如何迭代由空格分隔的单词组成的字符串中的单词?
注意,我对C字符串函数或那种字符操作/访问不感兴趣。比起效率,我更喜欢优雅。我当前的解决方案:
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
int main() {
string s = "Somewhere down the road";
istringstream iss(s);
do {
string subs;
iss >> subs;
cout << "Substring: " << subs << endl;
} while (iss);
}
如果您喜欢使用boost,但希望使用整个字符串作为分隔符(而不是之前提出的大多数解决方案中的单个字符),可以使用boost_split_iterator。
示例代码包括方便的模板:
#include <iostream>
#include <vector>
#include <boost/algorithm/string.hpp>
template<typename _OutputIterator>
inline void split(
const std::string& str,
const std::string& delim,
_OutputIterator result)
{
using namespace boost::algorithm;
typedef split_iterator<std::string::const_iterator> It;
for(It iter=make_split_iterator(str, first_finder(delim, is_equal()));
iter!=It();
++iter)
{
*(result++) = boost::copy_range<std::string>(*iter);
}
}
int main(int argc, char* argv[])
{
using namespace std;
vector<string> splitted;
split("HelloFOOworldFOO!", "FOO", back_inserter(splitted));
// or directly to console, for example
split("HelloFOOworldFOO!", "FOO", ostream_iterator<string>(cout, "\n"));
return 0;
}
这里有一个拆分函数:
是通用的使用标准C++(无增强)接受多个分隔符忽略空标记(可以轻松更改)模板<typename T>矢量<T>拆分(常量T&str,常量T&分隔符){向量<T>v;typename T::size_type start=0;自动位置=str.find_first_of(分隔符,开始);而(pos!=T::npos){if(pos!=开始)//忽略空标记v.template_back(str,start,pos-start);开始=位置+1;pos=str.find_first_of(分隔符,开始);}if(start<str.length())//忽略尾随分隔符v.template_back(str,start,str.length()-start);//添加字符串的剩余部分返回v;}
示例用法:
vector<string> v = split<string>("Hello, there; World", ";,");
vector<wstring> v = split<wstring>(L"Hello, there; World", L";,");
另一种灵活快速的方式
template<typename Operator>
void tokenize(Operator& op, const char* input, const char* delimiters) {
const char* s = input;
const char* e = s;
while (*e != 0) {
e = s;
while (*e != 0 && strchr(delimiters, *e) == 0) ++e;
if (e - s > 0) {
op(s, e - s);
}
s = e + 1;
}
}
要将其与字符串向量一起使用(编辑:由于有人指出不继承STL类…hrmf;):
template<class ContainerType>
class Appender {
public:
Appender(ContainerType& container) : container_(container) {;}
void operator() (const char* s, unsigned length) {
container_.push_back(std::string(s,length));
}
private:
ContainerType& container_;
};
std::vector<std::string> strVector;
Appender v(strVector);
tokenize(v, "A number of words to be tokenized", " \t");
就是这样!这只是使用tokenizer的一种方式,比如如何计数单词:
class WordCounter {
public:
WordCounter() : noOfWords(0) {}
void operator() (const char*, unsigned) {
++noOfWords;
}
unsigned noOfWords;
};
WordCounter wc;
tokenize(wc, "A number of words to be counted", " \t");
ASSERT( wc.noOfWords == 7 );
受限于想象力;)
我刚刚写了一个很好的例子,说明如何按符号拆分一个字符,然后将每个字符数组(由符号分隔的单词)放入一个向量中。为了简单起见,我创建了std字符串的向量类型。
我希望这对你有帮助,并且对你可读。
#include <vector>
#include <string>
#include <iostream>
void push(std::vector<std::string> &WORDS, std::string &TMP){
WORDS.push_back(TMP);
TMP = "";
}
std::vector<std::string> mySplit(char STRING[]){
std::vector<std::string> words;
std::string s;
for(unsigned short i = 0; i < strlen(STRING); i++){
if(STRING[i] != ' '){
s += STRING[i];
}else{
push(words, s);
}
}
push(words, s);//Used to get last split
return words;
}
int main(){
char string[] = "My awesome string.";
std::cout << mySplit(string)[2];
std::cin.get();
return 0;
}