我试图在PHP中创建一个随机字符串,我得到绝对没有输出:

<?php
    function RandomString()
    {
        $characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
        $randstring = '';
        for ($i = 0; $i < 10; $i++) {
            $randstring = $characters[rand(0, strlen($characters))];
        }
        return $randstring;
    }

    RandomString();
    echo $randstring;

我做错了什么?


当前回答

$t = array_merge(range('0', '9'), range('a', 'z'), range('A', 'Z'));
echo join('', array_map(function() use($t) { return $t[array_rand($t)]; }, range(1, 15)));

或一行程序

echo join('', array_map(function() { return substr('0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ', rand(0, 61), 1); }, range(1, 15)));

其他回答

function getRandomString($length) {
  $salt = array_merge(range('a', 'z'), range(0, 9));
  $maxIndex = count($salt) - 1;

  $result = '';
  for ($i = 0; $i < $length; $i++) {
    $index = mt_rand(0, $maxIndex);
    $result .= $salt[$index];
  }
  return $result
}

一条线的解决方案是

str_shuffle(base64_encode(date('mdyhis').date('mdyhis')));

这是另一个解决方案。

function genRandomString($length = 10)
{
    if($length < 1)
        $length = 1;
    return substr(preg_replace("/[^A-Za-z0-9]/", '', base64_encode(openssl_random_pseudo_bytes($length * 2))), 0, $length);
}

PS.我在Ubuntu上使用PHP 7.2。

function rndStr($len = 64) {
     $randomData = file_get_contents('/dev/urandom', false, null, 0, $len) . uniqid(mt_rand(), true);
     $str = substr(str_replace(array('/','=','+'),'', base64_encode($randomData)),0,$len);
    return $str;
}

在PHP中生成随机字符串的另一种方法是:

function RandomString($length) {
    $original_string = array_merge(range(0,9), range('a','z'), range('A', 'Z'));
    $original_string = implode("", $original_string);
    return substr(str_shuffle($original_string), 0, $length);
}
echo RandomString(6);