我有一些东西在设置。py,我想能够从模板访问,但我不知道如何做到这一点。我已经试过了
{{CONSTANT_NAME}}
但这似乎并不奏效。这可能吗?
我有一些东西在设置。py,我想能够从模板访问,但我不知道如何做到这一点。我已经试过了
{{CONSTANT_NAME}}
但这似乎并不奏效。这可能吗?
当前回答
If we were to compare context vs. template tags on a single variable, then knowing the more efficient option could be benificial. However, you might be better off to dip into the settings only from templates that need that variable. In that case it doesn't make sense to pass the variable into all templates. But if you are sending the variable into a common template such as the base.html template, Then it would not matter as the base.html template is rendered on every request, so you can use either methods.
如果您决定使用template tags选项,那么使用下面的代码,因为它允许您传入一个默认值,以防有问题的变量未定义。
例如:get_from_settings my_variable as my_context_value
例如:get_from_settings my_variable my_default as my_context_value
class SettingsAttrNode(Node):
def __init__(self, variable, default, as_value):
self.variable = getattr(settings, variable, default)
self.cxtname = as_value
def render(self, context):
context[self.cxtname] = self.variable
return ''
def get_from_setting(parser, token):
as_value = variable = default = ''
bits = token.contents.split()
if len(bits) == 4 and bits[2] == 'as':
variable = bits[1]
as_value = bits[3]
elif len(bits) == 5 and bits[3] == 'as':
variable = bits[1]
default = bits[2]
as_value = bits[4]
else:
raise TemplateSyntaxError, "usage: get_from_settings variable default as value " \
"OR: get_from_settings variable as value"
return SettingsAttrNode(variable=variable, default=default, as_value=as_value)
get_from_setting = register.tag(get_from_setting)
其他回答
IanSR和bchhun都建议在设置中覆盖TEMPLATE_CONTEXT_PROCESSORS。请注意,这个设置有一个默认值,如果在不重新设置默认值的情况下重写它,可能会导致一些问题。在最近的Django版本中,默认值也发生了变化。
https://docs.djangoproject.com/en/1.3/ref/settings/#template-context-processors
默认的TEMPLATE_CONTEXT_PROCESSORS:
TEMPLATE_CONTEXT_PROCESSORS = ("django.contrib.auth.context_processors.auth",
"django.core.context_processors.debug",
"django.core.context_processors.i18n",
"django.core.context_processors.media",
"django.core.context_processors.static",
"django.contrib.messages.context_processors.messages")
另一种方法是创建一个自定义模板标签,它可以让您从设置中获取值。
@register.tag
def value_from_settings(parser, token):
try:
# split_contents() knows not to split quoted strings.
tag_name, var = token.split_contents()
except ValueError:
raise template.TemplateSyntaxError, "%r tag requires a single argument" % token.contents.split()[0]
return ValueFromSettings(var)
class ValueFromSettings(template.Node):
def __init__(self, var):
self.arg = template.Variable(var)
def render(self, context):
return settings.__getattr__(str(self.arg))
然后你可以使用:
{% value_from_settings "FQDN" %}
将它打印在任何页面上,而无需跳过上下文处理器的约束。
一个更完整的实现。
/项目/ settings.py
APP_NAME = 'APP'
- app - templatetags settings_value . py
from django import template
from django.conf import settings
register = template.Library()
@register.simple_tag
def settings_value(name):
return getattr(settings, name, "")
/app/templates/index.html
<!DOCTYPE html>
{% load static %}
{% load settings_value %}
<head>
<title>{% settings_value "APP_NAME" %}</title>
...
上面来自bchhun的例子很好,只是你需要从settings.py显式地构建上下文字典。下面是一个未经测试的示例,说明如何从settings.py的所有大写属性(re: "^[A-Z0-9_]+$")自动构建上下文字典。
在settings.py的末尾:
_context = {}
local_context = locals()
for (k,v) in local_context.items():
if re.search('^[A-Z0-9_]+$',k):
_context[k] = str(v)
def settings_context(context):
return _context
TEMPLATE_CONTEXT_PROCESSORS = (
...
'myproject.settings.settings_context',
...
)
我发现这是Django 1.3最简单的方法:
views.py 从local_settings导入BASE_URL def根(请求): 返回render_to_response('hero.html', {'BASE_URL': BASE_URL}) hero.html var BASE_URL = '{{JS_BASE_URL}}';