo','humberto.acevedo@example.com'),
('Humberto','Acevedo','humberto.acevedo@example.com'),
('Pilar','Ackerman','pilar.ackerman@example.com');
查询
SELECT
contact_id,
first_name,
last_name,
email
FROM
contacts;
从表中删除重复的行
WITH cte AS (
SELECT
contact_id,
first_name,
last_name,
email,
ROW_NUMBER() OVER (
PARTITION BY
first_name,
last_name,
email
ORDER BY
first_name,
last_name,
email
) row_num
FROM
contacts
)
DELETE FROM cte
WHERE row_num > 1;
现在要删除记录吗
另一种在不丢失信息的情况下删除重复行的方法如下:
delete from dublicated_table t1 (nolock)
join (
select t2.dublicated_field
, min(len(t2.field_kept)) as min_field_kept
from dublicated_table t2 (nolock)
group by t2.dublicated_field having COUNT(*)>1
) t3
on t1.dublicated_field=t3.dublicated_field
and len(t1.field_kept)=t3.min_field_kept
