这可以在Postgres中使用like或ilike以及any或all with array实现。这是我使用Postgres 9的一个例子:

select id, name from tb_organisation where name ilike any (array['%wembley%', '%south%']);

然后打印出来:

 id  |          name
-----+------------------------
 433 | South Tampa Center
 613 | South Pole
 365 | Bromley South
 796 | Wembley Special Events
 202 | Southall
 111 | Wembley Inner Space

如果你正在使用MySQL，你可以得到的最接近全文搜索:

全文搜索，MySQL文档

我在这里与SQl Server和Oracle一起工作，但我感兴趣的是，这是否可能在任何RDBMS中。

Teradata支持LIKE ALL/ANY语法:

ALL every string in the list. ANY any string in the list. ┌──────────────────────────────┬────────────────────────────────────┐ │ THIS expression … │ IS equivalent to this expression … │ ├──────────────────────────────┼────────────────────────────────────┤ │ x LIKE ALL ('A%','%B','%C%') │ x LIKE 'A%' │ │ │ AND x LIKE '%B' │ │ │ AND x LIKE '%C%' │ │ │ │ │ x LIKE ANY ('A%','%B','%C%') │ x LIKE 'A%' │ │ │ OR x LIKE '%B' │ │ │ OR x LIKE '%C%' │ └──────────────────────────────┴────────────────────────────────────┘

编辑:

jOOQ 3.12.0版本支持该语法:

添加合成[NOT]像任何和[NOT]像所有操作符

很多时候，SQL用户希望能够组合like和IN谓词，例如: SELECT * 从客户 WHERE last_name [NOT] LIKE ANY ('A%'， 'E%') [ESCAPE '!'] 解决方法是手动将谓词展开为等效谓词 SELECT * 从客户 WHERE last_name LIKE 'A%' 或last_name LIKE 'E%' jOOQ可以开箱即用地支持这样一个合成谓词。

LIKE/ILIKE ANY(数组[]):

SELECT *
FROM t
WHERE c LIKE ANY (ARRAY['A%', '%B']);

SELECT *
FROM t
WHERE c LIKE ANY ('{"Do%", "%at"}');

db < > fiddle演示

雪花也支持LIKE ANY/LIKE ALL匹配:

像任何/所有 允许基于与一个或多个模式比较的字符串进行区分大小写的匹配。 <subject> LIKE ANY (<pattern1> [， <pattern2>…) [ESCAPE <escape_char>]

例子:

SELECT * 
FROM like_example 
WHERE subject LIKE ANY ('%Jo%oe%','T%e')
-- WHERE subject LIKE ALL ('%Jo%oe%','J%e')

使用内部连接代替:

SELECT ...
FROM SomeTable
JOIN
(SELECT 'bla%' AS Pattern 
UNION ALL SELECT '%foo%'
UNION ALL SELECT 'batz%'
UNION ALL SELECT 'abc'
) AS Patterns
ON SomeTable.SomeColumn LIKE Patterns.Pattern

你被困在

WHERE something LIKE 'bla%'
OR something LIKE '%foo%'
OR something LIKE 'batz%'

除非你填充一个临时表(包括数据中的通配符)并像这样连接:

FROM YourTable                y
    INNER JOIN YourTempTable  t On y.something LIKE t.something

试试(使用SQL Server语法):

declare @x table (x varchar(10))
declare @y table (y varchar(10))

insert @x values ('abcdefg')
insert @x values ('abc')
insert @x values ('mnop')

insert @y values ('%abc%')
insert @y values ('%b%')

select distinct *
FROM @x x
WHERE x.x LIKE '%abc%' 
   or x.x LIKE '%b%'


select distinct x.*  
FROM @x             x
    INNER JOIN  @y  y On x.x LIKE y.y

输出:

x
----------
abcdefg
abc

(2 row(s) affected)

x
----------
abc
abcdefg

(2 row(s) affected)

您可以以牺牲性能为代价，为大量元素动态地执行此操作，但这是可行的。

DECLARE @val nvarchar(256),
@list nvarchar(max) = 'one,two,three,ten,five';
CREATE table #table  (FIRST_NAME nvarchar(512), LAST_NAME nvarchar(512));
CREATE table #student  (FIRST_NAME nvarchar(512), LAST_NAME nvarchar(512), EMAIL 
nvarchar(512));
INSERT INTO #student (FIRST_NAME, LAST_NAME, EMAIL)
SELECT 'TEST', ' redOne' ,'test.redOne@toto.com' UNION ALL
SELECT 'student', ' student' ,'student@toto.com' UNION ALL
SELECT 'student', ' two' ,'student.two@toto.com' UNION ALL
SELECT 'hello', ' ONE TWO THREE' ,'student.two@toto.com'

DECLARE check_cursor CURSOR FOR select value from STRING_SPLIT(@list,',')

OPEN check_cursor  
FETCH NEXT FROM check_cursor INTO @val
WHILE @@FETCH_STATUS = 0  
    BEGIN
     PRINT @val
       IF EXISTS (select * from #student where REPLACE(FIRST_NAME, ' ','') 
like '%' + @val + '%' OR REPLACE(LAST_NAME, ' ','') like '%' + @val + '%') 
       BEGIN
       INSERT INTO #table (FIRST_NAME, LAST_NAME )
       SELECT TOP 1 FIRST_NAME, LAST_NAME VALUE from #student where 
REPLACE(FIRST_NAME, ' ','') like '%' + @val + '%' OR REPLACE(LAST_NAME, ' ','') 
like '%' + @val + '%'
       END;

      FETCH NEXT FROM check_cursor INTO @val 
    END
CLOSE check_cursor;  
DEALLOCATE check_cursor;  

SELECT * FROM #table;
DROP TABLE #table;
DROP TABLE #student;