如果您在用户可能看到或使用它的地方使用这个随机字符串(例如作为密码生成器)，您可能希望限制用于排除元音的字符集。这样你就不会不小心说脏话，也不会冒犯别人。别笑，这是常有的事。

Laravel 5框架中的辅助函数

/**
 * Generate a "random" alpha-numeric string.
 *
 * Should not be considered sufficient for cryptography, etc.
 *
 * @param  int  $length
 * @return string
 */
function str_random($length = 16)
{
    $pool = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';

    return substr(str_shuffle(str_repeat($pool, $length)), 0, $length);
}

一条线的解决方案是

str_shuffle(base64_encode(date('mdyhis').date('mdyhis')));

一个完整的解决方案(课程加测试)，部分基于上面的一些建议…

class TokenFactory
{
    private const LENGTH = 12;
    private const ALLOWED = '123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNPQRSTUVWXYZ~!@#$%^&*{}';
    private const MIN_NUMBER_OF_DIGITS = 1;
    private const MIN_NUMBER_OF_CAPS = 1;
    private const MIN_NUMBER_OF_SPECIALS = 1;
    private const MIN_NUMBER_OF_LETTERS = 1;

    /**
     * @return string
     * @throws \Exception
     */
    public function make(): string
    {
        $pass = $this->generateToken();

        if ($this->isTokenValid($pass)) {
            return $pass;
        } else {
            return $this->make();
        }
    }

    /**
     * @return string
     * @throws \Exception
     */
    private function generateToken(): string
    {
        $allowedCharacters = self::ALLOWED;
        $token              = '';
        $max               = mb_strlen($allowedCharacters, '8bit') - 1;
        for ($i = 0; $i < self::LENGTH; ++$i) {
            $token .= $allowedCharacters[random_int(0, $max)];
        }
        return $token;
    }

    /**
     * @param $token
     * @return bool
     */
    private function isTokenValid($token): bool
    {
        $numberOfDigits   = preg_match_all("/[0-9]/", $token);
        $numberOfCaps     = preg_match_all("/[A-Z]/", $token);
        $numberOfSpecials = preg_match_all("/[~!@#\$%^&*{}]/", $token);
        $numberOfLetters  = preg_match_all("/[a-z]/", $token);

        return
            $numberOfDigits > self::MIN_NUMBER_OF_DIGITS
            && $numberOfCaps > self::MIN_NUMBER_OF_CAPS
            && $numberOfSpecials > self::MIN_NUMBER_OF_SPECIALS
            && $numberOfLetters > self::MIN_NUMBER_OF_LETTERS
            ;
    }
}

class TokenFactoryTest
{
    public function test_correct_syntax()
    {
        /**
         * Arrange
         */
        $length = 12;
        $numberOfChecks = 1000;

        /**
         * Act & Assert
         */
        $class = new TokenFactory();

        $i = 0;
        while ($i < $numberOfChecks) {
            $generatedToken = $class->make();

            $numberOfDigits = preg_match_all( "/[0-9]/", $generatedToken );
            $numberOfCaps = preg_match_all( "/[A-Z]/", $generatedToken );
            $numberOfSpecials   = preg_match_all("/[~!@#\$%^&*{}]/", $generatedToken);
            $numberOfLetters   = preg_match_all("/[a-z]/", $generatedToken);

            Assert::assertEquals($length, strlen($generatedToken));
            Assert::assertTrue($numberOfDigits >= 1, 'Digit error: ' . $generatedToken);
            Assert::assertTrue($numberOfCaps >= 1, 'Caps error: ' . $generatedToken);
            Assert::assertTrue($numberOfSpecials >= 1, 'Specials error: ' . $generatedToken);
            Assert::assertTrue($numberOfLetters >= 1, 'Letters error: ' . $generatedToken);

            $i++;
        }
    }
}

顺便说一句，请确保在适合您需要的地方捕获该异常!

我想要特定字符和预设长度的伪随机字符串。我希望当前版本的PHP具有最高质量的伪随机性，此时它可以是v5、v6、v7或v8，并且可以使用默认配置或特殊配置。为了解决这种混乱，我在这里选取了其他几个答案，并包含了函数可用性条件。

使用。要全局使用它，给$VALID_ID_CHARS赋值你想要的字符，然后调用它:

$VALID_ID_CHARS = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
$myNewRandomId = makeId(6);

function makeId($desiredLen)
{
    global $VALID_ID_CHARS;
    if ($desiredLen < 1) {
        throw new \RangeException("Length must be a positive integer");
    }
    $vLen = 0;
    if (function_exists('mb_strlen')) {
        $vLen = mb_strlen($VALID_ID_CHARS, '8bit') - 1;
    } else {
        $vLen = strlen($VALID_ID_CHARS) - 1;
    }
    if (function_exists('random_int')) {
        $pieces = [];
        for ($i = 0; $i < $desiredLen; ++$i) {
            $pieces[] = $VALID_ID_CHARS[random_int(0, $vLen)];
        }
        return implode('', $pieces);
    }
    if (function_exists('openssl_random_pseudo_bytes')) {
        $random = openssl_random_pseudo_bytes($desiredLen);
        $id = '';
        for ($i = 0; $i < $desiredLen; ++$i) {
            $id .= $VALID_ID_CHARS[ord($random[$i]) % $vLen];
        }
        return $id;
    }
    http_response_code(500);
    die('random id generation failed. either random_int or openssl_random_pseudo_bytes is needed');
}

Laravel解决方案: 如果你正在使用Laravel框架，你可以像这样使用它的StringHelper。

使用“照亮\支持\斯特”;

Str：：random（$strlentgh = 16）