我想出了单行字典排序。

>> a = {2:3, 1:89, 4:5, 3:0}
>> c = {i:a[i] for i in sorted(a.keys())}
>> print(c)
{1: 89, 2: 3, 3: 0, 4: 5}
[Finished in 0.4s]

希望这对你有所帮助。

有一种简单的方法来整理字典。

根据你的问题，

解决方案是:

c={2:3, 1:89, 4:5, 3:0}
y=sorted(c.items())
print y

(其中c是你的字典名。)

这个程序给出如下输出:

[(1, 89), (2, 3), (3, 0), (4, 5)]

如你所愿。

另一个例子是:

d={"John":36,"Lucy":24,"Albert":32,"Peter":18,"Bill":41}
x=sorted(d.keys())
print x

给出输出:['Albert'， 'Bill'， 'John'， 'Lucy'， 'Peter']

y=sorted(d.values())
print y

给出输出:[18,24,32,36,41]

z=sorted(d.items())
print z

给出输出:

[('Albert', 32), ('Bill', 41), ('John', 36), ('Lucy', 24), ('Peter', 18)]

因此，通过将其更改为键、值和项，您可以像您想要的那样打印。希望这能有所帮助!

dictionary = {1:[2],2:[],5:[4,5],4:[5],3:[1]}

temp=sorted(dictionary)
sorted_dict = dict([(k,dictionary[k]) for i,k in enumerate(temp)])

sorted_dict:
         {1: [2], 2: [], 3: [1], 4: [5], 5: [4, 5]}

from operator import itemgetter
# if you would like to play with multiple dictionaries then here you go:
# Three dictionaries that are composed of first name and last name.
user = [
    {'fname': 'Mo', 'lname': 'Mahjoub'},
    {'fname': 'Abdo', 'lname': 'Al-hebashi'},
    {'fname': 'Ali', 'lname': 'Muhammad'}
]
#  This loop will sort by the first and the last names.
# notice that in a dictionary order doesn't matter. So it could put the first name first or the last name first. 
for k in sorted (user, key=itemgetter ('fname', 'lname')):
    print (k)

# This one will sort by the first name only.
for x in sorted (user, key=itemgetter ('fname')):
    print (x)

2.7中两个方法的时间比较显示它们实际上是相同的:

>>> setup_string = "a = sorted(dict({2:3, 1:89, 4:5, 3:0}).items())"
>>> timeit.timeit(stmt="[(k, val) for k, val in a]", setup=setup_string, number=10000)
0.003599141953657181

>>> setup_string = "from collections import OrderedDict\n"
>>> setup_string += "a = OrderedDict({1:89, 2:3, 3:0, 4:5})\n"
>>> setup_string += "b = a.items()"
>>> timeit.timeit(stmt="[(k, val) for k, val in b]", setup=setup_string, number=10000)
0.003581275490432745 

在这里，我找到了一些最简单的解决方案，使用pprint按键对python字典进行排序。 如。

>>> x = {'a': 10, 'cd': 20, 'b': 30, 'az': 99} 
>>> print x
{'a': 10, 'b': 30, 'az': 99, 'cd': 20}

但是当使用pprint时，它将返回排序后的dict

>>> import pprint 
>>> pprint.pprint(x)
{'a': 10, 'az': 99, 'b': 30, 'cd': 20}