我有一个网络调用要执行。但在此之前,我需要检查设备是否有互联网连接。

这是我目前为止所做的:

  var connectivityResult = new Connectivity().checkConnectivity();// User defined class
    if (connectivityResult == ConnectivityResult.mobile ||
        connectivityResult == ConnectivityResult.wifi) {*/
    this.getData();
    } else {
      neverSatisfied();
    }

上述方法行不通。


当前回答

基于这个答案https://stackoverflow.com/a/68436867/10761151

如果你使用dart零安全,你会得到一个错误, 因此,您可以将依赖项data_connection_checker: ^0.3.4更新为internet_connection_checker: ^0.0.1+2

你可以用这个代码

import 'dart:async';
import 'package:connectivity_plus/connectivity_plus.dart';
import 'package:internet_connection_checker/internet_connection_checker.dart';

class ConnectionUtil {
  static final ConnectionUtil _singleton = new ConnectionUtil._internal();
  ConnectionUtil._internal();

  static ConnectionUtil getInstance() => _singleton;

  bool hasConnection = false;

  StreamController connectionChangeController = StreamController();

  final Connectivity _connectivity = Connectivity();
  void initialize() {
    _connectivity.onConnectivityChanged.listen(_connectionChange);
  }

  void _connectionChange(ConnectivityResult result) {
    _hasInternetInternetConnection();
  }

  Stream get connectionChange => connectionChangeController.stream;
  Future<bool> _hasInternetInternetConnection() async {
    bool previousConnection = hasConnection;
    var connectivityResult = await (Connectivity().checkConnectivity());
    if (connectivityResult == ConnectivityResult.mobile || connectivityResult == ConnectivityResult.wifi) {
      // this is the different
      if (await InternetConnectionChecker().hasConnection) {
        hasConnection = true;
      } else {
        hasConnection = false;
      }
    } else {
      hasConnection = false;
    }

    if (previousConnection != hasConnection) {
      connectionChangeController.add(hasConnection);
    }
    return hasConnection;
  }
}

在有状态小部件上可以实现此代码

  bool hasInterNetConnection = false;

  @override
  initState() {
    ConnectionUtil connectionStatus = ConnectionUtil.getInstance();
    connectionStatus.initialize();
    connectionStatus.connectionChange.listen(connectionChanged);

    super.initState();
  }

  void connectionChanged(dynamic hasConnection) {
    setState(() {
      hasInterNetConnection = hasConnection;
    });
  }

其他回答

迟答,但用这个包来检查。 包名:data_connection_checker

在你的酒吧里。yuml文件:

dependencies:
    data_connection_checker: ^0.3.4

创建一个名为connection的文件。达特,随便你叫什么都行。 导入包:

import 'package:data_connection_checker/data_connection_checker.dart';

检查是否有网络连接:

print(await DataConnectionChecker().hasConnection);

使用

dependencies:
  connectivity: ^0.4.2

我们从资源处得到的是

      import 'package:connectivity/connectivity.dart';

      Future<bool> check() async {
        var connectivityResult = await (Connectivity().checkConnectivity());
        if (connectivityResult == ConnectivityResult.mobile) {
          return true;
        } else if (connectivityResult == ConnectivityResult.wifi) {
          return true;
        }
        return false;
      }

未来对我来说没什么问题,我们必须每次都实现它,比如:

check().then((intenet) {
      if (intenet != null && intenet) {
        // Internet Present Case
      }
      // No-Internet Case
    });

所以为了解决这个问题,我创建了一个类,它接受一个布尔isNetworkPresent参数的函数,就像这样

methodName(bool isNetworkPresent){}

实用工具类是

import 'package:connectivity/connectivity.dart'; class NetworkCheck { Future<bool> check() async { var connectivityResult = await (Connectivity().checkConnectivity()); if (connectivityResult == ConnectivityResult.mobile) { return true; } else if (connectivityResult == ConnectivityResult.wifi) { return true; } return false; } dynamic checkInternet(Function func) { check().then((intenet) { if (intenet != null && intenet) { func(true); } else{ func(false); } }); } }

并使用连接检查实用程序

  fetchPrefrence(bool isNetworkPresent) {
    if(isNetworkPresent){

    }else{

    }
  }

我将使用这种语法

NetworkCheck networkCheck = new NetworkCheck();
networkCheck.checkInternet(fetchPrefrence)

对于登陆这里的其他人,我想添加到Günter Zöchbauer的答案,这是我实现一个实用程序的解决方案,以知道是否有互联网,而不管其他任何事情。

免责声明:

