是否有可能找到给定包中的所有类或接口?(快速看了一下e.g. Package,似乎没有。)
当前回答
你需要查找类路径中的每个类装入器条目:
String pkg = "org/apache/commons/lang";
ClassLoader cl = ClassLoader.getSystemClassLoader();
URL[] urls = ((URLClassLoader) cl).getURLs();
for (URL url : urls) {
System.out.println(url.getFile());
File jar = new File(url.getFile());
// ....
}
如果条目是目录,只需在右边的子目录中查找:
if (jar.isDirectory()) {
File subdir = new File(jar, pkg);
if (!subdir.exists())
continue;
File[] files = subdir.listFiles();
for (File file : files) {
if (!file.isFile())
continue;
if (file.getName().endsWith(".class"))
System.out.println("Found class: "
+ file.getName().substring(0,
file.getName().length() - 6));
}
}
如果条目是文件,并且它是jar,检查它的ZIP条目:
else {
// try to open as ZIP
try {
ZipFile zip = new ZipFile(jar);
for (Enumeration<? extends ZipEntry> entries = zip
.entries(); entries.hasMoreElements();) {
ZipEntry entry = entries.nextElement();
String name = entry.getName();
if (!name.startsWith(pkg))
continue;
name = name.substring(pkg.length() + 1);
if (name.indexOf('/') < 0 && name.endsWith(".class"))
System.out.println("Found class: "
+ name.substring(0, name.length() - 6));
}
} catch (ZipException e) {
System.out.println("Not a ZIP: " + e.getMessage());
} catch (IOException e) {
System.err.println(e.getMessage());
}
}
现在,一旦包中有了所有的类名,就可以尝试用反射加载它们,并分析它们是类还是接口等等。
其他回答
我整理了一个简单的github项目来解决这个问题:
https://github.com/ddopson/java-class-enumerator
它既适用于基于文件的类路径,也适用于jar文件。
如果你在签出项目后运行'make',它将打印出以下内容:
Cleaning...
rm -rf build/
Building...
javac -d build/classes src/pro/ddopson/ClassEnumerator.java src/test/ClassIShouldFindOne.java src/test/ClassIShouldFindTwo.java src/test/subpkg/ClassIShouldFindThree.java src/test/TestClassEnumeration.java
Making JAR Files...
jar cf build/ClassEnumerator_test.jar -C build/classes/ .
jar cf build/ClassEnumerator.jar -C build/classes/ pro
Running Filesystem Classpath Test...
java -classpath build/classes test.TestClassEnumeration
ClassDiscovery: Package: 'test' becomes Resource: 'file:/Users/Dopson/work/other/java-class-enumeration/build/classes/test'
ClassDiscovery: Reading Directory '/Users/Dopson/work/other/java-class-enumeration/build/classes/test'
ClassDiscovery: FileName 'ClassIShouldFindOne.class' => class 'test.ClassIShouldFindOne'
ClassDiscovery: FileName 'ClassIShouldFindTwo.class' => class 'test.ClassIShouldFindTwo'
ClassDiscovery: FileName 'subpkg' => class 'null'
ClassDiscovery: Reading Directory '/Users/Dopson/work/other/java-class-enumeration/build/classes/test/subpkg'
ClassDiscovery: FileName 'ClassIShouldFindThree.class' => class 'test.subpkg.ClassIShouldFindThree'
ClassDiscovery: FileName 'TestClassEnumeration.class' => class 'test.TestClassEnumeration'
Running JAR Classpath Test...
java -classpath build/ClassEnumerator_test.jar test.TestClassEnumeration
ClassDiscovery: Package: 'test' becomes Resource: 'jar:file:/Users/Dopson/work/other/java-class-enumeration/build/ClassEnumerator_test.jar!/test'
ClassDiscovery: Reading JAR file: '/Users/Dopson/work/other/java-class-enumeration/build/ClassEnumerator_test.jar'
ClassDiscovery: JarEntry 'META-INF/' => class 'null'
ClassDiscovery: JarEntry 'META-INF/MANIFEST.MF' => class 'null'
ClassDiscovery: JarEntry 'pro/' => class 'null'
ClassDiscovery: JarEntry 'pro/ddopson/' => class 'null'
ClassDiscovery: JarEntry 'pro/ddopson/ClassEnumerator.class' => class 'null'
ClassDiscovery: JarEntry 'test/' => class 'null'
ClassDiscovery: JarEntry 'test/ClassIShouldFindOne.class' => class 'test.ClassIShouldFindOne'
ClassDiscovery: JarEntry 'test/ClassIShouldFindTwo.class' => class 'test.ClassIShouldFindTwo'
ClassDiscovery: JarEntry 'test/subpkg/' => class 'null'
ClassDiscovery: JarEntry 'test/subpkg/ClassIShouldFindThree.class' => class 'test.subpkg.ClassIShouldFindThree'
ClassDiscovery: JarEntry 'test/TestClassEnumeration.class' => class 'test.TestClassEnumeration'
Tests Passed.
另见我的另一个答案
在使用Maven时,Aleksander Blomskøld的解决方案对我的参数化测试@RunWith(parameterized .class)不起作用。正确命名了测试,并显示了找到但未执行的位置:
-------------------------------------------------------
T E S T S
-------------------------------------------------------
Running some.properly.named.test.run.with.maven.SomeTest
Tests run: 0, Failures: 0, Errors: 0, Skipped: 0, Time elapsed: 0.123 sec
这里也报道了类似的问题。
在我的例子中,@Parameters是在包中创建每个类的实例。这些测试在IDE中本地运行时运行良好。然而,当运行Maven时,在Aleksander Blomskøld的解决方案中没有找到类。
我确实用以下剪辑完成了它,灵感来自David Pärsson对Aleksander Blomskøld回答的评论:
Reflections reflections = new Reflections(new ConfigurationBuilder()
.setScanners(new SubTypesScanner(false /* don't exclude Object.class */), new ResourcesScanner())
.addUrls(ClasspathHelper.forJavaClassPath())
.filterInputsBy(new FilterBuilder()
.include(FilterBuilder.prefix(basePackage))));
Set<Class<?>> subTypesOf = reflections.getSubTypesOf(Object.class);
谷歌Guava 14包含了一个新类ClassPath,它有三个方法来扫描顶级类:
getTopLevelClasses () getTopLevelClasses(管柱packageName) getTopLevelClassesRecursive(管柱packageName)
有关更多信息,请参阅ClassPath javadocs。
这是不可能的,因为包中的所有类都可能不会被加载,而你总是知道一个类的包。
如果您不使用任何动态类加载器,您可以搜索类路径,并为每个条目搜索目录或JAR文件。
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