是否有可能找到给定包中的所有类或接口?(快速看了一下e.g. Package,似乎没有。)
当前回答
目前列出给定包中所有类的最健壮的机制是ClassGraph,因为它处理尽可能广泛的类路径规范机制,包括新的JPMS模块系统。(我是作者。)
List<String> classNames = new ArrayList<>();
try (ScanResult scanResult = new ClassGraph().acceptPackages("my.package")
.enableClassInfo().scan()) {
classNames.addAll(scanResult.getAllClasses().getNames());
}
其他回答
我无法为如此简单的东西找到一个简短的工作片段。所以在这里,我自己做了一段时间后:
Reflections reflections =
new Reflections(new ConfigurationBuilder()
.filterInputsBy(new FilterBuilder().includePackage(packagePath))
.setUrls(ClasspathHelper.forPackage(packagePath))
.setScanners(new SubTypesScanner(false)));
Set<String> typeList = reflections.getAllTypes();
它使用组织反射。
FindAllClassesUsingPlainJavaReflectionTest.java
@Slf4j
class FindAllClassesUsingPlainJavaReflectionTest {
private static final Function<Throwable, RuntimeException> asRuntimeException = throwable -> {
log.error(throwable.getLocalizedMessage());
return new RuntimeException(throwable);
};
private static final Function<String, Collection<Class<?>>> findAllPackageClasses = basePackageName -> {
Locale locale = Locale.getDefault();
Charset charset = StandardCharsets.UTF_8;
val fileManager = ToolProvider.getSystemJavaCompiler()
.getStandardFileManager(/* diagnosticListener */ null, locale, charset);
StandardLocation location = StandardLocation.CLASS_PATH;
JavaFileObject.Kind kind = JavaFileObject.Kind.CLASS;
Set<JavaFileObject.Kind> kinds = Collections.singleton(kind);
val javaFileObjects = Try.of(() -> fileManager.list(location, basePackageName, kinds, /* recurse */ true))
.getOrElseThrow(asRuntimeException);
String pathToPackageAndClass = basePackageName.replace(".", File.separator);
Function<String, String> mapToClassName = s -> {
String prefix = Arrays.stream(s.split(pathToPackageAndClass))
.findFirst()
.orElse("");
return s.replaceFirst(prefix, "")
.replaceAll(File.separator, ".");
};
return StreamSupport.stream(javaFileObjects.spliterator(), /* parallel */ true)
.filter(javaFileObject -> javaFileObject.getKind().equals(kind))
.map(FileObject::getName)
.map(fileObjectName -> fileObjectName.replace(".class", ""))
.map(mapToClassName)
.map(className -> Try.of(() -> Class.forName(className))
.getOrElseThrow(asRuntimeException))
.collect(Collectors.toList());
};
@Test
@DisplayName("should get classes recursively in given package")
void test() {
Collection<Class<?>> classes = findAllPackageClasses.apply(getClass().getPackage().getName());
assertThat(classes).hasSizeGreaterThan(4);
classes.stream().map(String::valueOf).forEach(log::info);
}
}
PS:为了简化处理错误的样板文件等,我在这里使用了vavr和lombok库
其他实现可以在我的GitHub daggerok/java-reflection-find- annotation -classes-or-methods repo中找到
几乎所有的答案要么使用reflection,要么从文件系统读取类文件。如果尝试从文件系统读取类,则在将应用程序打包为JAR或其他格式时可能会出错。此外,您可能不想为此目的使用单独的库。
这里有另一种方法,它是纯java,不依赖于文件系统。
import javax.tools.JavaFileObject;
import javax.tools.StandardJavaFileManager;
import javax.tools.StandardLocation;
import javax.tools.ToolProvider;
import java.io.File;
import java.util.ArrayList;
import java.util.Collection;
import java.util.Collections;
import java.util.regex.Pattern;
import java.util.stream.Collectors;
import java.util.stream.StreamSupport;
public class PackageUtil {
public static Collection<Class> getClasses(final String pack) throws Exception {
final StandardJavaFileManager fileManager = ToolProvider.getSystemJavaCompiler().getStandardFileManager(null, null, null);
return StreamSupport.stream(fileManager.list(StandardLocation.CLASS_PATH, pack, Collections.singleton(JavaFileObject.Kind.CLASS), false).spliterator(), false)
.map(javaFileObject -> {
try {
