这允许在MySQL中实现ROW_NUMBER()和PARTITION BY提供的相同功能

SELECT  @row_num := IF(@prev_value=GENDER,@row_num+1,1) AS RowNumber
       FirstName, 
       Age,
       Gender,
       @prev_value := GENDER
  FROM Person,
      (SELECT @row_num := 1) x,
      (SELECT @prev_value := '') y
  ORDER BY Gender, Age DESC

我也会投票给Mosty Mostacho的解决方案，对他的查询代码进行了轻微的修改:

SELECT a.i, a.j, (
    SELECT count(*) from test b where a.j >= b.j AND a.i = b.i
) AS row_number FROM test a

会得到相同的结果:

+------+------+------------+
|    i |    j | row_number |
+------+------+------------+
|    1 |   11 |          1 |
|    1 |   12 |          2 |
|    1 |   13 |          3 |
|    2 |   21 |          1 |
|    2 |   22 |          2 |
|    2 |   23 |          3 |
|    3 |   31 |          1 |
|    3 |   32 |          2 |
|    3 |   33 |          3 |
|    4 |   14 |          1 |
+------+------+------------+

对于表格:

+------+------+
|    i |    j |
+------+------+
|    1 |   11 |
|    1 |   12 |
|    1 |   13 |
|    2 |   21 |
|    2 |   22 |
|    2 |   23 |
|    3 |   31 |
|    3 |   32 |
|    3 |   33 |
|    4 |   14 |
+------+------+

唯一的区别是查询不使用JOIN和GROUP BY，而是依赖于嵌套选择。

SELECT 
    @i:=@i+1 AS iterator, 
    t.*
FROM 
    tablename AS t,
    (SELECT @i:=0) AS foo

我认为你可以在这里使用DENSE_RANK()函数。 例子:

select `score`, DENSE_RANK() OVER( ORDER BY score desc ) as `rank` from Scores;

https://www.mysqltutorial.org/mysql-window-functions/mysql-dense_rank-function/

这允许在MySQL中实现ROW_NUMBER()和PARTITION BY提供的相同功能

SELECT  @row_num := IF(@prev_value=GENDER,@row_num+1,1) AS RowNumber
       FirstName, 
       Age,
       Gender,
       @prev_value := GENDER
  FROM Person,
      (SELECT @row_num := 1) x,
      (SELECT @prev_value := '') y
  ORDER BY Gender, Age DESC

对于另一个列的划分，一种方法是由@abcdn描述的。但是，它的性能很低。我建议使用这段代码，它不需要连接表本身: 考虑同一张桌子。

你可以得到这样的分区:

set @row_num := 0;
set @j:= 0;

select IF(j= @j, @row_num := @row_num + 1, @row_num := 1) as row_num,
       i, @j:= j as j
from tbl fh
order by j, i;

结果是这样的:

这样做的好处是我们不需要连接表本身