从2016年开始，SQL Server包含了一个STRING_SPLIT函数。我使用SQL Server v17.4，我得到了这为我工作:

DECLARE @dashboard nvarchar(50)
SET @dashboard = 'P1%,P7%'

SELECT * from Project p
JOIN STRING_SPLIT(@dashboard, ',') AS sp ON p.ProjectNumber LIKE sp.value

这样做

WHERE something + '%' in ('bla', 'foo', 'batz')
OR '%' + something + '%' in ('tra', 'la', 'la')

or

WHERE something + '%' in (select col from table where ....)

我在这里与SQl Server和Oracle一起工作，但我感兴趣的是，这是否可能在任何RDBMS中。

Teradata支持LIKE ALL/ANY语法:

ALL every string in the list. ANY any string in the list. ┌──────────────────────────────┬────────────────────────────────────┐ │ THIS expression … │ IS equivalent to this expression … │ ├──────────────────────────────┼────────────────────────────────────┤ │ x LIKE ALL ('A%','%B','%C%') │ x LIKE 'A%' │ │ │ AND x LIKE '%B' │ │ │ AND x LIKE '%C%' │ │ │ │ │ x LIKE ANY ('A%','%B','%C%') │ x LIKE 'A%' │ │ │ OR x LIKE '%B' │ │ │ OR x LIKE '%C%' │ └──────────────────────────────┴────────────────────────────────────┘

编辑:

jOOQ 3.12.0版本支持该语法:

添加合成[NOT]像任何和[NOT]像所有操作符

很多时候，SQL用户希望能够组合like和IN谓词，例如: SELECT * 从客户 WHERE last_name [NOT] LIKE ANY ('A%'， 'E%') [ESCAPE '!'] 解决方法是手动将谓词展开为等效谓词 SELECT * 从客户 WHERE last_name LIKE 'A%' 或last_name LIKE 'E%' jOOQ可以开箱即用地支持这样一个合成谓词。

LIKE/ILIKE ANY(数组[]):

SELECT *
FROM t
WHERE c LIKE ANY (ARRAY['A%', '%B']);

SELECT *
FROM t
WHERE c LIKE ANY ('{"Do%", "%at"}');

db < > fiddle演示

雪花也支持LIKE ANY/LIKE ALL匹配:

像任何/所有 允许基于与一个或多个模式比较的字符串进行区分大小写的匹配。 <subject> LIKE ANY (<pattern1> [， <pattern2>…) [ESCAPE <escape_char>]

例子:

SELECT * 
FROM like_example 
WHERE subject LIKE ANY ('%Jo%oe%','T%e')
-- WHERE subject LIKE ALL ('%Jo%oe%','J%e')

没有这样的回答:

SELECT * FROM table WHERE something LIKE ('bla% %foo% batz%')

在甲骨文没有问题。

您可以以牺牲性能为代价，为大量元素动态地执行此操作，但这是可行的。

DECLARE @val nvarchar(256),
@list nvarchar(max) = 'one,two,three,ten,five';
CREATE table #table  (FIRST_NAME nvarchar(512), LAST_NAME nvarchar(512));
CREATE table #student  (FIRST_NAME nvarchar(512), LAST_NAME nvarchar(512), EMAIL 
nvarchar(512));
INSERT INTO #student (FIRST_NAME, LAST_NAME, EMAIL)
SELECT 'TEST', ' redOne' ,'test.redOne@toto.com' UNION ALL
SELECT 'student', ' student' ,'student@toto.com' UNION ALL
SELECT 'student', ' two' ,'student.two@toto.com' UNION ALL
SELECT 'hello', ' ONE TWO THREE' ,'student.two@toto.com'

DECLARE check_cursor CURSOR FOR select value from STRING_SPLIT(@list,',')

OPEN check_cursor  
FETCH NEXT FROM check_cursor INTO @val
WHILE @@FETCH_STATUS = 0  
    BEGIN
     PRINT @val
       IF EXISTS (select * from #student where REPLACE(FIRST_NAME, ' ','') 
like '%' + @val + '%' OR REPLACE(LAST_NAME, ' ','') like '%' + @val + '%') 
       BEGIN
       INSERT INTO #table (FIRST_NAME, LAST_NAME )
       SELECT TOP 1 FIRST_NAME, LAST_NAME VALUE from #student where 
REPLACE(FIRST_NAME, ' ','') like '%' + @val + '%' OR REPLACE(LAST_NAME, ' ','') 
like '%' + @val + '%'
       END;

      FETCH NEXT FROM check_cursor INTO @val 
    END
CLOSE check_cursor;  
DEALLOCATE check_cursor;  

SELECT * FROM #table;
DROP TABLE #table;
DROP TABLE #student;

你甚至可以试试这个

函数

CREATE  FUNCTION [dbo].[fn_Split](@text varchar(8000), @delimiter varchar(20))
RETURNS @Strings TABLE
(   
  position int IDENTITY PRIMARY KEY,
  value varchar(8000)  
)
AS
BEGIN

DECLARE @index int
SET @index = -1

WHILE (LEN(@text) > 0)
  BEGIN 
    SET @index = CHARINDEX(@delimiter , @text) 
    IF (@index = 0) AND (LEN(@text) > 0) 
      BEGIN  
        INSERT INTO @Strings VALUES (@text)
          BREAK 
      END 
    IF (@index > 1) 
      BEGIN  
        INSERT INTO @Strings VALUES (LEFT(@text, @index - 1))  
        SET @text = RIGHT(@text, (LEN(@text) - @index)) 
      END 
    ELSE
      SET @text = RIGHT(@text, (LEN(@text) - @index))
    END
  RETURN
END

查询

select * from my_table inner join (select value from fn_split('ABC,MOP',','))
as split_table on my_table.column_name like '%'+split_table.value+'%';