这是astorije的答案的修改版本，更好地支持负值舍入。

// https://stackoverflow.com/a/21323513/384884
// Modified answer from astorije
function round(value, precision) {
    // Ensure precision exists
    if (typeof precision === "undefined" || +precision === 0) {
        // Just do a regular Math.round
        return Math.round(value);
    }

    // Convert the value and precision variables both to numbers
    value = +value;
    precision = +precision;

    // Ensure the value is a number and that precision is usable
    if (isNaN(value) || !(typeof precision === "number" && precision % 1 === 0)) {
        // Return NaN
        return NaN;
    }

    // Get the sign of value
    var signValue = Math.sign(value);

    // Get the absolute value of value
    value = Math.abs(value);

    // Shift
    value = value.toString().split("e");
    value = Math.round(+(value[0] + "e" + (value[1] ? (+value[1] + precision) : precision)));

    // Shift back
    value = value.toString().split("e");
    value = +(value[0] + "e" + (value[1] ? (+value[1] - precision) : -precision));

    // Apply the sign
    value = value * signValue;

    // Return rounded value
    return value;
}

这是我解决这个问题的方法：

function roundNumber(number, precision = 0) {
    var num = number.toString().replace(",", "");
    var integer, decimal, significantDigit;

    if (num.indexOf(".") > 0 && num.substring(num.indexOf(".") + 1).length > precision && precision > 0) {
        integer = parseInt(num).toString();
        decimal = num.substring(num.indexOf(".") + 1);
        significantDigit = Number(decimal.substr(precision, 1));

        if (significantDigit >= 5) {
            decimal = (Number(decimal.substr(0, precision)) + 1).toString();
            return integer + "." + decimal;
        } else {
            decimal = (Number(decimal.substr(0, precision)) + 1).toString();
            return integer + "." + decimal;
        }
    }
    else if (num.indexOf(".") > 0) {
        integer = parseInt(num).toString();
        decimal = num.substring(num.indexOf(".") + 1);
        significantDigit = num.substring(num.length - 1, 1);

        if (significantDigit >= 5) {
            decimal = (Number(decimal) + 1).toString();
            return integer + "." + decimal;
        } else {
            return integer + "." + decimal;
        }
    }

    return number;
}

所有浏览器和精度的通用答案：

function round(num, places) {
    if(!places) {
        return Math.round(num);
    }

    var val = Math.pow(10, places);
    return Math.round(num * val) / val;
}

round(num, 2);

使用Math.rround（）：

Math.round(num * 100) / 100

或者更具体地说，为了确保1.005这样的数字正确，请使用Number.EPSILON：

Math.round((num + Number.EPSILON) * 100) / 100

MarkG的答案是正确的。这里是任何小数位数的通用扩展。

Number.prototype.round = function(places) {
  return +(Math.round(this + "e+" + places)  + "e-" + places);
}

用法：

var n = 1.7777;    
n.round(2); // 1.78

单元测试：

it.only('should round floats to 2 places', function() {
    
  var cases = [
    { n: 10,      e: 10,    p:2 },
    { n: 1.7777,  e: 1.78,  p:2 },
    { n: 1.005,   e: 1.01,  p:2 },
    { n: 1.005,   e: 1,     p:0 },
    { n: 1.77777, e: 1.8,   p:1 }
  ]
    
  cases.forEach(function(testCase) {
    var r = testCase.n.round(testCase.p);
    assert.equal(r, testCase.e, 'didn\'t get right number');
  });
})

这可能会帮助您：

var result = Math.round(input*100)/100;

有关更多信息，您可以查看Math.round（num）vs num.toFixed（0）和浏览器不一致性