我认为标准Date对象的任何内置特性都不会以一种比自己做数学更方便的方式为您做这件事。

hours = Math.floor(totalSeconds / 3600);
totalSeconds %= 3600;
minutes = Math.floor(totalSeconds / 60);
seconds = totalSeconds % 60;

例子:

let totalSeconds = 28565; let hours = Math.floor(totalSeconds / 3600); totalSeconds %= 3600; let minutes = Math.floor(totalSeconds / 60); let seconds = totalSeconds % 60; console.log("hours: " + hours); console.log("minutes: " + minutes); console.log("seconds: " + seconds); // If you want strings with leading zeroes: minutes = String(minutes).padStart(2, "0"); hours = String(hours).padStart(2, "0"); seconds = String(seconds).padStart(2, "0"); console.log(hours + ":" + minutes + ":" + seconds);

下面是一个函数，根据powtac的答案将秒转换为hh-mm-ss格式

斯菲德尔

/** 
 * Convert seconds to hh-mm-ss format.
 * @param {number} totalSeconds - the total seconds to convert to hh- mm-ss
**/
var SecondsTohhmmss = function(totalSeconds) {
  var hours   = Math.floor(totalSeconds / 3600);
  var minutes = Math.floor((totalSeconds - (hours * 3600)) / 60);
  var seconds = totalSeconds - (hours * 3600) - (minutes * 60);

  // round seconds
  seconds = Math.round(seconds * 100) / 100

  var result = (hours < 10 ? "0" + hours : hours);
      result += "-" + (minutes < 10 ? "0" + minutes : minutes);
      result += "-" + (seconds  < 10 ? "0" + seconds : seconds);
  return result;
}

示例使用

var seconds = SecondsTohhmmss(70);
console.log(seconds);
// logs 00-01-10

当我想象一个时钟或计时器时，我会这样做:

const secondsTo_HHMMSS = (seconds) => {
      //format to a readable friendly timer
      let hour = Math.floor(seconds / 3600);
      let minute = Math.floor((seconds % 3600) / 60);
      let second = seconds % 60;

      if(hour.toString().length === 1) {
            hour = `0${hour}`;
      }
      if(minute.toString().length === 1) {
            minute = `0${minute}`;
      }
      if(second.toString().length === 1) {
            second = `0${second}`;
      };

      let timer = `${hour}-${minute}-${second}`;

      return timer;
}

我只是想对上面这个不错的答案做一点解释:

var totalSec = new Date().getTime() / 1000;
var hours = parseInt( totalSec / 3600 ) % 24;
var minutes = parseInt( totalSec / 60 ) % 60;
var seconds = totalSec % 60;

var result = (hours < 10 ? "0" + hours : hours) + "-" + (minutes < 10 ? "0" + minutes : minutes) + "-" + (seconds  < 10 ? "0" + seconds : seconds);

On the second line, since there are 3600 seconds in 1 hour, we divide the total number of seconds by 3600 to get the total number of hours. We use parseInt to strip off any decimal. If totalSec was 12600 (3 and half hours), then parseInt( totalSec / 3600 ) would return 3, since we will have 3 full hours. Why do we need the % 24 in this case? If we exceed 24 hours, let's say we have 25 hours (90000 seconds), then the modulo here will take us back to 1 again, rather than returning 25. It is confining the result within a 24 hour limit, since there are 24 hours in one day.

当你看到这样的东西:

25 % 24

你可以这样想:

25 mod 24 or what is the remainder when we divide 25 by 24

再来看看这个老话题——OP表示HH:MM:SS，许多解决方案都很有效，直到你意识到你需要的时间不止24小时。也许你只需要一行代码。给你:

d=(s)=>{f=Math.floor;g=(n)=>('00'+n).slice(-2);return f(s/3600)+':'+g(f(s/60)%60)+':'+g(s%60)}

它返回H+:MM:SS。要使用它，只需使用:

d(91260);     // returns "25:21:00"
d(960);       // returns "0:16:00"

.．.我试图让它使用尽可能少的代码，这是一种很好的一行程序方法。

这是一个非常简单的任务，但你们中的一些人直接推荐了Moment.js，或者创建了一些最丑陋的函数来解析一些秒…

transform(time: number): string {
    if (time != null) {
        const hours: number = Math.floor(time / 3600);
        const minutes: number = Math.floor((time - (hours * 3600)) / 60);
        const seconds: number = time - (hours * 3600) - (minutes * 60);
        return [hours, (minutes < 10) ? '0' + minutes : minutes, (seconds < 10) ? '0' + seconds : seconds].join(':');
    } else {
        return '00:00:00';
    }
}

这在任何情况下都适用……