在MySQL中有一个很好的方法来复制SQL Server函数ROW_NUMBER()?
例如:
SELECT
col1, col2,
ROW_NUMBER() OVER (PARTITION BY col1, col2 ORDER BY col3 DESC) AS intRow
FROM Table1
然后,例如,我可以添加一个条件,将intRow限制为1,以获得每个(col1, col2)对的col3最高的单行。
在MySQL中有一个很好的方法来复制SQL Server函数ROW_NUMBER()?
例如:
SELECT
col1, col2,
ROW_NUMBER() OVER (PARTITION BY col1, col2 ORDER BY col3 DESC) AS intRow
FROM Table1
然后,例如,我可以添加一个条件,将intRow限制为1,以获得每个(col1, col2)对的col3最高的单行。
当前回答
我会定义一个函数:
delimiter $$
DROP FUNCTION IF EXISTS `getFakeId`$$
CREATE FUNCTION `getFakeId`() RETURNS int(11)
DETERMINISTIC
begin
return if(@fakeId, @fakeId:=@fakeId+1, @fakeId:=1);
end$$
那么我就可以:
select getFakeId() as id, t.* from table t, (select @fakeId:=0) as t2;
现在你没有子查询,视图中没有子查询。
其他回答
我没有看到任何简单的答案涵盖“PARTITION BY”部分,所以我的答案是:
SELECT
*
FROM (
select
CASE WHEN @partitionBy_1 = l THEN @row_number:=@row_number+1 ELSE @row_number:=1 END AS i
, @partitionBy_1:=l AS p
, t.*
from (
select @row_number:=0,@partitionBy_1:=null
) as x
cross join (
select 1 as n, 'a' as l
union all
select 1 as n, 'b' as l
union all
select 2 as n, 'b' as l
union all
select 2 as n, 'a' as l
union all
select 3 as n, 'a' as l
union all
select 3 as n, 'b' as l
) as t
ORDER BY l, n
) AS X
where i > 1
The ORDER BY clause must reflect your ROW_NUMBER need. Thus there's already a clear limitation: you can't have several ROW_NUMBER "emulation" of this form at the same time. The order of the "computed column" matters. If you have mysql compute those column in another order, it might not work. In this simple example I only put one but you can have several "PARTITION BY" parts CASE WHEN @partitionBy_1 = part1 AND @partitionBy_2 = part2 [...] THEN @row_number:=@row_number+1 ELSE @row_number:=1 END AS i , @partitionBy_1:=part1 AS P1 , @partitionBy_2:=part2 AS P2 [...] FROM ( SELECT @row_number:=0,@partitionBy_1:=null,@partitionBy_2:=null[...] ) as x
有点晚了,但也可能对那些寻找答案的人有帮助……
Between rows/row_number示例-可以在任何SQL中使用的递归查询:
WITH data(row_num, some_val) AS
(
SELECT 1 row_num, 1 some_val FROM any_table --dual in Oracle
UNION ALL
SELECT row_num+1, some_val+row_num FROM data WHERE row_num < 20 -- any number
)
SELECT * FROM data
WHERE row_num BETWEEN 5 AND 10
/
ROW_NUM SOME_VAL
-------------------
5 11
6 16
7 22
8 29
9 37
10 46
当我们有一个以上的列时,这个工作完美地为我创建RowNumber。这里是两列。
SELECT @row_num := IF(@prev_value= concat(`Fk_Business_Unit_Code`,`NetIQ_Job_Code`), @row_num+1, 1) AS RowNumber,
`Fk_Business_Unit_Code`,
`NetIQ_Job_Code`,
`Supervisor_Name`,
@prev_value := concat(`Fk_Business_Unit_Code`,`NetIQ_Job_Code`)
FROM (SELECT DISTINCT `Fk_Business_Unit_Code`,`NetIQ_Job_Code`,`Supervisor_Name`
FROM Employee
ORDER BY `Fk_Business_Unit_Code`, `NetIQ_Job_Code`, `Supervisor_Name` DESC) z,
(SELECT @row_num := 1) x,
(SELECT @prev_value := '') y
ORDER BY `Fk_Business_Unit_Code`, `NetIQ_Job_Code`,`Supervisor_Name` DESC
MariaDB 10.2实现了“窗口函数”,包括RANK(), ROW_NUMBER()和其他一些东西:
https://mariadb.com/kb/en/mariadb/window-functions/
根据本月在Percona Live上的一次演讲,它们得到了合理的优化。
语法与问题中的代码相同。
我会定义一个函数:
delimiter $$
DROP FUNCTION IF EXISTS `getFakeId`$$
CREATE FUNCTION `getFakeId`() RETURNS int(11)
DETERMINISTIC
begin
return if(@fakeId, @fakeId:=@fakeId+1, @fakeId:=1);
end$$
那么我就可以:
select getFakeId() as id, t.* from table t, (select @fakeId:=0) as t2;
现在你没有子查询,视图中没有子查询。