我试图扩展这里给出的JSON.net示例 http://james.newtonking.com/projects/json/help/CustomCreationConverter.html

我有另一个子类派生自基类/接口

public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
}

public class Employee : Person
{
    public string Department { get; set; }
    public string JobTitle { get; set; }
}

public class Artist : Person
{
    public string Skill { get; set; }
}

List<Person> people  = new List<Person>
{
    new Employee(),
    new Employee(),
    new Artist(),
};

我如何反序列化以下Json回到列表<人>

[
  {
    "Department": "Department1",
    "JobTitle": "JobTitle1",
    "FirstName": "FirstName1",
    "LastName": "LastName1"
  },
  {
    "Department": "Department2",
    "JobTitle": "JobTitle2",
    "FirstName": "FirstName2",
    "LastName": "LastName2"
  },
  {
    "Skill": "Painter",
    "FirstName": "FirstName3",
    "LastName": "LastName3"
  }
]

我不想使用TypeNameHandling JsonSerializerSettings。我特别寻找自定义JsonConverter实现来处理这个问题。关于这方面的文档和示例在网上非常少。我似乎不能得到覆盖的ReadJson()方法实现在JsonConverter的权利。


当前回答

很多时候,实现将与接口存在于相同的名称空间中。所以,我想到了这个:

    public class InterfaceConverter : JsonConverter
    {
    public override bool CanWrite => false;
    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        var token = JToken.ReadFrom(reader);
        var typeVariable = this.GetTypeVariable(token);
        if (TypeExtensions.TryParse(typeVariable, out var implimentation))
        { }
        else if (!typeof(IEnumerable).IsAssignableFrom(objectType))
        {
            implimentation = this.GetImplimentedType(objectType);
        }
        else
        {
            var genericArgumentTypes = objectType.GetGenericArguments();
            var innerType = genericArgumentTypes.FirstOrDefault();
            if (innerType == null)
            {
                implimentation = typeof(IEnumerable);
            }
            else
            {
                Type genericType = null;
                if (token.HasAny())
                {
                    var firstItem = token[0];
                    var genericTypeVariable = this.GetTypeVariable(firstItem);
                    TypeExtensions.TryParse(genericTypeVariable, out genericType);
                }

                genericType = genericType ?? this.GetImplimentedType(innerType);
                implimentation = typeof(IEnumerable<>);
                implimentation = implimentation.MakeGenericType(genericType);
            }
        }

        return JsonConvert.DeserializeObject(token.ToString(), implimentation);
    }

    public override bool CanConvert(Type objectType)
    {
        return !typeof(IEnumerable).IsAssignableFrom(objectType) && objectType.IsInterface || typeof(IEnumerable).IsAssignableFrom(objectType) && objectType.GetGenericArguments().Any(t => t.IsInterface);
    }

    protected Type GetImplimentedType(Type interfaceType)
    {
        if (!interfaceType.IsInterface)
        {
            return interfaceType;
        }

        var implimentationQualifiedName = interfaceType.AssemblyQualifiedName?.Replace(interfaceType.Name, interfaceType.Name.Substring(1));
        return implimentationQualifiedName == null ? interfaceType : Type.GetType(implimentationQualifiedName) ?? interfaceType;
    }

    protected string GetTypeVariable(JToken token)
    {
        if (!token.HasAny())
        {
            return null;
        }

        return token.Type != JTokenType.Object ? null : token.Value<string>("$type");
    }
}

因此,你可以像这样全局地包含它:

public static JsonSerializerSettings StandardSerializerSettings => new JsonSerializerSettings
    {
        Converters = new List<JsonConverter>
        {
            new InterfaceConverter()
        }
    };

其他回答

下面是另一个解决方案,它避免使用jObject.CreateReader(),而是创建一个新的JsonTextReader(这是默认JsonCreate使用的行为)。Deserialze方法:

public abstract class JsonCreationConverter<T> : JsonConverter
{
    protected abstract T Create(Type objectType, JObject jObject);

    public override bool CanConvert(Type objectType)
    {
        return typeof(T).IsAssignableFrom(objectType);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        if (reader.TokenType == JsonToken.Null)
            return null;

        // Load JObject from stream
        JObject jObject = JObject.Load(reader);

        // Create target object based on JObject
        T target = Create(objectType, jObject);

        // Populate the object properties
        StringWriter writer = new StringWriter();
        serializer.Serialize(writer, jObject);
        using (JsonTextReader newReader = new JsonTextReader(new StringReader(writer.ToString())))
        { 
            newReader.Culture = reader.Culture;
            newReader.DateParseHandling = reader.DateParseHandling;
            newReader.DateTimeZoneHandling = reader.DateTimeZoneHandling;
            newReader.FloatParseHandling = reader.FloatParseHandling;
            serializer.Populate(newReader, target);
        }

        return target;
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        serializer.Serialize(writer, value);
    }
}

