我们有请求。UserHostAddress在ASP. ASP. ASP中获取IP地址。NET,但这通常是用户的ISP的IP地址,而不是用户点击链接的机器IP地址。如何获取真实IP地址?

例如,在Stack Overflow用户配置文件中,它是:“上次帐户活动:4小时前从86.123.127.8开始”,但我的机器IP地址有点不同。Stack Overflow如何获得这个地址?

在一些web系统中,出于某些目的有一个IP地址检查。例如,对于某个IP地址,每24小时用户只能点击5次下载链接吗?这个IP地址应该是唯一的,而不是针对一个拥有大量客户端或互联网用户的ISP。

我听懂了吗?


当前回答

在NuGet包中安装Microsoft.AspNetCore.HttpOverrides 然后尝试:

public class ClientDeviceInfo
    {
        private readonly IHttpContextAccessor httpAccessor;

        public ClientDeviceInfo(IHttpContextAccessor httpAccessor)
        {
            this.httpAccessor = httpAccessor;
        }

        public string GetClientLocalIpAddress()
        {
            return httpAccessor.HttpContext.Connection.LocalIpAddress.ToString();
        }

        public string GetClientRemoteIpAddress()
        {
            return httpAccessor.HttpContext.Connection.RemoteIpAddress.ToString();
        }

        public string GetClientLocalPort()
        {
            return httpAccessor.HttpContext.Connection.LocalPort.ToString();
        }

        public string GetClientRemotePort()
        {
            return httpAccessor.HttpContext.Connection.RemotePort.ToString();
        }
     }

其他回答

到目前为止,所有的响应都考虑了非标准化但非常常见的X-Forwarded-For报头。有一个标准化的转发头,它有点难以解析。一些例子如下:

Forwarded: for="_gazonk"
Forwarded: For="[2001:db8:cafe::17]:4711"
Forwarded: for=192.0.2.60;proto=http;by=203.0.113.43
Forwarded: for=192.0.2.43, for=198.51.100.17

我已经编写了一个类,在确定客户端的IP地址时考虑这两个头。

using System;
using System.Web;

namespace Util
{
    public static class IP
    {
        public static string GetIPAddress()
        {
            return GetIPAddress(new HttpRequestWrapper(HttpContext.Current.Request));
        }

        internal static string GetIPAddress(HttpRequestBase request)
        {
            // handle standardized 'Forwarded' header
            string forwarded = request.Headers["Forwarded"];
            if (!String.IsNullOrEmpty(forwarded))
            {
                foreach (string segment in forwarded.Split(',')[0].Split(';'))
                {
                    string[] pair = segment.Trim().Split('=');
                    if (pair.Length == 2 && pair[0].Equals("for", StringComparison.OrdinalIgnoreCase))
                    {
                        string ip = pair[1].Trim('"');

                        // IPv6 addresses are always enclosed in square brackets
                        int left = ip.IndexOf('['), right = ip.IndexOf(']');
                        if (left == 0 && right > 0)
                        {
                            return ip.Substring(1, right - 1);
                        }

                        // strip port of IPv4 addresses
                        int colon = ip.IndexOf(':');
                        if (colon != -1)
                        {
                            return ip.Substring(0, colon);
                        }

                        // this will return IPv4, "unknown", and obfuscated addresses
                        return ip;
                    }
                }
            }

            // handle non-standardized 'X-Forwarded-For' header
            string xForwardedFor = request.Headers["X-Forwarded-For"];
            if (!String.IsNullOrEmpty(xForwardedFor))
            {
                return xForwardedFor.Split(',')[0];
            }

            return request.UserHostAddress;
        }
    }
}

下面是我用来验证我的解决方案的一些单元测试:

using System.Collections.Specialized;
using System.Web;
using Microsoft.VisualStudio.TestTools.UnitTesting;

namespace UtilTests
{
    [TestClass]
    public class IPTests
    {
        [TestMethod]
        public void TestForwardedObfuscated()
        {
            var request = new HttpRequestMock("for=\"_gazonk\"");
            Assert.AreEqual("_gazonk", Util.IP.GetIPAddress(request));
        }

        [TestMethod]
        public void TestForwardedIPv6()
        {
            var request = new HttpRequestMock("For=\"[2001:db8:cafe::17]:4711\"");
            Assert.AreEqual("2001:db8:cafe::17", Util.IP.GetIPAddress(request));
        }

        [TestMethod]
        public void TestForwardedIPv4()
        {
            var request = new HttpRequestMock("for=192.0.2.60;proto=http;by=203.0.113.43");
            Assert.AreEqual("192.0.2.60", Util.IP.GetIPAddress(request));
        }

        [TestMethod]
        public void TestForwardedIPv4WithPort()
        {
            var request = new HttpRequestMock("for=192.0.2.60:443;proto=http;by=203.0.113.43");
            Assert.AreEqual("192.0.2.60", Util.IP.GetIPAddress(request));
        }

        [TestMethod]
        public void TestForwardedMultiple()
        {
            var request = new HttpRequestMock("for=192.0.2.43, for=198.51.100.17");
            Assert.AreEqual("192.0.2.43", Util.IP.GetIPAddress(request));
        }
    }

    public class HttpRequestMock : HttpRequestBase
    {
        private NameValueCollection headers = new NameValueCollection();

        public HttpRequestMock(string forwarded)
        {
            headers["Forwarded"] = forwarded;
        }

        public override NameValueCollection Headers
        {
            get { return this.headers; }
        }
    }
}

IP地址是“七层堆栈”中的网络层的一部分。网络层可以对IP地址做任何它想做的事情。这就是代理服务器、NAT、中继或其他设备所发生的情况。

应用层不应该以任何方式依赖于IP地址。特别是,IP地址不意味着是网络连接一端的标识符以外的任何标识符。一旦连接被关闭,(同一用户的)IP地址就会发生变化。

Try:

using System.Net;

public static string GetIpAddress()  // Get IP Address
{
    string ip = "";     
    IPHostEntry ipEntry = Dns.GetHostEntry(GetCompCode());
    IPAddress[] addr = ipEntry.AddressList;
    ip = addr[2].ToString();
    return ip;
}
public static string GetCompCode()  // Get Computer Name
{   
    string strHostName = "";
    strHostName = Dns.GetHostName();
    return strHostName;
}

您还认为用户IP地址是什么?如果你想要网络适配器的IP地址,恐怕在Web应用程序中没有办法做到这一点。如果你的用户在NAT或其他东西后面,你也无法获得IP。

更新:虽然有些网站使用IP来限制用户(如rapidshare),但它们在NAT环境中不能正常工作。

在NuGet包中安装Microsoft.AspNetCore.HttpOverrides 然后尝试:

public class ClientDeviceInfo
    {
        private readonly IHttpContextAccessor httpAccessor;

        public ClientDeviceInfo(IHttpContextAccessor httpAccessor)
        {
            this.httpAccessor = httpAccessor;
        }

        public string GetClientLocalIpAddress()
        {
            return httpAccessor.HttpContext.Connection.LocalIpAddress.ToString();
        }

        public string GetClientRemoteIpAddress()
        {
            return httpAccessor.HttpContext.Connection.RemoteIpAddress.ToString();
        }

        public string GetClientLocalPort()
        {
            return httpAccessor.HttpContext.Connection.LocalPort.ToString();
        }

        public string GetClientRemotePort()
        {
            return httpAccessor.HttpContext.Connection.RemotePort.ToString();
        }
     }