如果你把你的常规表达式定义为一个字符串,那么所有的背影都必须逃脱,所以而不是“\w”你应该有“\w”。

否则,将其定义为常规表达式:

var pattern = /^\w+@[a-zA-Z_]+?\.[a-zA-Z]{2,3}$/; 

我稍微修改了Jaymon的答案,对于那些想要真正简单的验证的人来说:

anystring@anystring.anystring

常规表达:

/^\S+@\S+\.\S+$/

防止多种 @ 标志相匹配:

/^[^\s@]+@[^\s@]+\.[^\s@]+$/

上面的序列匹配整个序列,删除领先和 ^ 并追踪 $ 如果你想匹配在序列中的任何地方。

如果你想匹配整个字符串,你可能想先切割()字符串。

示例 JavaScript 功能:

函数验证电子邮件(电子邮件) { var re = /\S+@\S+\.\S+/; return re.test(电子邮件); } console.log(验证电子邮件(我的电子邮件是 anystring@anystring.any')); // true console.log(验证电子邮件(我的电子邮件是 anystring@anystring.any')); // false

<pre>
**The personal_info part contains the following ASCII characters.
1.Uppercase (A-Z) and lowercase (a-z) English letters.
2.Digits (0-9).
3.Characters ! # $ % & ' * + - / = ? ^ _ ` { | } ~
4.Character . ( period, dot or fullstop) provided that it is not the first or last character and it will not come one after the other.**
</pre>
*Example of valid email id*
<pre>
yoursite@ourearth.com
my.ownsite@ourearth.org
mysite@you.me.net
xxxx@gmail.com
xxxxxx@yahoo.com
</pre>
<pre>
xxxx.ourearth.com [@ is not present] 
xxxx@.com.my [ tld (Top Level domain) can not start with dot "." ]
@you.me.net [ No character before @ ]
xxxx123@gmail.b [ ".b" is not a valid tld ]
xxxx@.org.org [ tld can not start with dot "." ]
.xxxx@mysite.org [ an email should not be start with "." ]
xxxxx()*@gmail.com [ here the regular expression only allows character, digit, underscore and dash ]
xxxx..1234@yahoo.com [double dots are not allowed
</pre>
**javascript mail code**

    function ValidateEmail(inputText)
    {
    var mailformat = /^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$/;
    if(inputText.value.match(mailformat))
    {
    document.form1.text1.focus();
    return true;
    }
    else
    {
    alert("You have entered an invalid email address!");
    document.form1.text1.focus();
    return false;
    }
    }

通用电子邮件 regex (RFC 5322 官方标准): https://emailregex.com/

JavaScript 的内容:

/^(([^<>()\[\]\\.,;:\s@"]+(\.[^<>()\[\]\\.,;:\s@"]+)*)|(".+"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/

Sectrean的解决方案工作得很好,但它失败了我的镜头,所以我添加了一些漏洞:

function validateEmail(email){ 
     var re = /^(([^<>()[]\\.,;:\s@\"]+(\.[^<>()[]\\.,;:\s@\"]+)*)|(\".+\"))@(([[0-9]{1,3}\‌​.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/; 
     return re.test(email); 
}

与平板相反,这里是一个复杂的解决方案,但它在正确验证电子邮件方面做出了很好的工作:

function isEmail(email) { 
    return /^((([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+(\.([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+)*)|((\x22)((((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(([\x01-\x08\x0b\x0c\x0e-\x1f\x7f]|\x21|[\x23-\x5b]|[\x5d-\x7e]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(\\([\x01-\x09\x0b\x0c\x0d-\x7f]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF]))))*(((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(\x22)))@((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))$/i.test(email);
} 

使用如下:

if (isEmail('youremail@yourdomain.com')){ console.log('This is email is valid'); }