我试图扩展这里给出的JSON.net示例
http://james.newtonking.com/projects/json/help/CustomCreationConverter.html
我有另一个子类派生自基类/接口
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
public class Employee : Person
{
public string Department { get; set; }
public string JobTitle { get; set; }
}
public class Artist : Person
{
public string Skill { get; set; }
}
List<Person> people = new List<Person>
{
new Employee(),
new Employee(),
new Artist(),
};
我如何反序列化以下Json回到列表<人>
[
{
"Department": "Department1",
"JobTitle": "JobTitle1",
"FirstName": "FirstName1",
"LastName": "LastName1"
},
{
"Department": "Department2",
"JobTitle": "JobTitle2",
"FirstName": "FirstName2",
"LastName": "LastName2"
},
{
"Skill": "Painter",
"FirstName": "FirstName3",
"LastName": "LastName3"
}
]
我不想使用TypeNameHandling JsonSerializerSettings。我特别寻找自定义JsonConverter实现来处理这个问题。关于这方面的文档和示例在网上非常少。我似乎不能得到覆盖的ReadJson()方法实现在JsonConverter的权利。
只是想分享解决方案还在此基础上,与已知类型属性使用反射,不得不从任何基类派生类,解决方案可以受益于递归找到最佳匹配类虽然我不需要在我的例子中,匹配是由类型的转换器,如果已知类型将扫描所有直到匹配类型,所有属性在json字符串,会选择第一个匹配。
用法简单如下:
string json = "{ Name:\"Something\", LastName:\"Otherthing\" }";
var ret = JsonConvert.DeserializeObject<A>(json, new KnownTypeConverter());
在上述情况下，ret将是B型。
JSON类:
[KnownType(typeof(B))]
public class A
{
public string Name { get; set; }
}
public class B : A
{
public string LastName { get; set; }
}
转换代码:
/// <summary>
/// Use KnownType Attribute to match a divierd class based on the class given to the serilaizer
/// Selected class will be the first class to match all properties in the json object.
/// </summary>
public class KnownTypeConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return System.Attribute.GetCustomAttributes(objectType).Any(v => v is KnownTypeAttribute);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
// Load JObject from stream
JObject jObject = JObject.Load(reader);
// Create target object based on JObject
System.Attribute[] attrs = System.Attribute.GetCustomAttributes(objectType); // Reflection.
// Displaying output.
foreach (System.Attribute attr in attrs)
{
if (attr is KnownTypeAttribute)
{
KnownTypeAttribute k = (KnownTypeAttribute) attr;
var props = k.Type.GetProperties();
bool found = true;
foreach (var f in jObject)
{
if (!props.Any(z => z.Name == f.Key))
{
found = false;
break;
}
}
if (found)
{
var target = Activator.CreateInstance(k.Type);
serializer.Populate(jObject.CreateReader(),target);
return target;
}
}
}
throw new ObjectNotFoundException();
// Populate the object properties
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
使用标准的CustomCreationConverter，我在努力工作如何生成正确的类型(Person或Employee)，因为为了确定这一点，你需要分析JSON，并且没有内置的方法来使用Create方法。
我找到了一个关于类型转换的讨论线程，它提供了答案。这里是一个链接:类型转换(存档链接)。
所需要的是继承JsonConverter的子类，覆盖ReadJson方法并创建一个新的抽象Create方法，该方法接受一个JObject。
JObject类提供了加载JSON对象和的方法
提供对此对象内数据的访问。
被重写的ReadJson方法创建一个JObject并调用Create方法(由派生的转换器类实现)，传入JObject实例。
然后可以分析这个JObject实例，通过检查某些字段的存在来确定正确的类型。
例子
string json = "[{
\"Department\": \"Department1\",
\"JobTitle\": \"JobTitle1\",
\"FirstName\": \"FirstName1\",
\"LastName\": \"LastName1\"
},{
\"Department\": \"Department2\",
\"JobTitle\": \"JobTitle2\",
\"FirstName\": \"FirstName2\",
\"LastName\": \"LastName2\"
},
{\"Skill\": \"Painter\",
\"FirstName\": \"FirstName3\",
\"LastName\": \"LastName3\"
}]";
List<Person> persons =
JsonConvert.DeserializeObject<List<Person>>(json, new PersonConverter());
...
