我有一个网络调用要执行。但在此之前,我需要检查设备是否有互联网连接。
这是我目前为止所做的:
var connectivityResult = new Connectivity().checkConnectivity();// User defined class
if (connectivityResult == ConnectivityResult.mobile ||
connectivityResult == ConnectivityResult.wifi) {*/
this.getData();
} else {
neverSatisfied();
}
上述方法行不通。
import 'dart:async';
import 'dart:io';
import 'package:flutter/material.dart';
import 'package:app_settings/app_settings.dart';
import 'package:connectivity/connectivity.dart';
class InternetConnect extends StatefulWidget {
@override
InternetConnectState createState() => InternetConnectState();
}
class InternetConnectState extends State<InternetConnect> {
ConnectivityResult previous;
bool dialogshown = false;
StreamSubscription connectivitySubscription;
Future<bool> checkinternet() async {
try {
final result = await InternetAddress.lookup('google.com');
if (result.isNotEmpty && result[0].rawAddress.isNotEmpty) {
return Future.value(true);
}
} on SocketException catch (_) {
return Future.value(false);
}
}
void checkInternetConnect(BuildContext context) {
connectivitySubscription = Connectivity()
.onConnectivityChanged
.listen((ConnectivityResult connresult) {
if (connresult == ConnectivityResult.none) {
dialogshown = true;
showDialog(
context: context, barrierDismissible: false, child: alertDialog());
} else if (previous == ConnectivityResult.none) {
checkinternet().then((result) {
if (result == true) {
if (dialogshown == true) {
dialogshown = false;
Navigator.pop(context);
}
}
});
}
previous = connresult;
});
}
AlertDialog alertDialog() {
return AlertDialog(
title: Text('ERROR'),
content: Text("No Internet Detected."),
actions: <Widget>[
FlatButton(
// method to exit application programitacally
onPressed: () {
AppSettings.openWIFISettings();
},
child: Text("Settings"),
),
],
);
}
@override
Widget build(BuildContext context) {
return Container();
}
}
and you can use this method in init of any class
@override
void initState() {
// TODO: implement initState
InternetConnectState().checkInternetConnect(context);
super.initState();
}
使用connectivity_widget: ^0.1.7
添加附件:
dependencies:
connectivity_widget: ^0.1.7
添加代码:
ConnectivityWidget(
builder: (context, isOnline) => Center(
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
Text(
"${isOnline ? 'Connected' : 'Offline'}",
style: TextStyle(
fontSize: 30,
color: isOnline ? Colors.green : Colors.red),
),
],
),
),
)
输出:
在@dennmatt的回答之后,我注意到InternetAddress。查找可能会返回成功的结果,即使互联网连接断开-我测试它从我的模拟器连接到我的家庭WiFi,然后断开我的路由器的电缆。我认为原因是路由器缓存了域查找结果,所以它不必在每个查找请求时查询DNS服务器。
不管怎样,如果你像我一样使用Firestore,你可以用一个空事务替换try-SocketException-catch块并捕获TimeoutExceptions:
try {
await Firestore.instance.runTransaction((Transaction tx) {}).timeout(Duration(seconds: 5));
hasConnection = true;
} on PlatformException catch(_) { // May be thrown on Airplane mode
hasConnection = false;
} on TimeoutException catch(_) {
hasConnection = false;
}
另外,请注意,previousConnection是在async internet -check之前设置的,因此理论上,如果checkConnection()在短时间内被调用多次,那么在一行中可能有多个hasConnection=true或多个hasConnection=false。
我不确定@dennmatt是否故意这样做,但在我们的用例中没有副作用(setState只被调用两次,具有相同的值)。