使用标准的CustomCreationConverter,我在努力工作如何生成正确的类型(Person或Employee),因为为了确定这一点,你需要分析JSON,并且没有内置的方法来使用Create方法。

我找到了一个关于类型转换的讨论线程,它提供了答案。这里是一个链接:类型转换(存档链接)。

所需要的是继承JsonConverter的子类,覆盖ReadJson方法并创建一个新的抽象Create方法,该方法接受一个JObject。

JObject类提供了加载JSON对象和的方法 提供对此对象内数据的访问。

被重写的ReadJson方法创建一个JObject并调用Create方法(由派生的转换器类实现),传入JObject实例。

然后可以分析这个JObject实例,通过检查某些字段的存在来确定正确的类型。

例子

string json = "[{
        \"Department\": \"Department1\",
        \"JobTitle\": \"JobTitle1\",
        \"FirstName\": \"FirstName1\",
        \"LastName\": \"LastName1\"
    },{
        \"Department\": \"Department2\",
        \"JobTitle\": \"JobTitle2\",
        \"FirstName\": \"FirstName2\",
        \"LastName\": \"LastName2\"
    },
        {\"Skill\": \"Painter\",
        \"FirstName\": \"FirstName3\",
        \"LastName\": \"LastName3\"
    }]";

List<Person> persons = 
    JsonConvert.DeserializeObject<List<Person>>(json, new PersonConverter());

...

public class PersonConverter : JsonCreationConverter<Person>
{
    protected override Person Create(Type objectType, JObject jObject)
    {
        if (FieldExists("Skill", jObject))
        {
            return new Artist();
        }
        else if (FieldExists("Department", jObject))
        {
            return new Employee();
        }
        else
        {
            return new Person();
        }
    }

    private bool FieldExists(string fieldName, JObject jObject)
    {
        return jObject[fieldName] != null;
    }
}

public abstract class JsonCreationConverter<T> : JsonConverter
{
    /// <summary>
    /// Create an instance of objectType, based properties in the JSON object
    /// </summary>
    /// <param name="objectType">type of object expected</param>
    /// <param name="jObject">
    /// contents of JSON object that will be deserialized
    /// </param>
    /// <returns></returns>
    protected abstract T Create(Type objectType, JObject jObject);

    public override bool CanConvert(Type objectType)
    {
        return typeof(T).IsAssignableFrom(objectType);
    }

    public override bool CanWrite
    {
        get { return false; }
    }

    public override object ReadJson(JsonReader reader, 
                                    Type objectType, 
                                     object existingValue, 
                                     JsonSerializer serializer)
    {
        // Load JObject from stream
        JObject jObject = JObject.Load(reader);

        // Create target object based on JObject
        T target = Create(objectType, jObject);

        // Populate the object properties
        serializer.Populate(jObject.CreateReader(), target);

        return target;
    }
}

只是想分享解决方案还在此基础上,与已知类型属性使用反射,不得不从任何基类派生类,解决方案可以受益于递归找到最佳匹配类虽然我不需要在我的例子中,匹配是由类型的转换器,如果已知类型将扫描所有直到匹配类型,所有属性在json字符串,会选择第一个匹配。

用法简单如下:

 string json = "{ Name:\"Something\", LastName:\"Otherthing\" }";
 var ret  = JsonConvert.DeserializeObject<A>(json, new KnownTypeConverter());

在上述情况下,ret将是B型。

JSON类:

[KnownType(typeof(B))]
public class A
{
   public string Name { get; set; }
}

public class B : A
{
   public string LastName { get; set; }
}

转换代码:

/// <summary>
    /// Use KnownType Attribute to match a divierd class based on the class given to the serilaizer
    /// Selected class will be the first class to match all properties in the json object.
    /// </summary>
    public  class KnownTypeConverter : JsonConverter
    {
        public override bool CanConvert(Type objectType)
        {
            return System.Attribute.GetCustomAttributes(objectType).Any(v => v is KnownTypeAttribute);
        }

        public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
        {
            // Load JObject from stream
            JObject jObject = JObject.Load(reader);

            // Create target object based on JObject
            System.Attribute[] attrs = System.Attribute.GetCustomAttributes(objectType);  // Reflection. 

