我知道这有点老了，但是…

ES2015:

var toHHMMSS = (secs) => {
    var sec_num = parseInt(secs, 10)
    var hours   = Math.floor(sec_num / 3600)
    var minutes = Math.floor(sec_num / 60) % 60
    var seconds = sec_num % 60

    return [hours,minutes,seconds]
        .map(v => v < 10 ? "0" + v : v)
        .filter((v,i) => v !== "00" || i > 0)
        .join(":")
}

它将输出:

toHHMMSS(129600) // 36:00:00
toHHMMSS(13545) // 03:45:45
toHHMMSS(180) // 03:00
toHHMMSS(18) // 00:18

有很多解决这个问题的选项，显然有很好的选项建议，但我想在这里添加一个更优化的代码

function formatSeconds(sec) {
     return [(sec / 3600), ((sec % 3600) / 60), ((sec % 3600) % 60)]
            .map(v => v < 10 ? "0" + parseInt(v) : parseInt(v))
            .filter((i, j) => i !== "00" || j > 0)
            .join(":");
}

如果你不想格式化0和小于10的数字，你可以使用

function formatSeconds(sec) {
  return parseInt(sec / 3600) + ':' + parseInt((sec % 3600) / 60) + ':' + parseInt((sec % 3600) % 60);

}

示例代码http://fiddly.org/1c476/1

我认为标准Date对象的任何内置特性都不会以一种比自己做数学更方便的方式为您做这件事。

hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
minutes = Math.floor(totalSeconds / 60);
seconds = totalSeconds % 60;

例子:

let totalSeconds = 28565; let hours = Math.floor(totalSeconds / 3600); totalSeconds %= 3600; let minutes = Math.floor(totalSeconds / 60); let seconds = totalSeconds % 60; console.log("hours: " + hours); console.log("minutes: " + minutes); console.log("seconds: " + seconds); // If you want strings with leading zeroes: minutes = String(minutes).padStart(2, "0"); hours = String(hours).padStart(2, "0"); seconds = String(seconds).padStart(2, "0"); console.log(hours + ":" + minutes + ":" + seconds);

var  timeInSec = "661"; //even it can be string

String.prototype.toHHMMSS = function () { 
   /* extend the String by using prototypical inheritance */
    var seconds = parseInt(this, 10); // don't forget the second param
    var hours   = Math.floor(seconds / 3600);
    var minutes = Math.floor((seconds - (hours * 3600)) / 60);
    seconds = seconds - (hours * 3600) - (minutes * 60);

    if (hours   < 10) {hours   = "0"+hours;}
    if (minutes < 10) {minutes = "0"+minutes;}
    if (seconds < 10) {seconds = "0"+seconds;}
    var time    = hours+':'+minutes+':'+seconds;
    return time;
}

alert("5678".toHHMMSS());   // "01:34:38"
console.log(timeInSec.toHHMMSS());   //"00:11:01"

我们可以把这个函数写得更短更清晰，但这会降低可读性，所以我们要把它写得尽可能简单，尽可能稳定。

或者你可以在这里检查一下:

这是一个非常简单的任务，但你们中的一些人直接推荐了Moment.js，或者创建了一些最丑陋的函数来解析一些秒…

transform(time: number): string {
    if (time != null) {
        const hours: number = Math.floor(time / 3600);
        const minutes: number = Math.floor((time - (hours * 3600)) / 60);
        const seconds: number = time - (hours * 3600) - (minutes * 60);
        return [hours, (minutes < 10) ? '0' + minutes : minutes, (seconds < 10) ? '0' + seconds : seconds].join(':');
    } else {
        return '00:00:00';
    }
}

这在任何情况下都适用……

这招很管用:

function secondstotime(secs)
{
    var t = new Date(1970,0,1);
    t.setSeconds(secs);
    var s = t.toTimeString().substr(0,8);
    if(secs > 86399)
        s = Math.floor((t - Date.parse("1/1/70")) / 3600000) + s.substr(2);
    return s;
}

(来源此处)