是否有一种方法可以在没有表单的情况下使用POST方法发送数据,并且只使用纯JavaScript(而不是jQuery $.post())刷新页面?也许httprequest或其他东西(只是不能找到它现在)?


当前回答

你可以使用XMLHttpRequest, fetch API,… 如果您想使用XMLHttpRequest,可以执行以下操作

var xhr = new XMLHttpRequest();
xhr.open("POST", url, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
    name: "Deska",
    email: "deska@gmail.com",
    phone: "342234553"
 }));
xhr.onload = function() {
    var data = JSON.parse(this.responseText);
    console.log(data);
};

或者如果你想使用取回API

fetch(url, {
    method:"POST",
    body: JSON.stringify({
        name: "Deska",
        email: "deska@gmail.com",
        phone: "342234553"
        })
    }).then(result => {
        // do something with the result
        console.log("Completed with result:", result);
    }).catch(err => {
        // if any error occured, then catch it here
        console.error(err);
    });

其他回答

领航员sendBeacon()。

如果你只是需要POST数据,不需要服务器的响应,最短的解决方案是使用navigator.sendBeacon():

const data = JSON.stringify({
  example_1: 123,
  example_2: 'Hello, world!',
});

navigator.sendBeacon('example.php', data);

你可以使用XMLHttpRequest, fetch API,… 如果您想使用XMLHttpRequest,可以执行以下操作

var xhr = new XMLHttpRequest();
xhr.open("POST", url, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
    name: "Deska",
    email: "deska@gmail.com",
    phone: "342234553"
 }));
xhr.onload = function() {
    var data = JSON.parse(this.responseText);
    console.log(data);
};

或者如果你想使用取回API

fetch(url, {
    method:"POST",
    body: JSON.stringify({
        name: "Deska",
        email: "deska@gmail.com",
        phone: "342234553"
        })
    }).then(result => {
        // do something with the result
        console.log("Completed with result:", result);
    }).catch(err => {
        // if any error occured, then catch it here
        console.error(err);
    });

这里有一个很好的函数,你(或其他人)可以在他们的代码中使用:

function post(url, data) {
    return new Promise((res, rej) => {
        let stringified = "";
        for (const [key, value] of Object.entries(data))
            stringified += `${stringified != '' ? '&' : ''}${key}=${value}`

        const xhr = new XMLHttpRequest();
        xhr.onreadystatechange = () => {
            if (xhr.readyState == 4)
                if (xhr.status == 200)
                    res(xhr.responseText)
                else
                    rej({ code: xhr.status, text: xhr.responseText })
        }
        xhr.open("POST", url, true);
        xhr.setRequestHeader('Content-Type', 'application/json');
        xhr.send(stringified);
    })
}

使用jbezz库的这个函数

var makeHttpObject = function () {
  try {return new XMLHttpRequest();}
  catch (error) {}
  try {return new ActiveXObject("Msxml2.XMLHTTP");}
  catch (error) {}
  try {return new ActiveXObject("Microsoft.XMLHTTP");}
  catch (error) {}
  throw new Error("Could not create HTTP request object.");
}
function SendData(data){
    let type = (data.type ? data.type : "GET")
    let DataS = data.data;
    let url = data.url;
    let func = (data.success ? data.success : function(){})
    let funcE =(data.error ? data.error : function(){})
    let a_syne = (data.asyne ? data.asyne : false); 
    let u = null;
    try{u = new URLSearchParams(DataS).toString();}catch(e){u = Object.keys(DataS).map(function(k) {return encodeURIComponent(k) + '=' + encodeURIComponent(DataS[k])}).join('&')}
    if(type == "GET"){url +="?"+u}
    const xhttp =  makeHttpObject();
    xhttp.onload = function(){func(this.responseText)}
    xmlHttp.onreadystatechange = function() {if (xmlHttp.readyState == 4) 
    {if(xmlHttp.status !== 200){funcE(xmlHttp.statusText)}}}
    xhttp.open(type,url,a_syne);
    xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    xhttp.send(u);
}

使用这个运行:

SendData({
    url:"YOUR_URL",
    asyne:true,
    type:"POST", // or GET
    data:{
        username:"ali",
        password:"mypass" // Your Data
    },
    success:function(Result){
        console.log(Result)
    },
    error:function(e){
        console.log("We Have Some Error")
    }
});

Or

下载jbezz并添加到您的页面。

下载链接:github.com

使用:

$$.api({
        url:"YOUR_URL",
        asyne:true,
        type:"POST", // or GET
        data:{
            username:"ali",
            password:"mypass" // Your Data
        },
        success:function(Result){
            console.log(Result)
        },
        error:function(e){
            console.log("We Have Some Error")
        }
    });
const data = { username: 'example' };

fetch('https://example.com/profile', {
  method: 'POST', // or 'PUT'
  headers: {
 '           Content-Type': 'application/json',
           },
  body: JSON.stringify(data),
})
  .then(response => response.json())
  .then(data => {
      console.log('Success:', data);
     })
 .catch((error) => {
         console.error('Error:', error);
   });