使用策略的解决方案:

interface INumericPolicy<T>
{
    T Zero();
    T Add(T a, T b);
    // add more functions here, such as multiplication etc.
}

struct NumericPolicies:
    INumericPolicy<int>,
    INumericPolicy<long>
    // add more INumericPolicy<> for different numeric types.
{
    int INumericPolicy<int>.Zero() { return 0; }
    long INumericPolicy<long>.Zero() { return 0; }
    int INumericPolicy<int>.Add(int a, int b) { return a + b; }
    long INumericPolicy<long>.Add(long a, long b) { return a + b; }
    // implement all functions from INumericPolicy<> interfaces.

    public static NumericPolicies Instance = new NumericPolicies();
}

算法:

static class Algorithms
{
    public static T Sum<P, T>(this P p, params T[] a)
        where P: INumericPolicy<T>
    {
        var r = p.Zero();
        foreach(var i in a)
        {
            r = p.Add(r, i);
        }
        return r;
    }

}

用法:

int i = NumericPolicies.Instance.Sum(1, 2, 3, 4, 5);
long l = NumericPolicies.Instance.Sum(1L, 2, 3, 4, 5);
NumericPolicies.Instance.Sum("www", "") // compile-time error.

该解决方案是编译时安全的。CityLizard框架提供了。net 4.0的编译版本。文件名为“lib/NETFramework4.0/ citylizad . policy .dll”。

它也可以在Nuget: https://www.nuget.org/packages/CityLizard/。参见CityLizard.Policy.I结构。

使用策略的解决方案:

interface INumericPolicy<T>
{
    T Zero();
    T Add(T a, T b);
    // add more functions here, such as multiplication etc.
}

struct NumericPolicies:
    INumericPolicy<int>,
    INumericPolicy<long>
    // add more INumericPolicy<> for different numeric types.
{
    int INumericPolicy<int>.Zero() { return 0; }
    long INumericPolicy<long>.Zero() { return 0; }
    int INumericPolicy<int>.Add(int a, int b) { return a + b; }
    long INumericPolicy<long>.Add(long a, long b) { return a + b; }
    // implement all functions from INumericPolicy<> interfaces.

    public static NumericPolicies Instance = new NumericPolicies();
}

算法:

static class Algorithms
{
    public static T Sum<P, T>(this P p, params T[] a)
        where P: INumericPolicy<T>
    {
        var r = p.Zero();
        foreach(var i in a)
        {
            r = p.Add(r, i);
        }
        return r;
    }

}

用法:

int i = NumericPolicies.Instance.Sum(1, 2, 3, 4, 5);
long l = NumericPolicies.Instance.Sum(1L, 2, 3, 4, 5);
NumericPolicies.Instance.Sum("www", "") // compile-time error.

该解决方案是编译时安全的。CityLizard框架提供了。net 4.0的编译版本。文件名为“lib/NETFramework4.0/ citylizad . policy .dll”。

它也可以在Nuget: https://www.nuget.org/packages/CityLizard/。参见CityLizard.Policy.I结构。

十多年后，这个特性终于出现在。net 7中。最通用的接口是INumber<TSelf>而不是innumeric(在系统中。数字名称空间)，它不仅包含整数类型。要只接受整数类型，可以考虑使用IBinaryInteger<TSelf>。以你的原型，神秘的IntegerFunction为例:

static bool IntegerFunction<T>(T value) where T : IBinaryInteger<T> {
    return value > T.Zero;
}

Console.WriteLine(IntegerFunction(5));         // True
Console.WriteLine(IntegerFunction((sbyte)-5)); // False
Console.WriteLine(IntegerFunction((ulong)5));  // True

下面的答案(现在已经过时了)是作为一个历史的角度。

c#不支持这一点。在接受Bruce Eckel的采访时，Hejlsberg描述了没有实现该功能的原因:

And it's not clear that the added complexity is worth the small yield that you get. If something you want to do is not directly supported in the constraint system, you can do it with a factory pattern. You could have a Matrix<T>, for example, and in that Matrix you would like to define a dot product method. That of course that means you ultimately need to understand how to multiply two Ts, but you can't say that as a constraint, at least not if T is int, double, or float. But what you could do is have your Matrix take as an argument a Calculator<T>, and in Calculator<T>, have a method called multiply. You go implement that and you pass it to the Matrix.

然而，这会导致相当复杂的代码，用户必须为他们想要使用的每个T提供自己的Calculator<T>实现。只要它不需要是可扩展的，也就是说，如果你只想支持固定数量的类型，比如int和double，你可以使用一个相对简单的接口:

var mat = new Matrix<int>(w, h);

(GitHub Gist中的最小实现。)

然而，一旦您希望用户能够提供他们自己的自定义类型，您就需要打开这个实现，以便用户能够提供他们自己的Calculator实例。例如，要实例化一个使用自定义十进制浮点数实现DFP的矩阵，你必须编写以下代码:

var mat = new Matrix<DFP>(DfpCalculator.Instance, w, h);

实现DfpCalculator的所有成员:ICalculator<DFP>。

正如Sergey Shandar的回答中所讨论的那样，另一种选择(不幸的是，它也有同样的局限性)是使用策略类。

这个练习的意义是什么?

正如人们已经指出的，你可以让一个非泛型函数取最大的项，编译器会自动为你转换较小的整型。

static bool IntegerFunction(Int64 value) { }

如果您的函数处于性能关键的路径上(在我看来，这是不太可能的)，您可以为所有需要的函数提供重载。

static bool IntegerFunction(Int64 value) { }
...
static bool IntegerFunction(Int16 value) { }

. net数字基元类型不共享任何允许它们用于计算的公共接口。可以定义自己的接口(例如ISignedWholeNumber)来执行这样的操作，定义包含单个Int16、Int32等的结构并实现这些接口，然后有方法接受受ISignedWholeNumber约束的泛型类型，但是必须将数值转换为你的结构类型可能是一个麻烦。

An alternative approach would be to define static class Int64Converter<T> with a static property bool Available {get;}; and static delegates for Int64 GetInt64(T value), T FromInt64(Int64 value), bool TryStoreInt64(Int64 value, ref T dest). The class constructor could use be hard-coded to load delegates for known types, and possibly use Reflection to test whether type T implements methods with the proper names and signatures (in case it's something like a struct which contains an Int64 and represents a number, but has a custom ToString() method). This approach would lose the advantages associated with compile-time type-checking, but would still manage to avoid boxing operations and each type would only have to be "checked" once. After that, operations associated with that type would be replaced with a delegate dispatch.

不幸的是，在这种情况下，只能在where子句中指定struct。不能具体指定Int16、Int32等，这看起来确实很奇怪，但我相信，在决定不允许在where子句中使用值类型的基础上，有一些深层的实现原因。

我想唯一的解决方案是执行运行时检查，这不幸地阻止了在编译时拾取问题。大概是这样的:-

static bool IntegerFunction<T>(T value) where T : struct {
  if (typeof(T) != typeof(Int16)  &&
      typeof(T) != typeof(Int32)  &&
      typeof(T) != typeof(Int64)  &&
      typeof(T) != typeof(UInt16) &&
      typeof(T) != typeof(UInt32) &&
      typeof(T) != typeof(UInt64)) {
    throw new ArgumentException(
      string.Format("Type '{0}' is not valid.", typeof(T).ToString()));
  }

  // Rest of code...
}

我知道这有点难看，但至少提供了所需的约束条件。

我还将研究此实现可能的性能影响，也许有更快的方法。