在Python中,是否有一种方法可以通过ICMP来ping服务器,如果服务器响应则返回TRUE,如果没有响应则返回FALSE ?
当前回答
下面是一个使用Python的子进程模块和底层操作系统提供的ping CLI工具的解决方案。在Windows和Linux上测试。支持设置网络超时。不需要根权限(至少在Windows和Linux上)。
import platform
import subprocess
def ping(host, network_timeout=3):
"""Send a ping packet to the specified host, using the system "ping" command."""
args = [
'ping'
]
platform_os = platform.system().lower()
if platform_os == 'windows':
args.extend(['-n', '1'])
args.extend(['-w', str(network_timeout * 1000)])
elif platform_os in ('linux', 'darwin'):
args.extend(['-c', '1'])
args.extend(['-W', str(network_timeout)])
else:
raise NotImplemented('Unsupported OS: {}'.format(platform_os))
args.append(host)
try:
if platform_os == 'windows':
output = subprocess.run(args, check=True, universal_newlines=True).stdout
if output and 'TTL' not in output:
return False
else:
subprocess.run(args, check=True)
return True
except (subprocess.CalledProcessError, subprocess.TimeoutExpired):
return False
其他回答
WINDOWS ONLY -不敢相信没有人破解Win32_PingStatus 使用一个简单的WMI查询,我们可以免费返回一个包含非常详细信息的对象
import wmi
# new WMI object
c = wmi.WMI()
# here is where the ping actually is triggered
x = c.Win32_PingStatus(Address='google.com')
# how big is this thing? - 1 element
print 'length x: ' ,len(x)
#lets look at the object 'WMI Object:\n'
print x
#print out the whole returned object
# only x[0] element has values in it
print '\nPrint Whole Object - can directly reference the field names:\n'
for i in x:
print i
#just a single field in the object - Method 1
print 'Method 1 ( i is actually x[0] ) :'
for i in x:
print 'Response:\t', i.ResponseTime, 'ms'
print 'TTL:\t', i.TimeToLive
#or better yet directly access the field you want
print '\npinged ', x[0].ProtocolAddress, ' and got reply in ', x[0].ResponseTime, 'ms'
样例输出
下面是一个使用Python的子进程模块和底层操作系统提供的ping CLI工具的解决方案。在Windows和Linux上测试。支持设置网络超时。不需要根权限(至少在Windows和Linux上)。
import platform
import subprocess
def ping(host, network_timeout=3):
"""Send a ping packet to the specified host, using the system "ping" command."""
args = [
'ping'
]
platform_os = platform.system().lower()
if platform_os == 'windows':
args.extend(['-n', '1'])
args.extend(['-w', str(network_timeout * 1000)])
elif platform_os in ('linux', 'darwin'):
args.extend(['-c', '1'])
args.extend(['-W', str(network_timeout)])
else:
raise NotImplemented('Unsupported OS: {}'.format(platform_os))
args.append(host)
try:
if platform_os == 'windows':
output = subprocess.run(args, check=True, universal_newlines=True).stdout
if output and 'TTL' not in output:
return False
else:
subprocess.run(args, check=True)
return True
except (subprocess.CalledProcessError, subprocess.TimeoutExpired):
return False
这个脚本适用于Windows,也适用于其他操作系统: 它可以在Windows, Debian和macosx上工作,需要在solaris上测试。
import os
import platform
def isUp(hostname):
giveFeedback = False
if platform.system() == "Windows":
response = os.system("ping "+hostname+" -n 1")
else:
response = os.system("ping -c 1 " + hostname)
isUpBool = False
if response == 0:
if giveFeedback:
print hostname, 'is up!'
isUpBool = True
else:
if giveFeedback:
print hostname, 'is down!'
return isUpBool
print(isUp("example.com")) #Example domain
print(isUp("localhost")) #Your computer
print(isUp("invalid.example.com")) #Unresolvable hostname: https://tools.ietf.org/html/rfc6761
print(isUp("192.168.1.1")) #Pings local router
print(isUp("192.168.1.135")) #Pings a local computer - will differ for your network
使用Multi-ping (pip install multiPing),我做了这个简单的代码(简单地复制和粘贴,如果你愿意!):
from multiping import MultiPing
def ping(host,n = 0):
if(n>0):
avg = 0
for i in range (n):
avg += ping(host)
avg = avg/n
# Create a MultiPing object to test hosts / addresses
mp = MultiPing([host])
# Send the pings to those addresses
mp.send()
# With a 1 second timout, wait for responses (may return sooner if all
# results are received).
responses, no_responses = mp.receive(1)
for addr, rtt in responses.items():
RTT = rtt
if no_responses:
# Sending pings once more, but just to those addresses that have not
# responded, yet.
mp.send()
responses, no_responses = mp.receive(1)
RTT = -1
return RTT
用法:
#Getting the latency average (in seconds) of host '192.168.0.123' using 10 samples
ping('192.168.0.123',10)
如果你想要一个单一的样本,第二个参数“10”可以忽略!
希望能有所帮助!
我需要一个更快的ping扫描,我不想使用任何外部库,所以我决定使用内置的asyncio来实现并发。
此代码需要python 3.7+,仅在Linux上制作和测试。它不能在Windows上工作,但我相信你可以很容易地将其更改为在Windows上工作。
我不是asyncio方面的专家,但我使用了这篇很棒的文章,用并发性加速你的Python程序,我想出了这些代码行。我试图使它尽可能简单,所以很可能您需要添加更多的代码来满足您的需求。
它不会返回true或false,我认为让它打印响应ping请求的IP会更方便。我认为这是相当快的,在近10秒内ping 255个ip。
#!/usr/bin/python3
import asyncio
async def ping(host):
"""
Prints the hosts that respond to ping request
"""
ping_process = await asyncio.create_subprocess_shell("ping -c 1 " + host + " > /dev/null 2>&1")
await ping_process.wait()
if ping_process.returncode == 0:
print(host)
return
async def ping_all():
tasks = []
for i in range(1,255):
ip = "192.168.1.{}".format(i)
task = asyncio.ensure_future(ping(ip))
tasks.append(task)
await asyncio.gather(*tasks, return_exceptions = True)
asyncio.run(ping_all())
样例输出:
192.168.1.1
192.168.1.3
192.168.1.102
192.168.1.106
192.168.1.6
请注意,IP不是按顺序排列的,因为IP在它响应时就会打印出来,所以先响应的就会先打印出来。
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