public class PersonConverter : JsonCreationConverter<Person>
{
protected override Person Create(Type objectType, JObject jObject)
{
if (FieldExists("Skill", jObject))
{
return new Artist();
}
else if (FieldExists("Department", jObject))
{
return new Employee();
}
else
{
return new Person();
}
}
private bool FieldExists(string fieldName, JObject jObject)
{
return jObject[fieldName] != null;
}
}
public abstract class JsonCreationConverter<T> : JsonConverter
{
/// <summary>
/// Create an instance of objectType, based properties in the JSON object
/// </summary>
/// <param name="objectType">type of object expected</param>
/// <param name="jObject">
/// contents of JSON object that will be deserialized
/// </param>
/// <returns></returns>
protected abstract T Create(Type objectType, JObject jObject);
public override bool CanConvert(Type objectType)
{
return typeof(T).IsAssignableFrom(objectType);
}
public override bool CanWrite
{
get { return false; }
}
public override object ReadJson(JsonReader reader,
Type objectType,
object existingValue,
JsonSerializer serializer)
{
// Load JObject from stream
JObject jObject = JObject.Load(reader);
// Create target object based on JObject
T target = Create(objectType, jObject);
// Populate the object properties
serializer.Populate(jObject.CreateReader(), target);
return target;
}
}
下面是另一个解决方案，它避免使用jObject.CreateReader()，而是创建一个新的JsonTextReader(这是默认JsonCreate使用的行为)。Deserialze方法:
public abstract class JsonCreationConverter<T> : JsonConverter
{
protected abstract T Create(Type objectType, JObject jObject);
public override bool CanConvert(Type objectType)
{
return typeof(T).IsAssignableFrom(objectType);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
if (reader.TokenType == JsonToken.Null)
return null;
// Load JObject from stream
JObject jObject = JObject.Load(reader);
// Create target object based on JObject
T target = Create(objectType, jObject);
// Populate the object properties
StringWriter writer = new StringWriter();
serializer.Serialize(writer, jObject);
using (JsonTextReader newReader = new JsonTextReader(new StringReader(writer.ToString())))
{
newReader.Culture = reader.Culture;
newReader.DateParseHandling = reader.DateParseHandling;
newReader.DateTimeZoneHandling = reader.DateTimeZoneHandling;
newReader.FloatParseHandling = reader.FloatParseHandling;
serializer.Populate(newReader, target);
}
return target;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
serializer.Serialize(writer, value);
}
}
项目JsonSubTypes实现了一个通用转换器，该转换器在属性的帮助下处理该特性。
对于具体的示例，这里提供了它是如何工作的:
[JsonConverter(typeof(JsonSubtypes))]
[JsonSubtypes.KnownSubTypeWithProperty(typeof(Employee), "JobTitle")]
[JsonSubtypes.KnownSubTypeWithProperty(typeof(Artist), "Skill")]
public class Person
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
public class Employee : Person
{
public string Department { get; set; }
public string JobTitle { get; set; }
}
public class Artist : Person
{
public string Skill { get; set; }
}
[TestMethod]
public void Demo()
{
string json = "[{\"Department\":\"Department1\",\"JobTitle\":\"JobTitle1\",\"FirstName\":\"FirstName1\",\"LastName\":\"LastName1\"}," +
"{\"Department\":\"Department1\",\"JobTitle\":\"JobTitle1\",\"FirstName\":\"FirstName1\",\"LastName\":\"LastName1\"}," +
"{\"Skill\":\"Painter\",\"FirstName\":\"FirstName1\",\"LastName\":\"LastName1\"}]";
var persons = JsonConvert.DeserializeObject<IReadOnlyCollection<Person>>(json);
Assert.AreEqual("Painter", (persons.Last() as Artist)?.Skill);
}
作为Totem已知类型解决方案的另一个变体，您可以使用反射来创建泛型类型解析器，以避免使用已知类型属性的需要。
这使用了一种类似于Juval Lowy用于WCF的GenericResolver的技术。
只要基类是抽象类或接口类，就会自动确定已知类型，而不必使用已知类型属性进行装饰。
在我自己的情况下，我选择使用$type属性来指定json对象中的类型，而不是试图从属性中确定它，尽管您可以借鉴其他解决方案来使用基于属性的确定。
public class JsonKnownTypeConverter : JsonConverter
{
public IEnumerable<Type> KnownTypes { get; set; }
