在Python中,是否有一种方法可以通过ICMP来ping服务器,如果服务器响应则返回TRUE,如果没有响应则返回FALSE ?


当前回答

因为我喜欢让我的Python程序在2.7和3版本上通用。在Linux, Mac OS和Windows平台上,我必须修改现有的示例。

# shebang does not work over all platforms
# ping.py  2016-02-25 Rudolf
# subprocess.call() is preferred to os.system()
# works under Python 2.7 and 3.4
# works under Linux, Mac OS, Windows

def ping(host):
    """
    Returns True if host responds to a ping request
    """
    import subprocess, platform

    # Ping parameters as function of OS
    ping_str = "-n 1" if  platform.system().lower()=="windows" else "-c 1"
    args = "ping " + " " + ping_str + " " + host
    need_sh = False if  platform.system().lower()=="windows" else True

    # Ping
    return subprocess.call(args, shell=need_sh) == 0

# test call
print(ping("192.168.17.142"))

其他回答

我的解决方法是:

def ping(self, host):
    res = False

    ping_param = "-n 1" if system_name().lower() == "windows" else "-c 1"

    resultado = os.popen("ping " + ping_param + " " + host).read()

    if "TTL=" in resultado:
        res = True
    return res

“TTL”是判断ping是否正确的方法。 Saludos

在windows或linux中Ping它们,返回一个排序的列表。这是@Ahmed Essam和@Arno回复的混合/修正。

import asyncio
import re

import platform
isWindows = platform.system()


async def ping(host):
    cmd = 'ping {} {} 1'.format(host, '-n' if isWindows else '-c')
    ping_proc = \
        await asyncio.create_subprocess_shell(cmd, stdout=asyncio.subprocess.PIPE,
                                                      stderr=asyncio.subprocess.PIPE)
    stdout, stderr = await ping_proc.communicate()
    outstr = stdout.decode()

    if ping_proc.returncode == 0:
        delay = int(re.search(r'(?:time=)([\d]*)', outstr).group(1)) if 'time=' in outstr else -1
        if delay >= 0:
            # print('{} {}ms'.format(host, delay))
            return [host, delay]

    return [host, None]


async def ping_all():
    tasks = []

    for i in range(1, 256):
        ip = "192.168.1.{}".format(i)
        task = asyncio.ensure_future(ping(ip))
        tasks.append(task)

    retList = await asyncio.gather(*tasks, return_exceptions=True)
    retList = [x for x in retList if x[1] is not None]
    retList.sort(key=lambda x: int(x[0].split('.')[-1]))

    return retList


loop = asyncio.ProactorEventLoop()
asyncio.set_event_loop(loop)
pingRet = loop.run_until_complete(ping_all())

for ip, d in pingRet:
    print('{:<16s} {}ms'.format(ip, d))

我使用这篇文章中回答的想法,但只使用更新的推荐子进程模块和python3:

import subprocess
import platform

operating_sys = platform.system()
nas = '192.168.0.10'

def ping(ip):
    # ping_command = ['ping', ip, '-n', '1'] instead of ping_command = ['ping', ip, '-n 1'] for Windows
    ping_command = ['ping', ip, '-n', '1'] if operating_sys == 'Windows' else ['ping', ip, '-c 1']
    shell_needed = True if operating_sys == 'Windows' else False

    ping_output = subprocess.run(ping_command,shell=shell_needed,stdout=subprocess.PIPE)
    success = ping_output.returncode
    return True if success == 0 else False

out = ping(nas)
print(out)

确保安装了pyping或安装它

#!/usr/bin/python
import pyping

response = pyping.ping('Your IP')

if response.ret_code == 0:
    print("reachable")
else:
    print("unreachable")

此函数适用于任何操作系统(Unix、Linux、macOS和Windows) Python 2和Python 3

编辑: @radato os。System被subprocess.call取代。这避免了在没有验证主机名字符串的情况下shell注入漏洞。

import platform    # For getting the operating system name
import subprocess  # For executing a shell command

def ping(host):
    """
    Returns True if host (str) responds to a ping request.
    Remember that a host may not respond to a ping (ICMP) request even if the host name is valid.
    """

    # Option for the number of packets as a function of
    param = '-n' if platform.system().lower()=='windows' else '-c'

    # Building the command. Ex: "ping -c 1 google.com"
    command = ['ping', param, '1', host]

    return subprocess.call(command) == 0

注意,根据Windows上的@ikrase,如果你得到一个目标主机不可达错误,这个函数仍然会返回True。

解释

该命令在Windows和类unix系统中都是ping。 选项-n (Windows)或-c (Unix)控制包的数量,在本例中设置为1。

platform.system()返回平台名称。前女友。macOS上的“达尔文”。 Subprocess.call()执行一个系统调用。例如subprocess.call ([' ls ', ' - l '])。