如何解决“惰性初始化角色集合失败”Hibernate异常

我有这样一个问题:

org.hibernate.LazyInitializationException:惰性初始化role: mvc3.model.Topic.comments集合失败，没有会话或会话已关闭

下面是模型:

@Entity
@Table(name = "T_TOPIC")
public class Topic {

    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private int id;

    @ManyToOne
    @JoinColumn(name="USER_ID")
    private User author;

    @Enumerated(EnumType.STRING)    
    private Tag topicTag;

    private String name;
    private String text;

    @OneToMany(mappedBy = "topic", cascade = CascadeType.ALL)
    private Collection<Comment> comments = new LinkedHashSet<Comment>();

    ...

    public Collection<Comment> getComments() {
           return comments;
    }

}

调用model的控制器如下所示:

@Controller
@RequestMapping(value = "/topic")
public class TopicController {

    @Autowired
    private TopicService service;

    private static final Logger logger = LoggerFactory.getLogger(TopicController.class);


    @RequestMapping(value = "/details/{topicId}", method = RequestMethod.GET)
    public ModelAndView details(@PathVariable(value="topicId") int id)
    {

            Topic topicById = service.findTopicByID(id);
            Collection<Comment> commentList = topicById.getComments();

            Hashtable modelData = new Hashtable();
            modelData.put("topic", topicById);
            modelData.put("commentList", commentList);

            return new ModelAndView("/topic/details", modelData);

     }

}

jsp页面看起来如下所示:

<%@page import="com.epam.mvc3.helpers.Utils"%>
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%@ page session="false" %>
<html>
<head>
      <title>View Topic</title>
</head>
<body>

<ul>
<c:forEach items="${commentList}" var="item">
<jsp:useBean id="item" type="mvc3.model.Comment"/>
<li>${item.getText()}</li>

</c:forEach>
</ul>
</body>
</html>

在查看jsp时，将引发异常。在c:forEach循环的行中

当前回答

在我的Spring-Boot项目中，spring.jpa.open-in-view在application.properties中被设置为false。将其设置为true就解决了这个问题。

2021-12-27 17:43:30

其他回答

对于fetch = FetchType.LAZY，你应该有两个东西。

@Transactional

and

Hibernate.initialize(topicById.getComments());

2019-10-05 03:54:15

在我的Spring-Boot项目中，spring.jpa.open-in-view在application.properties中被设置为false。将其设置为true就解决了这个问题。

2021-12-27 17:43:30

通过使用hibernate @Transactional注释，如果你从数据库中获得一个具有惰性获取属性的对象，你可以像这样简单地获取这些属性:

@Transactional
public void checkTicketSalePresence(UUID ticketUuid, UUID saleUuid) {
        Optional<Ticket> savedTicketOpt = ticketRepository.findById(ticketUuid);
        savedTicketOpt.ifPresent(ticket -> {
            Optional<Sale> saleOpt = ticket.getSales().stream().filter(sale -> sale.getUuid() == saleUuid).findFirst();
            assertThat(saleOpt).isPresent();
        });
}

这里，在Hibernate代理管理的事务中，调用ticket.getSales()执行另一个查询来获取sales，因为您显式地请求了它。

2018-07-25 09:53:53

处理LazyInitializationException的最好方法是在查询时加入取回，像这样:

select t
from Topic t
left join fetch t.comments

您应该始终避免以下反模式:

FetchType。急切的 OSIV (Open Session in View) 冬眠。enable_lazy_load_no_trans Hibernate配置属性

因此，确保你的FetchType。LAZY关联在查询时或使用Hibernate在原始的@Transactional范围内初始化。初始化辅助集合。

2018-06-27 06:21:50

此问题是由于在关闭hibernate会话的情况下访问属性造成的。控制器中没有hibernate事务。

可能的解决方式:

Do all this logic, in the service layer, (with the @Transactional), not in the controller. There should be the right place to do this, it is part of the logic of the app, not in the controller (in this case, an interface to load the model). All the operations in the service layer should be transactional. i.e.: Move this line to the TopicService.findTopicByID method: Collection commentList = topicById.getComments(); Use 'eager' instead of 'lazy'. Now you are not using 'lazy' .. it is not a real solution, if you want to use lazy, works like a temporary (very temporary) workaround. use @Transactional in the Controller. It should not be used here, you are mixing service layer with presentation, it is not a good design. use OpenSessionInViewFilter, many disadvantages reported, possible instability.

一般来说，最佳解是1。

2017-02-13 14:17:16

如何解决“惰性初始化角色集合失败”Hibernate异常

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