是否有一种方法可以在没有表单的情况下使用POST方法发送数据,并且只使用纯JavaScript(而不是jQuery $.post())刷新页面?也许httprequest或其他东西(只是不能找到它现在)?
当前回答
你知道JavaScript有内置的方法和库来创建和提交表单吗?
我在这里看到很多回复都要求使用第三方库,我认为这是多余的。
我将在纯Javascript中做以下工作:
<script>
function launchMyForm()
{
var myForm = document.createElement("FORM");
myForm.setAttribute("id","TestForm");
document.body.appendChild(myForm);
// this will create a new FORM which is mapped to the Java Object of myForm, with an id of TestForm. Equivalent to: <form id="TestForm"></form>
var myInput = document.createElement("INPUT");
myInput.setAttribute("id","MyInput");
myInput.setAttribute("type","text");
myInput.setAttribute("value","Heider");
document.getElementById("TestForm").appendChild(myInput);
// To submit the form:
myForm.method = "POST";
myForm.action = "whatever.aspx"; // or "response.php"
myForm.submit();
// This will create an INPUT equivalent to: <INPUT id="MyInput" type="text" value="Heider" /> and then assign it to be inside the TestForm tags.
}
</script>
这样(A)你就不需要依靠第三方来做这项工作。(B)所有浏览器都内置它,(C)更快,(D)它有效,请随意试用。
我希望这能有所帮助。
H
其他回答
你知道JavaScript有内置的方法和库来创建和提交表单吗?
我在这里看到很多回复都要求使用第三方库,我认为这是多余的。
我将在纯Javascript中做以下工作:
<script>
function launchMyForm()
{
var myForm = document.createElement("FORM");
myForm.setAttribute("id","TestForm");
document.body.appendChild(myForm);
// this will create a new FORM which is mapped to the Java Object of myForm, with an id of TestForm. Equivalent to: <form id="TestForm"></form>
var myInput = document.createElement("INPUT");
myInput.setAttribute("id","MyInput");
myInput.setAttribute("type","text");
myInput.setAttribute("value","Heider");
document.getElementById("TestForm").appendChild(myInput);
// To submit the form:
myForm.method = "POST";
myForm.action = "whatever.aspx"; // or "response.php"
myForm.submit();
// This will create an INPUT equivalent to: <INPUT id="MyInput" type="text" value="Heider" /> and then assign it to be inside the TestForm tags.
}
</script>
这样(A)你就不需要依靠第三方来做这项工作。(B)所有浏览器都内置它,(C)更快,(D)它有效,请随意试用。
我希望这能有所帮助。
H
你可以使用XMLHttpRequest, fetch API,… 如果您想使用XMLHttpRequest,可以执行以下操作
var xhr = new XMLHttpRequest();
xhr.open("POST", url, true);
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.send(JSON.stringify({
name: "Deska",
email: "deska@gmail.com",
phone: "342234553"
}));
xhr.onload = function() {
var data = JSON.parse(this.responseText);
console.log(data);
};
或者如果你想使用取回API
fetch(url, {
method:"POST",
body: JSON.stringify({
name: "Deska",
email: "deska@gmail.com",
phone: "342234553"
})
}).then(result => {
// do something with the result
console.log("Completed with result:", result);
}).catch(err => {
// if any error occured, then catch it here
console.error(err);
});
Fetch API旨在使GET请求变得容易,但它也能够POST。
let data = {element: "barium"};
fetch("/post/data/here", {
method: "POST",
headers: {'Content-Type': 'application/json'},
body: JSON.stringify(data)
}).then(res => {
console.log("Request complete! response:", res);
});
如果你和我一样懒(或者只是喜欢快捷方式/助手):
window.post = function(url, data) {
return fetch(url, {method: "POST", headers: {'Content-Type': 'application/json'}, body: JSON.stringify(data)});
}
// ...
post("post/data/here", {element: "osmium"});
你可以像下面这样使用XMLHttpRequest对象:
xhr.open("POST", url, true);
xhr.setRequestHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
xhr.send(someStuff);
代码会将someStuff发布到url。只要确保在创建XMLHttpRequest对象时,它是跨浏览器兼容的。关于如何做到这一点,有无数的例子。
使用jbezz库的这个函数
var makeHttpObject = function () {
try {return new XMLHttpRequest();}
catch (error) {}
try {return new ActiveXObject("Msxml2.XMLHTTP");}
catch (error) {}
try {return new ActiveXObject("Microsoft.XMLHTTP");}
catch (error) {}
throw new Error("Could not create HTTP request object.");
}
function SendData(data){
let type = (data.type ? data.type : "GET")
let DataS = data.data;
let url = data.url;
let func = (data.success ? data.success : function(){})
let funcE =(data.error ? data.error : function(){})
let a_syne = (data.asyne ? data.asyne : false);
let u = null;
try{u = new URLSearchParams(DataS).toString();}catch(e){u = Object.keys(DataS).map(function(k) {return encodeURIComponent(k) + '=' + encodeURIComponent(DataS[k])}).join('&')}
if(type == "GET"){url +="?"+u}
const xhttp = makeHttpObject();
xhttp.onload = function(){func(this.responseText)}
xmlHttp.onreadystatechange = function() {if (xmlHttp.readyState == 4)
{if(xmlHttp.status !== 200){funcE(xmlHttp.statusText)}}}
xhttp.open(type,url,a_syne);
xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhttp.send(u);
}
使用这个运行:
SendData({
url:"YOUR_URL",
asyne:true,
type:"POST", // or GET
data:{
username:"ali",
password:"mypass" // Your Data
},
success:function(Result){
console.log(Result)
},
error:function(e){
console.log("We Have Some Error")
}
});
Or
下载jbezz并添加到您的页面。
下载链接:github.com
使用:
$$.api({
url:"YOUR_URL",
asyne:true,
type:"POST", // or GET
data:{
username:"ali",
password:"mypass" // Your Data
},
success:function(Result){
console.log(Result)
},
error:function(e){
console.log("We Have Some Error")
}
});