我一直在到处找这个,但我似乎找不到。我知道如何解雇使用Objective-C键盘,但我不知道如何使用Swift?有人知道吗?


当前回答

//Simple exercise to demonstrate, assuming the view controller has a //Textfield, Button and a Label. And that the label should display the //userinputs when button clicked. And if you want the keyboard to disappear //when clicken anywhere on the screen + upon clicking Return key in the //keyboard. Dont forget to add "UITextFieldDelegate" and 
//"self.userInput.delegate = self" as below

import UIKit

class ViewController: UIViewController,UITextFieldDelegate {

    @IBOutlet weak var userInput: UITextField!
    @IBAction func transferBtn(sender: AnyObject) {
                display.text = userInput.text

    }
    @IBOutlet weak var display: UILabel!

    override func viewDidLoad() {
        super.viewDidLoad()

//This is important for the textFieldShouldReturn function, conforming to textfieldDelegate and setting it to self
        self.userInput.delegate = self
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

//This is for the keyboard to GO AWAYY !! when user clicks anywhere on the view
    override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
        self.view.endEditing(true)
    }


//This is for the keyboard to GO AWAYY !! when user clicks "Return" key  on the keyboard

    func textFieldShouldReturn(textField: UITextField) -> Bool {
        textField.resignFirstResponder()
        return true
    }

}

其他回答

我得到了你

override func viewDidLoad() {
    super.viewDidLoad() /*This ensures that our view loaded*/
    self.textField.delegate = self /*we select our text field that we want*/   
    self.view.addGestureRecognizer(UITapGestureRecognizer(target: self, action: Selector("dismissKeyboard")))
}

func dismissKeyboard(){ /*this is a void function*/
    textField.resignFirstResponder() /*This will dismiss our keyboard on tap*/
}

下面是关于如何在Xcode 6.1中使用Swift消除键盘的回答:

import UIKit

class ItemViewController: UIViewController, UITextFieldDelegate {

    @IBOutlet var textFieldItemName: UITextField!

    @IBOutlet var textFieldQt: UITextField!

    @IBOutlet var textFieldMoreInfo: UITextField!


    override func viewDidLoad() {
        super.viewDidLoad()

        textFieldItemName.delegate = self
        textFieldQt.delegate = self
        textFieldMoreInfo.delegate = self
    }

                       ...

    /**
     * Called when 'return' key pressed. return NO to ignore.
     */
    func textFieldShouldReturn(textField: UITextField) -> Bool {
        textField.resignFirstResponder()
        return true
    }


   /**
    * Called when the user click on the view (outside the UITextField).
    */
    override func touchesBegan(touches: Set<UITouch>, withEvent event: UIEvent?) {
        self.view.endEditing(true)
    }

}

(此信息的来源)。

我发现最好的解决方案包括来自@Esqarrouth的接受答案,并进行了一些调整:

extension UIViewController {
    func hideKeyboardWhenTappedAround() {
        let tap: UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: "dismissKeyboardView")
        tap.cancelsTouchesInView = false
        view.addGestureRecognizer(tap)
    }

    func dismissKeyboardView() {
        view.endEditing(true)
    }
}

电话响了。cancelsTouchesInView = false是关键的:它确保UITapGestureRecognizer不会阻止视图上的其他元素接收用户交互。

方法解雇键盘()被更改为稍微不那么优雅的解雇keyboardview()。这是因为在我的项目相当旧的代码库中,有很多次已经使用了dismissKeyboard()(我想这并不少见),导致编译器问题。

然后,如上所述,这个行为可以在各个视图控制器中启用:

override func viewDidLoad() {
    super.viewDidLoad()
    self.hideKeyboardWhenTappedAround() 
}

如果你有其他视图也应该接收触摸,你必须设置 cancelsTouchesInView = false

是这样的:

let elsewhereTap = UITapGestureRecognizer(target: self, action: #selector(dismissKeyboard))
    elsewhereTap.cancelsTouchesInView = false
    self.view.addGestureRecognizer(elsewhereTap)

以下是如何通过点击其他地方来消除键盘,使用Swift 5只需两行。

(我讨厌添加另一个答案,但由于这是谷歌上的顶级结果,我将帮助像我这样的新手。)

在你的ViewController.swift中,找到viewDidLoad()函数。

加上这两行:

let tap: UIGestureRecognizer = UITapGestureRecognizer(target: self.view, action: #selector(UIView.endEditing))
        
view.addGestureRecognizer(tap)