是否有可能找到给定包中的所有类或接口?(快速看了一下e.g. Package,似乎没有。)


当前回答

你可以使用这个使用ClassLoader的method1。

/**
 * Scans all classes accessible from the context class loader which belong to the given package and subpackages.
 *
 * @param packageName The base package
 * @return The classes
 * @throws ClassNotFoundException
 * @throws IOException
 */
private static Class[] getClasses(String packageName)
        throws ClassNotFoundException, IOException {
    ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
    assert classLoader != null;
    String path = packageName.replace('.', '/');
    Enumeration<URL> resources = classLoader.getResources(path);
    List<File> dirs = new ArrayList<File>();
    while (resources.hasMoreElements()) {
        URL resource = resources.nextElement();
        dirs.add(new File(resource.getFile()));
    }
    ArrayList<Class> classes = new ArrayList<Class>();
    for (File directory : dirs) {
        classes.addAll(findClasses(directory, packageName));
    }
    return classes.toArray(new Class[classes.size()]);
}

/**
 * Recursive method used to find all classes in a given directory and subdirs.
 *
 * @param directory   The base directory
 * @param packageName The package name for classes found inside the base directory
 * @return The classes
 * @throws ClassNotFoundException
 */
private static List<Class> findClasses(File directory, String packageName) throws ClassNotFoundException {
    List<Class> classes = new ArrayList<Class>();
    if (!directory.exists()) {
        return classes;
    }
    File[] files = directory.listFiles();
    for (File file : files) {
        if (file.isDirectory()) {
            assert !file.getName().contains(".");
            classes.addAll(findClasses(file, packageName + "." + file.getName()));
        } else if (file.getName().endsWith(".class")) {
            classes.add(Class.forName(packageName + '.' + file.getName().substring(0, file.getName().length() - 6)));
        }
    }
    return classes;
}

__________ 1 .该方法最初取自http://snippets.dzone.com/posts/show/4831,由互联网档案馆存档,如现在所示。该代码片段也可以在https://dzone.com/articles/get-all-classes-within-package上获得。

其他回答

这是不可能的,因为包中的所有类都可能不会被加载,而你总是知道一个类的包。

如果你在Spring-land,你可以使用PathMatchingResourcePatternResolver;

  PathMatchingResourcePatternResolver resolver = new PathMatchingResourcePatternResolver();
  Resource[] resources = resolver.getResources("classpath*:some/package/name/*.class");

    Arrays.asList(resources).forEach(r->{
        ...
    });

值得一提的

如果你想要一个包下所有类的列表,你可以用下面的方式使用Reflection:

List<Class> myTypes = new ArrayList<>();

Reflections reflections = new Reflections("com.package");
for (String s : reflections.getStore().get(SubTypesScanner.class).values()) {
    myTypes.add(Class.forName(s));
}

这将创建一个类列表,稍后您可以随心所欲地使用它们。

你需要查找类路径中的每个类装入器条目:

    String pkg = "org/apache/commons/lang";
    ClassLoader cl = ClassLoader.getSystemClassLoader();
    URL[] urls = ((URLClassLoader) cl).getURLs();
    for (URL url : urls) {
        System.out.println(url.getFile());
        File jar = new File(url.getFile());
        // ....
    }   

如果条目是目录,只需在右边的子目录中查找:

if (jar.isDirectory()) {
    File subdir = new File(jar, pkg);
    if (!subdir.exists())
        continue;
    File[] files = subdir.listFiles();
    for (File file : files) {
        if (!file.isFile())
            continue;
        if (file.getName().endsWith(".class"))
            System.out.println("Found class: "
                    + file.getName().substring(0,
                            file.getName().length() - 6));
    }
}   

如果条目是文件,并且它是jar,检查它的ZIP条目:

else {
    // try to open as ZIP
    try {
        ZipFile zip = new ZipFile(jar);
        for (Enumeration<? extends ZipEntry> entries = zip
                .entries(); entries.hasMoreElements();) {
            ZipEntry entry = entries.nextElement();
            String name = entry.getName();
            if (!name.startsWith(pkg))
                continue;
            name = name.substring(pkg.length() + 1);
            if (name.indexOf('/') < 0 && name.endsWith(".class"))
                System.out.println("Found class: "
                        + name.substring(0, name.length() - 6));
        }
    } catch (ZipException e) {
        System.out.println("Not a ZIP: " + e.getMessage());
    } catch (IOException e) {
        System.err.println(e.getMessage());
    }
}

现在,一旦包中有了所有的类名,就可以尝试用反射加载它们,并分析它们是类还是接口等等。

不使用任何额外的库:

package test;

import java.io.DataInputStream;
import java.io.InputStream;
import java.net.URL;
import java.util.ArrayList;
import java.util.List;

public class Test {
    public static void main(String[] args) throws Exception{
        List<Class> classes = getClasses(Test.class.getClassLoader(),"test");
        for(Class c:classes){
            System.out.println("Class: "+c);
        }
    }

    public static List<Class> getClasses(ClassLoader cl,String pack) throws Exception{

        String dottedPackage = pack.replaceAll("[/]", ".");
        List<Class> classes = new ArrayList<Class>();
        URL upackage = cl.getResource(pack);

        DataInputStream dis = new DataInputStream((InputStream) upackage.getContent());
        String line = null;
        while ((line = dis.readLine()) != null) {
            if(line.endsWith(".class")) {
               classes.add(Class.forName(dottedPackage+"."+line.substring(0,line.lastIndexOf('.'))));
            }
        }
        return classes;
    }
}