public JsonKnownTypeConverter() : this(ReflectTypes())
{
}
public JsonKnownTypeConverter(IEnumerable<Type> knownTypes)
{
KnownTypes = knownTypes;
}
protected object Create(Type objectType, JObject jObject)
{
if (jObject["$type"] != null)
{
string typeName = jObject["$type"].ToString();
return Activator.CreateInstance(KnownTypes.First(x => typeName == x.Name));
}
else
{
return Activator.CreateInstance(objectType);
}
throw new InvalidOperationException("No supported type");
}
public override bool CanConvert(Type objectType)
{
if (KnownTypes == null)
return false;
return (objectType.IsInterface || objectType.IsAbstract) && KnownTypes.Any(objectType.IsAssignableFrom);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
// Load JObject from stream
JObject jObject = JObject.Load(reader);
// Create target object based on JObject
var target = Create(objectType, jObject);
// Populate the object properties
serializer.Populate(jObject.CreateReader(), target);
return target;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
throw new NotImplementedException();
}
//Static helpers
static Assembly CallingAssembly = Assembly.GetCallingAssembly();
static Type[] ReflectTypes()
{
List<Type> types = new List<Type>();
var referencedAssemblies = Assembly.GetExecutingAssembly().GetReferencedAssemblies();
foreach (var assemblyName in referencedAssemblies)
{
Assembly assembly = Assembly.Load(assemblyName);
Type[] typesInReferencedAssembly = GetTypes(assembly);
types.AddRange(typesInReferencedAssembly);
}
return types.ToArray();
}
static Type[] GetTypes(Assembly assembly, bool publicOnly = true)
{
Type[] allTypes = assembly.GetTypes();
List<Type> types = new List<Type>();
foreach (Type type in allTypes)
{
if (type.IsEnum == false &&
type.IsInterface == false &&
type.IsGenericTypeDefinition == false)
{
if (publicOnly == true && type.IsPublic == false)
{
if (type.IsNested == false)
{
continue;
}
if (type.IsNestedPrivate == true)
{
continue;
}
}
types.Add(type);
}
}
return types.ToArray();
}
然后可以将其作为格式化程序安装
GlobalConfiguration.Configuration.Formatters.JsonFormatter.SerializerSettings.Converters.Add(new JsonKnownTypeConverter());
只是想分享解决方案还在此基础上,与已知类型属性使用反射,不得不从任何基类派生类,解决方案可以受益于递归找到最佳匹配类虽然我不需要在我的例子中,匹配是由类型的转换器,如果已知类型将扫描所有直到匹配类型,所有属性在json字符串,会选择第一个匹配。
用法简单如下:
string json = "{ Name:\"Something\", LastName:\"Otherthing\" }";
var ret = JsonConvert.DeserializeObject<A>(json, new KnownTypeConverter());
在上述情况下，ret将是B型。
JSON类:
[KnownType(typeof(B))]
public class A
{
public string Name { get; set; }
}
public class B : A
{
public string LastName { get; set; }
}
转换代码:
/// <summary>
/// Use KnownType Attribute to match a divierd class based on the class given to the serilaizer
/// Selected class will be the first class to match all properties in the json object.
/// </summary>
public class KnownTypeConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return System.Attribute.GetCustomAttributes(objectType).Any(v => v is KnownTypeAttribute);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
// Load JObject from stream
JObject jObject = JObject.Load(reader);
// Create target object based on JObject
System.Attribute[] attrs = System.Attribute.GetCustomAttributes(objectType); // Reflection.
// Displaying output.
foreach (System.Attribute attr in attrs)
{
if (attr is KnownTypeAttribute)
{
KnownTypeAttribute k = (KnownTypeAttribute) attr;
var props = k.Type.GetProperties();
bool found = true;
foreach (var f in jObject)
{
if (!props.Any(z => z.Name == f.Key))
{
found = false;
break;
}
}
if (found)
{
var target = Activator.CreateInstance(k.Type);
serializer.Populate(jObject.CreateReader(),target);
return target;
}
}
}
throw new ObjectNotFoundException();
// Populate the object properties
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
