是否有一种简单的方法来遍历列名和值对?
我的SQLAlchemy版本是0.5.6
下面是我尝试使用dict(row)的示例代码:
import sqlalchemy
from sqlalchemy import *
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker
print "sqlalchemy version:",sqlalchemy.__version__
engine = create_engine('sqlite:///:memory:', echo=False)
metadata = MetaData()
users_table = Table('users', metadata,
Column('id', Integer, primary_key=True),
Column('name', String),
)
metadata.create_all(engine)
class User(declarative_base()):
__tablename__ = 'users'
id = Column(Integer, primary_key=True)
name = Column(String)
def __init__(self, name):
self.name = name
Session = sessionmaker(bind=engine)
session = Session()
user1 = User("anurag")
session.add(user1)
session.commit()
# uncommenting next line throws exception 'TypeError: 'User' object is not iterable'
#print dict(user1)
# this one also throws 'TypeError: 'User' object is not iterable'
for u in session.query(User).all():
print dict(u)
在我的系统输出上运行这段代码:
Traceback (most recent call last):
File "untitled-1.py", line 37, in <module>
print dict(u)
TypeError: 'User' object is not iterable
正如@balki提到的:
如果您正在查询特定的字段，可以使用_asdict()方法，因为它作为KeyedTuple返回。
In [1]: foo = db.session.query(Topic.name).first()
In [2]: foo._asdict()
Out[2]: {'name': u'blah'}
然而，如果您没有指定列，则可以使用其他建议的方法之一——例如@charlax提供的方法。注意，此方法仅对2.7+有效。
In [1]: foo = db.session.query(Topic).first()
In [2]: {x.name: getattr(foo, x.name) for x in foo.__table__.columns}
Out[2]: {'name': u'blah'}
返回this:class:的内容。KeyedTuple作为字典
In [46]: result = aggregate_events[0]
In [47]: type(result)
Out[47]: sqlalchemy.util._collections.result
In [48]: def to_dict(query_result=None):
...: cover_dict = {key: getattr(query_result, key) for key in query_result.keys()}
...: return cover_dict
...:
...:
In [49]: to_dict(result)
Out[49]:
{'calculate_avg': None,
'calculate_max': None,
'calculate_min': None,
'calculate_sum': None,
'dataPointIntID': 6,
'data_avg': 10.0,
'data_max': 10.0,
'data_min': 10.0,
'data_sum': 60.0,
'deviceID': u'asas',
'productID': u'U7qUDa',
'tenantID': u'CvdQcYzUM'}
如OP所述，调用dict初始化器会引发一个异常，消息为“User”对象不可迭代。所以真正的问题是如何使一个SQLAlchemy模型可迭代?
We'll have to implement the special methods __iter__ and __next__, but if we inherit directly from the declarative_base model, we would still run into the undesirable "_sa_instance_state" key. What's worse, is we would have to loop through __dict__.keys() for every call to __next__ because the keys() method returns a View -- an iterable that is not indexed. This would increase the time complexity by a factor of N, where N is the number of keys in __dict__. Generating the dict would cost O(N^2). We can do better.
我们可以实现自己的基类，它实现所需的特殊方法，并存储可以通过索引访问的列名列表，从而降低生成O(N)字典的时间复杂性。这有一个额外的好处，我们可以定义一次逻辑，并在任何时候从基类继承，我们希望我们的模型类是可迭代的。
class IterableBase(declarative_base()):
__abstract__ = True
def _init_keys(self):
self._keys = [c.name for c in self.__table__.columns]
self._dict = {c.name: getattr(self, c.name) for c in self.__table__.columns}
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self._init_keys()
def __setattr__(self, name, value):
super().__setattr__(name, value)
if name not in ('_dict', '_keys', '_n') and '_dict' in self.__dict__:
self._dict[name] = value
def __iter__(self):
self._n = 0
return self
def __next__(self):
if self._n >= len(self._keys):
raise StopIteration
self._n += 1
key = self._keys[self._n-1]
return (key, self._dict[key])
现在User类可以直接从IterableBase类继承。
class User(IterableBase):
__tablename__ = 'users'
id = Column(Integer, primary_key=True)
name = Column(String)
您可以确认，以User实例作为参数调用dict函数将返回所需的字典，没有"_sa_instance_state"。你可能已经注意到在IterableBase类中声明的__setattr__方法。这确保在初始化后属性发生变化或设置时更新_dict。
def main():
user1 = User('Bob')
print(dict(user1))
# outputs {'id': None, 'name': 'Bob'}
user1.id = 42
print(dict(user1))
# outputs {'id': 42, 'name': 'Bob'}
if __name__ == '__main__':
main()
