在MySQL中有一个很好的方法来复制SQL Server函数ROW_NUMBER()?
例如:
SELECT
col1, col2,
ROW_NUMBER() OVER (PARTITION BY col1, col2 ORDER BY col3 DESC) AS intRow
FROM Table1
然后,例如,我可以添加一个条件,将intRow限制为1,以获得每个(col1, col2)对的col3最高的单行。
在MySQL中有一个很好的方法来复制SQL Server函数ROW_NUMBER()?
例如:
SELECT
col1, col2,
ROW_NUMBER() OVER (PARTITION BY col1, col2 ORDER BY col3 DESC) AS intRow
FROM Table1
然后,例如,我可以添加一个条件,将intRow限制为1,以获得每个(col1, col2)对的col3最高的单行。
当前回答
这允许在MySQL中实现ROW_NUMBER()和PARTITION BY提供的相同功能
SELECT @row_num := IF(@prev_value=GENDER,@row_num+1,1) AS RowNumber
FirstName,
Age,
Gender,
@prev_value := GENDER
FROM Person,
(SELECT @row_num := 1) x,
(SELECT @prev_value := '') y
ORDER BY Gender, Age DESC
其他回答
这允许在MySQL中实现ROW_NUMBER()和PARTITION BY提供的相同功能
SELECT @row_num := IF(@prev_value=GENDER,@row_num+1,1) AS RowNumber
FirstName,
Age,
Gender,
@prev_value := GENDER
FROM Person,
(SELECT @row_num := 1) x,
(SELECT @prev_value := '') y
ORDER BY Gender, Age DESC
我没有看到任何简单的答案涵盖“PARTITION BY”部分,所以我的答案是:
SELECT
*
FROM (
select
CASE WHEN @partitionBy_1 = l THEN @row_number:=@row_number+1 ELSE @row_number:=1 END AS i
, @partitionBy_1:=l AS p
, t.*
from (
select @row_number:=0,@partitionBy_1:=null
) as x
cross join (
select 1 as n, 'a' as l
union all
select 1 as n, 'b' as l
union all
select 2 as n, 'b' as l
union all
select 2 as n, 'a' as l
union all
select 3 as n, 'a' as l
union all
select 3 as n, 'b' as l
) as t
ORDER BY l, n
) AS X
where i > 1
The ORDER BY clause must reflect your ROW_NUMBER need. Thus there's already a clear limitation: you can't have several ROW_NUMBER "emulation" of this form at the same time. The order of the "computed column" matters. If you have mysql compute those column in another order, it might not work. In this simple example I only put one but you can have several "PARTITION BY" parts CASE WHEN @partitionBy_1 = part1 AND @partitionBy_2 = part2 [...] THEN @row_number:=@row_number+1 ELSE @row_number:=1 END AS i , @partitionBy_1:=part1 AS P1 , @partitionBy_2:=part2 AS P2 [...] FROM ( SELECT @row_number:=0,@partitionBy_1:=null,@partitionBy_2:=null[...] ) as x
如果查询有GROUP BY语句,使用交叉连接和逗号的解决方案将不起作用。对于这种情况,您可以使用subselect:
SELECT (@row_number := @row_number + 1) AS rowNumber, res.*
FROM
(
SELECT SUM(r.amount)
FROM Results r
WHERE username = 1
GROUP BY r.amount
) res
CROSS JOIN (SELECT @row_number := 0) AS dummy
MySQL中没有排名功能。最接近的方法是使用变量:
SELECT t.*,
@rownum := @rownum + 1 AS rank
FROM YOUR_TABLE t,
(SELECT @rownum := 0) r
那么在我的案例中这是如何起作用的呢?我需要两个变量,分别代表col1和col2?当col1改变时,Col2需要以某种方式重置…?
是的。如果它是Oracle,您可以使用LEAD函数在下一个值处达到峰值。值得庆幸的是,Quassnoi涵盖了在MySQL中需要实现的逻辑。
我认为你可以在这里使用DENSE_RANK()函数。 例子:
select `score`, DENSE_RANK() OVER( ORDER BY score desc ) as `rank` from Scores;
https://www.mysqltutorial.org/mysql-window-functions/mysql-dense_rank-function/