我有这样一个问题:

org.hibernate.LazyInitializationException:惰性初始化role: mvc3.model.Topic.comments集合失败,没有会话或会话已关闭

下面是模型:

@Entity
@Table(name = "T_TOPIC")
public class Topic {

    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private int id;

    @ManyToOne
    @JoinColumn(name="USER_ID")
    private User author;

    @Enumerated(EnumType.STRING)    
    private Tag topicTag;

    private String name;
    private String text;

    @OneToMany(mappedBy = "topic", cascade = CascadeType.ALL)
    private Collection<Comment> comments = new LinkedHashSet<Comment>();

    ...

    public Collection<Comment> getComments() {
           return comments;
    }

}

调用model的控制器如下所示:

@Controller
@RequestMapping(value = "/topic")
public class TopicController {

    @Autowired
    private TopicService service;

    private static final Logger logger = LoggerFactory.getLogger(TopicController.class);


    @RequestMapping(value = "/details/{topicId}", method = RequestMethod.GET)
    public ModelAndView details(@PathVariable(value="topicId") int id)
    {

            Topic topicById = service.findTopicByID(id);
            Collection<Comment> commentList = topicById.getComments();

            Hashtable modelData = new Hashtable();
            modelData.put("topic", topicById);
            modelData.put("commentList", commentList);

            return new ModelAndView("/topic/details", modelData);

     }

}

jsp页面看起来如下所示:

<%@page import="com.epam.mvc3.helpers.Utils"%>
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<%@ page session="false" %>
<html>
<head>
      <title>View Topic</title>
</head>
<body>

<ul>
<c:forEach items="${commentList}" var="item">
<jsp:useBean id="item" type="mvc3.model.Comment"/>
<li>${item.getText()}</li>

</c:forEach>
</ul>
</body>
</html>

在查看jsp时,将引发异常。在c:forEach循环的行中


当前回答

你的列表是惰性加载的,所以列表没有加载。 仅仅通过电话进入名单是不够的。 在Hibernate中使用。初始化以初始化列表。 如果不起作用,运行列表元素并调用Hibernate。初始化每一个。 这需要在从事务范围返回之前进行。 看看这篇文章。 搜寻-

Node n = // .. get the node
Hibernate.initialize(n); // initializes 'parent' similar to getParent.
Hibernate.initialize(n.getChildren()); // pass the lazy collection into the session 

其他回答

我发现将@PersistenceContext声明为EXTENDED也解决了这个问题:

@PersistenceContext(type = PersistenceContextType.EXTENDED)

原因是当您使用延迟加载时,会话是关闭的。

有两种解决方案。

不要使用惰性加载。 在XML中设置lazy=false或在注释中设置@OneToMany(fetch = FetchType.EAGER)。 使用惰性加载。 在XML中设置lazy=true或在注释中设置@OneToMany(fetch = FetchType.LAZY)。 并在web.xml中添加OpenSessionInViewFilter过滤器

详见我的帖子。

在我的情况下,下面的代码是一个问题:

entityManager.detach(topicById);
topicById.getComments() // exception thrown

因为它从数据库中分离,当需要时Hibernate不再从字段中检索list。所以我在分离之前初始化它:

Hibernate.initialize(topicById.getComments());
entityManager.detach(topicById);
topicById.getComments() // works like a charm

此问题是由于在关闭hibernate会话的情况下访问属性造成的。控制器中没有hibernate事务。

可能的解决方式:

Do all this logic, in the service layer, (with the @Transactional), not in the controller. There should be the right place to do this, it is part of the logic of the app, not in the controller (in this case, an interface to load the model). All the operations in the service layer should be transactional. i.e.: Move this line to the TopicService.findTopicByID method: Collection commentList = topicById.getComments(); Use 'eager' instead of 'lazy'. Now you are not using 'lazy' .. it is not a real solution, if you want to use lazy, works like a temporary (very temporary) workaround. use @Transactional in the Controller. It should not be used here, you are mixing service layer with presentation, it is not a good design. use OpenSessionInViewFilter, many disadvantages reported, possible instability.

一般来说,最佳解是1。

最好的解决方案之一是在应用程序中添加以下内容。属性文件: spring.jpa.properties.hibernate.enable_lazy_load_no_trans = true