最好的方式:

function(
  a, b               // Placeholders
){
  for(               // Loop :)
      b = a = '';    // b - result , a - numeric variable
      a++ < 36;      //
      b += a*51&52   // If "a" is not 9 or 14 or 19 or 24
                  ?  //  return a random number or 4
           (
               a^15              // If "a" is not 15,
                  ?              // generate a random number from 0 to 15
               8^Math.random() *
               (a^20 ? 16 : 4)   // unless "a" is 20, in which case a random number from 8 to 11,
                  :
               4                 //  otherwise 4
           ).toString(16)
                  :
         '-'                     //  In other cases, (if "a" is 9,14,19,24) insert "-"
      );
  return b
 }

最小化:

function(a,b){for(b=a='';a++<36;b+=a*51&52?(a^15?8^Math.random()*(a^20?16:4):4).toString(16):'-');return b}

您可以使用 npm 包指南、GUID 发电机和验证器。

例子:

Guid.raw();
// -> '6fdf6ffc-ed77-94fa-407e-a7b86ed9e59d'

注意: 此包已被削弱. 使用 uuid 相反。

例子:

const uuidv4 = require('uuid/v4');
uuidv4(); // ⇨ '10ba038e-48da-487b-96e8-8d3b99b6d18a'

  // RFC 4122
  //
  // A UUID is 128 bits long
  //
  // String representation is five fields of 4, 2, 2, 2, and 6 bytes.
  // Fields represented as lowercase, zero-filled, hexadecimal strings, and
  // are separated by dash characters
  //
  // A version 4 UUID is generated by setting all but six bits to randomly
  // chosen values
  var uuid = [
    Math.random().toString(16).slice(2, 10),
    Math.random().toString(16).slice(2, 6),

    // Set the four most significant bits (bits 12 through 15) of the
    // time_hi_and_version field to the 4-bit version number from Section
    // 4.1.3
    (Math.random() * .0625 /* 0x.1 */ + .25 /* 0x.4 */).toString(16).slice(2, 6),

    // Set the two most significant bits (bits 6 and 7) of the
    // clock_seq_hi_and_reserved to zero and one, respectively
    (Math.random() * .25 /* 0x.4 */ + .5 /* 0x.8 */).toString(16).slice(2, 6),

    Math.random().toString(16).slice(2, 14)].join('-');

只有在任何人落下谷歌正在寻找一个小用途图书馆的情况下,ShortId满足了这个问题的所有要求,它允许指定允许的字符和长度,并保证不序列,不重复的线条。

为了使这一点更为真实的答案,该图书馆的核心使用下列逻辑来制作其简短的ID:

function encode(lookup, number) {
    var loopCounter = 0;
    var done;

    var str = '';

    while (!done) {
        str = str + lookup( ( (number >> (4 * loopCounter)) & 0x0f ) | randomByte() );
        done = number < (Math.pow(16, loopCounter + 1 ) );
        loopCounter++;
    }
    return str;
}

/* Generates the short id */
function generate() {

    var str = '';

    var seconds = Math.floor((Date.now() - REDUCE_TIME) * 0.001);

    if (seconds === previousSeconds) {
        counter++;
    } else {
        counter = 0;
        previousSeconds = seconds;
    }

    str = str + encode(alphabet.lookup, version);
    str = str + encode(alphabet.lookup, clusterWorkerId);
    if (counter > 0) {
        str = str + encode(alphabet.lookup, counter);
    }
    str = str + encode(alphabet.lookup, seconds);

    return str;
}

我没有编辑这只是反映这个方法的最基本部分,所以上面的代码包含一些额外的逻辑从图书馆. 如果你对它正在做的一切好奇,请看看来源: https://github.com/dylang/shortid/tree/master/lib

下面是顶级投票答案的组合,与Chrome的冲突工作组合:

generateGUID = (typeof(window.crypto) != 'undefined' &&
                typeof(window.crypto.getRandomValues) != 'undefined') ?
    function() {
        // If we have a cryptographically secure PRNG, use that
        // https://stackoverflow.com/questions/6906916/collisions-when-generating-uuids-in-javascript
        var buf = new Uint16Array(8);
        window.crypto.getRandomValues(buf);
        var S4 = function(num) {
            var ret = num.toString(16);
            while(ret.length < 4){
                ret = "0"+ret;
            }
            return ret;
        };
        return (S4(buf[0])+S4(buf[1])+"-"+S4(buf[2])+"-"+S4(buf[3])+"-"+S4(buf[4])+"-"+S4(buf[5])+S4(buf[6])+S4(buf[7]));
    }

    :

    function() {
        // Otherwise, just use Math.random
        // https://stackoverflow.com/questions/105034/how-to-create-a-guid-uuid-in-javascript/2117523#2117523
        return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, function(c) {
            var r = Math.random()*16|0, v = c == 'x' ? r : (r&0x3|0x8);
            return v.toString(16);
        });
    };

这是在Jsbin,如果你想测试它。

                  Desktop   Android
           broofa: 1617ms   12869ms
               e1:  636ms    5778ms
               e2:  606ms    4754ms
               e3:  364ms    3003ms
               e4:  329ms    2015ms
               e5:  147ms    1156ms
               e6:  146ms    1035ms
               e7:  105ms     726ms
             guid:  962ms   10762ms
generateQuickGuid:  292ms    2961ms
  - Note: 500k iterations, results will vary by browser/CPU.

对于一个解释,让我们从Brofa的代码开始:

因此,它取代 x 与任何随机六分数数字, y 与随机数据(除了强迫顶部两个比特到 10 个 RFC 特征),而 regex 不匹配 - 或 4 个字符,所以他不需要处理它们。

下一个优化是另一个经典. 因为我们只处理四个字符串的输出,让我们将字符串的数量切成一半,并在每个字符串中处理八个字符串。 这是荒谬的,因为我们仍然必须处理RFC相应的字符串位置,但它不是太困难。

编辑: http://jcward.com/UUID.js - UUID.generate()