我对Dart和Flutter都是新手,所以这可能不是最好的方法,但很想得到反馈。


结合flutter_connectivity和Günter Zöchbauer的连接测试

我的需求

我不希望在需要检查连接的任何地方出现一堆重复的代码,我希望它在发生变化时自动更新组件或其他与连接相关的东西。

ConnectionStatusSingleton

首先我们设置一个Singleton。如果你不熟悉这种模式,网上有很多关于它们的好信息。但要点在于,您希望在应用程序生命周期中创建类的单个实例,并且能够在任何地方使用它。

这个单例连接到flutter_connectivity并监听连接性更改,然后测试网络连接,然后使用StreamController更新任何关心的内容。

它是这样的:

import 'dart:io'; //InternetAddress utility
import 'dart:async'; //For StreamController/Stream

import 'package:connectivity/connectivity.dart';

class ConnectionStatusSingleton {
    //This creates the single instance by calling the `_internal` constructor specified below
    static final ConnectionStatusSingleton _singleton = new ConnectionStatusSingleton._internal();
    ConnectionStatusSingleton._internal();

    //This is what's used to retrieve the instance through the app
    static ConnectionStatusSingleton getInstance() => _singleton;

    //This tracks the current connection status
    bool hasConnection = false;

    //This is how we'll allow subscribing to connection changes
    StreamController connectionChangeController = new StreamController.broadcast();

    //flutter_connectivity
    final Connectivity _connectivity = Connectivity();

    //Hook into flutter_connectivity's Stream to listen for changes
    //And check the connection status out of the gate
    void initialize() {
        _connectivity.onConnectivityChanged.listen(_connectionChange);
        checkConnection();
    }

    Stream get connectionChange => connectionChangeController.stream;

    //A clean up method to close our StreamController
    //   Because this is meant to exist through the entire application life cycle this isn't
    //   really an issue
    void dispose() {
        connectionChangeController.close();
    }

    //flutter_connectivity's listener
    void _connectionChange(ConnectivityResult result) {
        checkConnection();
    }

    //The test to actually see if there is a connection
    Future<bool> checkConnection() async {
        bool previousConnection = hasConnection;

        try {
            final result = await InternetAddress.lookup('google.com');
            if (result.isNotEmpty && result[0].rawAddress.isNotEmpty) {
                hasConnection = true;
            } else {
                hasConnection = false;
            }
        } on SocketException catch(_) {
            hasConnection = false;
        }

        //The connection status changed send out an update to all listeners
        if (previousConnection != hasConnection) {
            connectionChangeController.add(hasConnection);
        }

        return hasConnection;
    }
}

使用

初始化

首先,我们必须确保调用了我们单例的initialize。但只有一次。 这部分取决于你,但我在我的应用程序的main():

void main() {
    ConnectionStatusSingleton connectionStatus = ConnectionStatusSingleton.getInstance();
    connectionStatus.initialize();

    runApp(MyApp());

    //Call this if initialization is occuring in a scope that will end during app lifecycle
    //connectionStatus.dispose();   
}

在Widget或其他地方

import 'dart:async'; //For StreamSubscription

...

class MyWidgetState extends State<MyWidget> {
    StreamSubscription _connectionChangeStream;

    bool isOffline = false;

    @override
    initState() {
        super.initState();

        ConnectionStatusSingleton connectionStatus = ConnectionStatusSingleton.getInstance();
        _connectionChangeStream = connectionStatus.connectionChange.listen(connectionChanged);
    }

    void connectionChanged(dynamic hasConnection) {
        setState(() {
            isOffline = !hasConnection;
        });
    }

    @override
    Widget build(BuildContext ctxt) {
        ...
    }
}

希望其他人觉得这有用!


示例github repo: https://github.com/dennmat/flutter-connectiontest-example

在模拟器中切换飞行模式以查看结果

我有一些问题与接受的答案,但似乎它解决了别人的答案。我想要一个解决方案,可以从它使用的url得到响应,所以我认为http将是伟大的功能,为此,我发现这个答案真的很有帮助。如何使用HTTP请求(Flutter/Dart)检查Internet连接?

我写了一个包来检查活跃的互联网连接和显示相应的小部件。

flutter_no_internet_widget

例子:

InternetWidget(
 online: Text('Online'),
 offline: Text('Offline),
);

根据网络状态,将显示适当的小部件。如果您有一个活跃的互联网连接,一个在线小部件将显示。

所有重量级的工作都由包完成,您所要做的就是提供在线和离线小部件。您还可以提供一个加载小部件和查找URL。

欢迎讨论、提交意见书或提出建议。