                // Displaying output. 
            foreach (System.Attribute attr in attrs)
            {
                if (attr is KnownTypeAttribute)
                {
                    KnownTypeAttribute k = (KnownTypeAttribute) attr;
                    var props = k.Type.GetProperties();
                    bool found = true;
                    foreach (var f in jObject)
                    {
                        if (!props.Any(z => z.Name == f.Key))
                        {
                            found = false;
                            break;
                        }
                    }

                    if (found)
                    {
                        var target = Activator.CreateInstance(k.Type);
                        serializer.Populate(jObject.CreateReader(),target);
                        return target;
                    }
                }
            }
            throw new ObjectNotFoundException();


            // Populate the object properties

        }

        public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
        {
            throw new NotImplementedException();
        }
    }

项目JsonSubTypes实现了一个通用转换器,该转换器在属性的帮助下处理该特性。

对于具体的示例,这里提供了它是如何工作的:

    [JsonConverter(typeof(JsonSubtypes))]
    [JsonSubtypes.KnownSubTypeWithProperty(typeof(Employee), "JobTitle")]
    [JsonSubtypes.KnownSubTypeWithProperty(typeof(Artist), "Skill")]
    public class Person
    {
        public string FirstName { get; set; }
        public string LastName { get; set; }
    }

    public class Employee : Person
    {
        public string Department { get; set; }
        public string JobTitle { get; set; }
    }

    public class Artist : Person
    {
        public string Skill { get; set; }
    }

    [TestMethod]
    public void Demo()
    {
        string json = "[{\"Department\":\"Department1\",\"JobTitle\":\"JobTitle1\",\"FirstName\":\"FirstName1\",\"LastName\":\"LastName1\"}," +
                      "{\"Department\":\"Department1\",\"JobTitle\":\"JobTitle1\",\"FirstName\":\"FirstName1\",\"LastName\":\"LastName1\"}," +
                      "{\"Skill\":\"Painter\",\"FirstName\":\"FirstName1\",\"LastName\":\"LastName1\"}]";


        var persons = JsonConvert.DeserializeObject<IReadOnlyCollection<Person>>(json);
        Assert.AreEqual("Painter", (persons.Last() as Artist)?.Skill);
    }

这是对《图腾》答案的扩展。它做的基本相同的事情,但属性匹配是基于序列化的json对象,而不是反映。net对象。如果你正在使用[JsonProperty],使用CamelCasePropertyNamesContractResolver,或者做任何其他会导致json不匹配。net对象的事情,这是很重要的。

用法很简单:

[KnownType(typeof(B))]
public class A
{
   public string Name { get; set; }
}

public class B : A
{
   public string LastName { get; set; }
}

转换代码:

/// <summary>
/// Use KnownType Attribute to match a divierd class based on the class given to the serilaizer
/// Selected class will be the first class to match all properties in the json object.
/// </summary>
public class KnownTypeConverter : JsonConverter {
    public override bool CanConvert( Type objectType ) {
        return System.Attribute.GetCustomAttributes( objectType ).Any( v => v is KnownTypeAttribute );
    }

    public override bool CanWrite {
        get { return false; }
    }

    public override object ReadJson( JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer ) {
        // Load JObject from stream
        JObject jObject = JObject.Load( reader );

        // Create target object based on JObject
        System.Attribute[ ] attrs = System.Attribute.GetCustomAttributes( objectType );  // Reflection. 

        // check known types for a match. 
        foreach( var attr in attrs.OfType<KnownTypeAttribute>( ) ) {
            object target = Activator.CreateInstance( attr.Type );

            JObject jTest;
            using( var writer = new StringWriter( ) ) {
                using( var jsonWriter = new JsonTextWriter( writer ) ) {
                    serializer.Serialize( jsonWriter, target );
                    string json = writer.ToString( );
                    jTest = JObject.Parse( json );
                }
            }

            var jO = this.GetKeys( jObject ).Select( k => k.Key ).ToList( );
            var jT = this.GetKeys( jTest ).Select( k => k.Key ).ToList( );

            if( jO.Count == jT.Count && jO.Intersect( jT ).Count( ) == jO.Count ) {
                serializer.Populate( jObject.CreateReader( ), target );
                return target;
            }
        }

        throw new SerializationException( string.Format( "Could not convert base class {0}", objectType ) );
    }

    public override void WriteJson( JsonWriter writer, object value, JsonSerializer serializer ) {
        throw new NotImplementedException( );
    }

    private IEnumerable<KeyValuePair<string, JToken>> GetKeys( JObject obj ) {
        var list = new List<KeyValuePair<string, JToken>>( );
        foreach( var t in obj ) {
            list.Add( t );
        }
        return list;
    }
}