由于没有一个答案提到即将到来的Ranges库，它从c++ 20开始就在标准库中可用，目前在GitHub上单独可用为range-v3，我想添加一种使用它执行转换的方法。

就地修改字符串:

str |= action::transform([](unsigned char c){ return std::tolower(c); });

生成一个新的字符串:

auto new_string = original_string
    | view::transform([](unsigned char c){ return std::tolower(c); });

(不要忘记#include <cctype>和所需的Ranges头。)

注意:使用unsigned char作为lambda的参数是受cppreference的启发，它声明:

Like all other functions from <cctype>, the behavior of std::tolower is undefined if the argument's value is neither representable as unsigned char nor equal to EOF. To use these functions safely with plain chars (or signed chars), the argument should first be converted to unsigned char: char my_tolower(char ch) { return static_cast<char>(std::tolower(static_cast<unsigned char>(ch))); } Similarly, they should not be directly used with standard algorithms when the iterator's value type is char or signed char. Instead, convert the value to unsigned char first: std::string str_tolower(std::string s) { std::transform(s.begin(), s.end(), s.begin(), // static_cast<int(*)(int)>(std::tolower) // wrong // [](int c){ return std::tolower(c); } // wrong // [](char c){ return std::tolower(c); } // wrong [](unsigned char c){ return std::tolower(c); } // correct ); return s; }

// tolower example (C++)
#include <iostream>       // std::cout
#include <string>         // std::string
#include <locale>         // std::locale, std::tolower

int main ()
{
  std::locale loc;
  std::string str="Test String.\n";
  for (std::string::size_type i=0; i<str.length(); ++i)
    std::cout << std::tolower(str[i],loc);
  return 0;
}

欲了解更多信息:http://www.cplusplus.com/reference/locale/tolower/

代码片段

#include<bits/stdc++.h>
using namespace std;


int main ()
{
    ios::sync_with_stdio(false);

    string str="String Convert\n";

    for(int i=0; i<str.size(); i++)
    {
      str[i] = tolower(str[i]);
    }
    cout<<str<<endl;

    return 0;
}

如果你想要一些简单的东西，这里有一个宏观的技巧:

#define STRTOLOWER(x) std::transform (x.begin(), x.end(), x.begin(), ::tolower)
#define STRTOUPPER(x) std::transform (x.begin(), x.end(), x.begin(), ::toupper)
#define STRTOUCFIRST(x) std::transform (x.begin(), x.begin()+1, x.begin(),  ::toupper); std::transform (x.begin()+1, x.end(),   x.begin()+1,::tolower)

但是，请注意，如果您正在处理的不仅仅是ASCII字符，那么@AndreasSpindler对这个答案的评论仍然是一个重要的考虑因素。

改编自《不常见问题》:

#include <algorithm>
#include <cctype>
#include <string>

std::string data = "Abc";
std::transform(data.begin(), data.end(), data.begin(),
    [](unsigned char c){ return std::tolower(c); });

如果不遍历每个字符，你真的无法逃脱。否则就无法知道字符是小写还是大写。

如果你真的讨厌ower()，这里有一个专门的ascii替代方案，我不建议你使用:

char asciitolower(char in) {
    if (in <= 'Z' && in >= 'A')
        return in - ('Z' - 'z');
    return in;
}

std::transform(data.begin(), data.end(), data.begin(), asciitolower);

请注意，tolower()只能执行单个字节的字符替换，这不适用于许多脚本，特别是在使用UTF-8这样的多字节编码时。

Boost为此提供了一个字符串算法:

#include <boost/algorithm/string.hpp>

std::string str = "HELLO, WORLD!";
boost::algorithm::to_lower(str); // modifies str

或者，对于非原位:

#include <boost/algorithm/string.hpp>

const std::string str = "HELLO, WORLD!";
const std::string lower_str = boost::algorithm::to_lower_copy(str);