是否有可能找到给定包中的所有类或接口?(快速看了一下e.g. Package,似乎没有。)


当前回答

如果您不使用任何动态类加载器,您可以搜索类路径,并为每个条目搜索目录或JAR文件。

其他回答

如果您只是想加载一组相关的类,那么Spring可以帮助您。

Spring可以在一行代码中实例化实现给定接口的所有类的列表或映射。列表或映射将包含实现该接口的所有类的实例。

也就是说,作为从文件系统中加载类列表的替代方法,只需在您想要加载的所有类中实现相同的接口,而不管包是什么,并使用Spring为您提供所有这些类的实例。这样,您就可以加载(并实例化)您想要的所有类,而不管它们在哪个包中。

另一方面,如果您希望将它们都放在一个包中,那么只需让包中的所有类实现给定的接口。

注意,接口本身不需要声明任何方法——它可以完全为空。

要注入实现给定接口的类列表,请使用以下代码行…

  @Autowired
  private List<ISomeInterface> implementationList;

也可以使用Spring注入类的Map。如果有兴趣,请阅读文档。

最后,我将提供一个比搜索整个文件系统树更优雅的解决方案。

创建一个自定义注释,用于构建应用于它的类的目录——类似于@ClassCatalog。

目前列出给定包中所有类的最健壮的机制是ClassGraph,因为它处理尽可能广泛的类路径规范机制,包括新的JPMS模块系统。(我是作者。)

List<String> classNames = new ArrayList<>();
try (ScanResult scanResult = new ClassGraph().acceptPackages("my.package")
        .enableClassInfo().scan()) {
    classNames.addAll(scanResult.getAllClasses().getNames());
}

春天

这个例子是针对Spring 4的,但是您也可以在早期版本中找到类路径扫描器。

// create scanner and disable default filters (that is the 'false' argument)
final ClassPathScanningCandidateComponentProvider provider = new ClassPathScanningCandidateComponentProvider(false);
// add include filters which matches all the classes (or use your own)
provider.addIncludeFilter(new RegexPatternTypeFilter(Pattern.compile(".*")));

// get matching classes defined in the package
final Set<BeanDefinition> classes = provider.findCandidateComponents("my.package.name");

// this is how you can load the class type from BeanDefinition instance
for (BeanDefinition bean: classes) {
    Class<?> clazz = Class.forName(bean.getBeanClassName());
    // ... do your magic with the class ...
}

谷歌番石榴

注意:在版本14中,API仍然被标记为@Beta,所以在生产代码中要小心。

final ClassLoader loader = Thread.currentThread().getContextClassLoader();

for (final ClassPath.ClassInfo info : ClassPath.from(loader).getTopLevelClasses()) {
  if (info.getName().startsWith("my.package.")) {
    final Class<?> clazz = info.load();
    // do something with your clazz
  }
}

不使用任何额外的库:

package test;

import java.io.DataInputStream;
import java.io.InputStream;
import java.net.URL;
import java.util.ArrayList;
import java.util.List;

public class Test {
    public static void main(String[] args) throws Exception{
        List<Class> classes = getClasses(Test.class.getClassLoader(),"test");
        for(Class c:classes){
            System.out.println("Class: "+c);
        }
    }

    public static List<Class> getClasses(ClassLoader cl,String pack) throws Exception{

        String dottedPackage = pack.replaceAll("[/]", ".");
        List<Class> classes = new ArrayList<Class>();
        URL upackage = cl.getResource(pack);

        DataInputStream dis = new DataInputStream((InputStream) upackage.getContent());
        String line = null;
        while ((line = dis.readLine()) != null) {
            if(line.endsWith(".class")) {
               classes.add(Class.forName(dottedPackage+"."+line.substring(0,line.lastIndexOf('.'))));
            }
        }
        return classes;
    }
}

我整理了一个简单的github项目来解决这个问题:

https://github.com/ddopson/java-class-enumerator

它既适用于基于文件的类路径,也适用于jar文件。

如果你在签出项目后运行'make',它将打印出以下内容:

 Cleaning...
rm -rf build/
 Building...
javac -d build/classes src/pro/ddopson/ClassEnumerator.java src/test/ClassIShouldFindOne.java src/test/ClassIShouldFindTwo.java src/test/subpkg/ClassIShouldFindThree.java src/test/TestClassEnumeration.java
 Making JAR Files...
jar cf build/ClassEnumerator_test.jar -C build/classes/ . 
jar cf build/ClassEnumerator.jar -C build/classes/ pro
 Running Filesystem Classpath Test...
java -classpath build/classes test.TestClassEnumeration
ClassDiscovery: Package: 'test' becomes Resource: 'file:/Users/Dopson/work/other/java-class-enumeration/build/classes/test'
ClassDiscovery: Reading Directory '/Users/Dopson/work/other/java-class-enumeration/build/classes/test'
ClassDiscovery: FileName 'ClassIShouldFindOne.class'  =>  class 'test.ClassIShouldFindOne'
ClassDiscovery: FileName 'ClassIShouldFindTwo.class'  =>  class 'test.ClassIShouldFindTwo'
ClassDiscovery: FileName 'subpkg'  =>  class 'null'
ClassDiscovery: Reading Directory '/Users/Dopson/work/other/java-class-enumeration/build/classes/test/subpkg'
ClassDiscovery: FileName 'ClassIShouldFindThree.class'  =>  class 'test.subpkg.ClassIShouldFindThree'
ClassDiscovery: FileName 'TestClassEnumeration.class'  =>  class 'test.TestClassEnumeration'
 Running JAR Classpath Test...
java -classpath build/ClassEnumerator_test.jar  test.TestClassEnumeration
ClassDiscovery: Package: 'test' becomes Resource: 'jar:file:/Users/Dopson/work/other/java-class-enumeration/build/ClassEnumerator_test.jar!/test'
ClassDiscovery: Reading JAR file: '/Users/Dopson/work/other/java-class-enumeration/build/ClassEnumerator_test.jar'
ClassDiscovery: JarEntry 'META-INF/'  =>  class 'null'
ClassDiscovery: JarEntry 'META-INF/MANIFEST.MF'  =>  class 'null'
ClassDiscovery: JarEntry 'pro/'  =>  class 'null'
ClassDiscovery: JarEntry 'pro/ddopson/'  =>  class 'null'
ClassDiscovery: JarEntry 'pro/ddopson/ClassEnumerator.class'  =>  class 'null'
ClassDiscovery: JarEntry 'test/'  =>  class 'null'
ClassDiscovery: JarEntry 'test/ClassIShouldFindOne.class'  =>  class 'test.ClassIShouldFindOne'
ClassDiscovery: JarEntry 'test/ClassIShouldFindTwo.class'  =>  class 'test.ClassIShouldFindTwo'
ClassDiscovery: JarEntry 'test/subpkg/'  =>  class 'null'
ClassDiscovery: JarEntry 'test/subpkg/ClassIShouldFindThree.class'  =>  class 'test.subpkg.ClassIShouldFindThree'
ClassDiscovery: JarEntry 'test/TestClassEnumeration.class'  =>  class 'test.TestClassEnumeration'
 Tests Passed. 

另见我的另一个答案