下面是我简单的破解/变通方法…不是最全面的，但很容易修改，比我在写这篇文章之前找到的任何其他答案都更容易阅读和理解:

import logging
import multiprocessing

class FakeLogger(object):
    def __init__(self, q):
        self.q = q
    def info(self, item):
        self.q.put('INFO - {}'.format(item))
    def debug(self, item):
        self.q.put('DEBUG - {}'.format(item))
    def critical(self, item):
        self.q.put('CRITICAL - {}'.format(item))
    def warning(self, item):
        self.q.put('WARNING - {}'.format(item))

def some_other_func_that_gets_logger_and_logs(num):
    # notice the name get's discarded
    # of course you can easily add this to your FakeLogger class
    local_logger = logging.getLogger('local')
    local_logger.info('Hey I am logging this: {} and working on it to make this {}!'.format(num, num*2))
    local_logger.debug('hmm, something may need debugging here')
    return num*2

def func_to_parallelize(data_chunk):
    # unpack our args
    the_num, logger_q = data_chunk
    # since we're now in a new process, let's monkeypatch the logging module
    logging.getLogger = lambda name=None: FakeLogger(logger_q)
    # now do the actual work that happens to log stuff too
    new_num = some_other_func_that_gets_logger_and_logs(the_num)
    return (the_num, new_num)

if __name__ == '__main__':
    multiprocessing.freeze_support()
    m = multiprocessing.Manager()
    logger_q = m.Queue()
    # we have to pass our data to be parallel-processed
    # we also need to pass the Queue object so we can retrieve the logs
    parallelable_data = [(1, logger_q), (2, logger_q)]
    # set up a pool of processes so we can take advantage of multiple CPU cores
    pool_size = multiprocessing.cpu_count() * 2
    pool = multiprocessing.Pool(processes=pool_size, maxtasksperchild=4)
    worker_output = pool.map(func_to_parallelize, parallelable_data)
    pool.close() # no more tasks
    pool.join()  # wrap up current tasks
    # get the contents of our FakeLogger object
    while not logger_q.empty():
        print logger_q.get()
    print 'worker output contained: {}'.format(worker_output)

我有一个解决方案，类似于ironhacker的，除了我使用日志。在我的一些代码中，我发现我需要在将异常传递回队列之前格式化它，因为回溯是不能pickle的:

class QueueHandler(logging.Handler):
    def __init__(self, queue):
        logging.Handler.__init__(self)
        self.queue = queue
    def emit(self, record):
        if record.exc_info:
            # can't pass exc_info across processes so just format now
            record.exc_text = self.formatException(record.exc_info)
            record.exc_info = None
        self.queue.put(record)
    def formatException(self, ei):
        sio = cStringIO.StringIO()
        traceback.print_exception(ei[0], ei[1], ei[2], None, sio)
        s = sio.getvalue()
        sio.close()
        if s[-1] == "\n":
            s = s[:-1]
        return s

然而，另一种选择可能是日志包中各种非基于文件的日志处理程序:

套接字处理程序 数据报处理程序 系统日志处理程序

(和其他人)

通过这种方式，您可以轻松地在某个地方创建一个日志守护进程，以便安全地对其进行写入并正确地处理结果。(例如，一个简单的套接字服务器，它只是解pickle消息并将其发送到自己的旋转文件处理程序。)

SyslogHandler也会为您处理这个问题。当然，您可以使用自己的syslog实例，而不是系统实例。

下面是一个可以在Windows环境下使用的类，需要ActivePython。 您还可以继承其他日志处理程序(StreamHandler等)。

class SyncronizedFileHandler(logging.FileHandler):
    MUTEX_NAME = 'logging_mutex'

    def __init__(self , *args , **kwargs):

        self.mutex = win32event.CreateMutex(None , False , self.MUTEX_NAME)
        return super(SyncronizedFileHandler , self ).__init__(*args , **kwargs)

    def emit(self, *args , **kwargs):
        try:
            win32event.WaitForSingleObject(self.mutex , win32event.INFINITE)
            ret = super(SyncronizedFileHandler , self ).emit(*args , **kwargs)
        finally:
            win32event.ReleaseMutex(self.mutex)
        return ret

下面是一个演示用法的例子:

import logging
import random , time , os , sys , datetime
from string import letters
import win32api , win32event
from multiprocessing import Pool

def f(i):
    time.sleep(random.randint(0,10) * 0.1)
    ch = random.choice(letters)
    logging.info( ch * 30)


def init_logging():
    '''
    initilize the loggers
    '''
    formatter = logging.Formatter("%(levelname)s - %(process)d - %(asctime)s - %(filename)s - %(lineno)d - %(message)s")
    logger = logging.getLogger()
    logger.setLevel(logging.INFO)

    file_handler = SyncronizedFileHandler(sys.argv[1])
    file_handler.setLevel(logging.INFO)
    file_handler.setFormatter(formatter)
    logger.addHandler(file_handler)

#must be called in the parent and in every worker process
init_logging() 

if __name__ == '__main__':
    #multiprocessing stuff
    pool = Pool(processes=10)
    imap_result = pool.imap(f , range(30))
    for i , _ in enumerate(imap_result):
        pass

下面是另一个简单的解决方案，适用于从谷歌到这里的其他人(比如我)。日志记录应该很简单!仅适用于3.2或更高版本。

import multiprocessing
import logging
from logging.handlers import QueueHandler, QueueListener
import time
import random


def f(i):
    time.sleep(random.uniform(.01, .05))
    logging.info('function called with {} in worker thread.'.format(i))
    time.sleep(random.uniform(.01, .05))
    return i


def worker_init(q):
    # all records from worker processes go to qh and then into q
    qh = QueueHandler(q)
    logger = logging.getLogger()
    logger.setLevel(logging.DEBUG)
    logger.addHandler(qh)


def logger_init():
    q = multiprocessing.Queue()
    # this is the handler for all log records
    handler = logging.StreamHandler()
    handler.setFormatter(logging.Formatter("%(levelname)s: %(asctime)s - %(process)s - %(message)s"))

    # ql gets records from the queue and sends them to the handler
    ql = QueueListener(q, handler)
    ql.start()

    logger = logging.getLogger()
    logger.setLevel(logging.DEBUG)
    # add the handler to the logger so records from this process are handled
    logger.addHandler(handler)

    return ql, q


def main():
    q_listener, q = logger_init()

    logging.info('hello from main thread')
    pool = multiprocessing.Pool(4, worker_init, [q])
    for result in pool.map(f, range(10)):
        pass
    pool.close()
    pool.join()
    q_listener.stop()

if __name__ == '__main__':
    main()

如果在日志模块中的锁、线程和fork的组合中出现死锁，则在错误报告6721中报告(另见相关SO问题)。

有一个小的解决方案张贴在这里。

但是，这只会修复日志记录中任何潜在的死锁。这并不能解决问题，事情可能会变得混乱。请参阅此处提供的其他答案。