使用这个

$users = DB::table('users')
                    ->where('votes', '>', 100)
                    ->orWhere('name', 'John')
                    ->get();

查询作用域可以帮助您提高代码的可读性。

http://laravel.com/docs/eloquent#query-scopes

用一些例子更新这个答案:

在你的模型中，像这样创建作用域方法:

public function scopeActive($query)
{
    return $query->where('active', '=', 1);
}

public function scopeThat($query)
{
    return $query->where('that', '=', 1);
}

然后，你可以在构建查询时调用这个作用域:

$users = User::active()->that()->get();

你可以这样做，这是最短的方法。

    $results = User::where(['this'=>1, 
              'that'=>1, 
               'this_too'=>1, 
               'that_too'=>1, 
              'this_as_well'=>1, 
               'that_as_well'=>1, 
                'this_one_too'=>1, 
               'that_one_too'=>1, 
              'this_one_as_well'=>1,
                'that_one_as_well'=>1])->get();

多个where子句

    $query=DB::table('users')
        ->whereRaw("users.id BETWEEN 1003 AND 1004")
        ->whereNotIn('users.id', [1005,1006,1007])
        ->whereIn('users.id',  [1008,1009,1010]);
    $query->where(function($query2) use ($value)
    {
        $query2->where('user_type', 2)
            ->orWhere('value', $value);
    });

   if ($user == 'admin'){
        $query->where('users.user_name', $user);
    }

终于得到了结果

    $result = $query->get();

使用纯Eloquent，像这样实现它。这段代码返回所有帐户处于活动状态的已登录用户。 $用户= \ App \用户::(“状态”,“积极”)——> (logged_in,真的)- > ();

$variable = array('this' => 1,
                    'that' => 1
                    'that' => 1,
                    'this_too' => 1,
                    'that_too' => 1,
                    'this_as_well' => 1,
                    'that_as_well' => 1,
                    'this_one_too' => 1,
                    'that_one_too' => 1,
                    'this_one_as_well' => 1,
                    'that_one_as_well' => 1);

foreach ($variable as $key => $value) {
    User::where($key, '=', $value);
}