final String[] split = javaFileObject.getName()
.replace(".class", "")
.replace(")", "")
.split(Pattern.quote(File.separator));
final String fullClassName = pack + "." + split[split.length - 1];
return Class.forName(fullClassName);
} catch (ClassNotFoundException e) {
throw new RuntimeException(e);
}
})
.collect(Collectors.toCollection(ArrayList::new));
}
}
Java 8不是必须的。你可以使用for循环代替流。 你可以这样测试
public static void main(String[] args) throws Exception {
final String pack = "java.nio.file"; // Or any other package
PackageUtil.getClasses(pack).stream().forEach(System.out::println);
}
春天
这个例子是针对Spring 4的,但是您也可以在早期版本中找到类路径扫描器。
// create scanner and disable default filters (that is the 'false' argument)
final ClassPathScanningCandidateComponentProvider provider = new ClassPathScanningCandidateComponentProvider(false);
// add include filters which matches all the classes (or use your own)
provider.addIncludeFilter(new RegexPatternTypeFilter(Pattern.compile(".*")));
// get matching classes defined in the package
final Set<BeanDefinition> classes = provider.findCandidateComponents("my.package.name");
// this is how you can load the class type from BeanDefinition instance
for (BeanDefinition bean: classes) {
Class<?> clazz = Class.forName(bean.getBeanClassName());
// ... do your magic with the class ...
}
谷歌番石榴
注意:在版本14中,API仍然被标记为@Beta,所以在生产代码中要小心。
final ClassLoader loader = Thread.currentThread().getContextClassLoader();
for (final ClassPath.ClassInfo info : ClassPath.from(loader).getTopLevelClasses()) {
if (info.getName().startsWith("my.package.")) {
final Class<?> clazz = info.load();
// do something with your clazz
}
}
你可以使用这个使用ClassLoader的method1。
/**
* Scans all classes accessible from the context class loader which belong to the given package and subpackages.
*
* @param packageName The base package
* @return The classes
* @throws ClassNotFoundException
* @throws IOException
*/
private static Class[] getClasses(String packageName)
throws ClassNotFoundException, IOException {
ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
assert classLoader != null;
String path = packageName.replace('.', '/');
Enumeration<URL> resources = classLoader.getResources(path);
List<File> dirs = new ArrayList<File>();
while (resources.hasMoreElements()) {
URL resource = resources.nextElement();
dirs.add(new File(resource.getFile()));
}
ArrayList<Class> classes = new ArrayList<Class>();
for (File directory : dirs) {
classes.addAll(findClasses(directory, packageName));
}
return classes.toArray(new Class[classes.size()]);
}
/**
* Recursive method used to find all classes in a given directory and subdirs.
*
* @param directory The base directory
* @param packageName The package name for classes found inside the base directory
* @return The classes
* @throws ClassNotFoundException
*/
private static List<Class> findClasses(File directory, String packageName) throws ClassNotFoundException {
List<Class> classes = new ArrayList<Class>();
if (!directory.exists()) {
return classes;
}
File[] files = directory.listFiles();
for (File file : files) {
if (file.isDirectory()) {
assert !file.getName().contains(".");
classes.addAll(findClasses(file, packageName + "." + file.getName()));
} else if (file.getName().endsWith(".class")) {
classes.add(Class.forName(packageName + '.' + file.getName().substring(0, file.getName().length() - 6)));
}
}
return classes;
}
__________ 1 .该方法最初取自http://snippets.dzone.com/posts/show/4831,由互联网档案馆存档,如现在所示。该代码片段也可以在https://dzone.com/articles/get-all-classes-within-package上获得。
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