在.NET 2.0 c#应用程序中,我使用以下代码来检测操作系统平台:

string os_platform = System.Environment.OSVersion.Platform.ToString();

返回“Win32NT”。问题是即使在Windows Vista 64位上运行,它也会返回“Win32NT”。

有没有其他方法来知道正确的平台(32位或64位)?

注意,当在Windows 64位上作为32位应用程序运行时,它也应该检测64位。


当前回答

OSInfo。位

using System;
namespace CSharp411
{
    class Program
    {
        static void Main( string[] args )
        {
           Console.WriteLine( "Operation System Information" );
           Console.WriteLine( "----------------------------" );
           Console.WriteLine( "Name = {0}", OSInfo.Name );
           Console.WriteLine( "Edition = {0}", OSInfo.Edition );
           Console.WriteLine( "Service Pack = {0}", OSInfo.ServicePack );
           Console.WriteLine( "Version = {0}", OSInfo.VersionString );
           Console.WriteLine( "Bits = {0}", OSInfo.Bits );
           Console.ReadLine();
        }
    }
}

其他回答

使用dotPeek有助于了解框架是如何实际执行的。考虑到这一点,以下是我的想法:

public static class EnvironmentHelper
{
    [DllImport("kernel32.dll")]
    static extern IntPtr GetCurrentProcess();

    [DllImport("kernel32.dll")]
    static extern IntPtr GetModuleHandle(string moduleName);

    [DllImport("kernel32")]
    static extern IntPtr GetProcAddress(IntPtr hModule, string procName);

    [DllImport("kernel32.dll")]
    static extern bool IsWow64Process(IntPtr hProcess, out bool wow64Process);

    public static bool Is64BitOperatingSystem()
    {
        // Check if this process is natively an x64 process. If it is, it will only run on x64 environments, thus, the environment must be x64.
        if (IntPtr.Size == 8)
            return true;
        // Check if this process is an x86 process running on an x64 environment.
        IntPtr moduleHandle = GetModuleHandle("kernel32");
        if (moduleHandle != IntPtr.Zero)
        {
            IntPtr processAddress = GetProcAddress(moduleHandle, "IsWow64Process");
            if (processAddress != IntPtr.Zero)
            {
                bool result;
                if (IsWow64Process(GetCurrentProcess(), out result) && result)
                    return true;
            }
        }
        // The environment must be an x86 environment.
        return false;
    }
}

使用示例:

EnvironmentHelper.Is64BitOperatingSystem();

这只是Bruno Lopez上面建议的一个实现,但适用于Win2k +所有的WinXP服务包。我只是想把它贴出来这样别人就不用亲手卷了。(本可以作为评论发布,但我是一个新用户!)

[DllImport("kernel32", SetLastError = true, CallingConvention = CallingConvention.Winapi)]
public extern static IntPtr LoadLibrary(string libraryName);

[DllImport("kernel32", SetLastError = true, CallingConvention = CallingConvention.Winapi)]
public extern static IntPtr GetProcAddress(IntPtr hwnd, string procedureName);

private delegate bool IsWow64ProcessDelegate([In] IntPtr handle, [Out] out bool isWow64Process);

public static bool IsOS64Bit()
{
    if (IntPtr.Size == 8 || (IntPtr.Size == 4 && Is32BitProcessOn64BitProcessor()))
    {
        return true;
    }
    else
    {
        return false;
    }
}

private static IsWow64ProcessDelegate GetIsWow64ProcessDelegate()
{
  IntPtr handle = LoadLibrary("kernel32");

  if ( handle != IntPtr.Zero)
  {
    IntPtr fnPtr = GetProcAddress(handle, "IsWow64Process");

    if (fnPtr != IntPtr.Zero)
    {
      return (IsWow64ProcessDelegate)Marshal.GetDelegateForFunctionPointer((IntPtr)fnPtr, typeof(IsWow64ProcessDelegate));
    }
  }

  return null;
}

private static bool Is32BitProcessOn64BitProcessor()
{
  IsWow64ProcessDelegate fnDelegate = GetIsWow64ProcessDelegate();

  if (fnDelegate == null)
  {
    return false;
  }

  bool isWow64;
  bool retVal = fnDelegate.Invoke(Process.GetCurrentProcess().Handle, out isWow64);

  if (retVal == false)
  {
    return false;
  }

  return isWow64;
}

还可以检查PROCESSOR_ARCHITECTURE环境变量。

它要么不存在,要么在32位Windows上被设置为“x86”。

private int GetOSArchitecture()
{
    string pa = 
        Environment.GetEnvironmentVariable("PROCESSOR_ARCHITECTURE");
    return ((String.IsNullOrEmpty(pa) || 
             String.Compare(pa, 0, "x86", 0, 3, true) == 0) ? 32 : 64);
}

试试这个:

Environment.Is64BitOperatingSystem

Environment.Is64BitProcess

@foobar:你是对的,这太简单了;)

在99%的情况下,具有较弱系统管理员背景的开发人员最终无法意识到微软一直为任何人提供的枚举Windows的功能。

在这种情况下,系统管理员总是会编写更好、更简单的代码。

然而,有一件事需要注意,构建配置必须是AnyCPU,这个环境变量才能在正确的系统上返回正确的值:

System.Environment.GetEnvironmentVariable("PROCESSOR_ARCHITECTURE")

这将在32位Windows上返回“X86”,在64位Windows上返回“AMD64”。