我使用Laravel雄辩的查询构建器,我有一个查询,我想在多个条件上有一个where子句。它能起作用,但并不优雅。

例子:

$results = User::where('this', '=', 1)
    ->where('that', '=', 1)
    ->where('this_too', '=', 1)
    ->where('that_too', '=', 1)
    ->where('this_as_well', '=', 1)
    ->where('that_as_well', '=', 1)
    ->where('this_one_too', '=', 1)
    ->where('that_one_too', '=', 1)
    ->where('this_one_as_well', '=', 1)
    ->where('that_one_as_well', '=', 1)
    ->get();

有没有更好的方法,或者我应该坚持这个方法?


当前回答

Model::where('column_1','=','value_1')
       ->where('column_2 ','=','value_2')
       ->get();

OR

// If you are looking for equal value then no need to add =
Model::where('column_1','value_1')
        ->where('column_2','value_2')
         ->get();

OR

Model::where(['column_1' => 'value_1',
              'column_2' => 'value_2'])->get();

其他回答

多个地方

您还可以将一个条件数组传递给where函数。数组的每个元素都应该是一个数组,包含通常传递给where方法的三个参数:

Model::where([
    ['status', '=', '1'],
    ['subscribed', '<>', '1'],
])->get();

多个或Where子句

如果你需要在圆括号内对"or"条件进行分组,你可以将闭包作为第一个参数传递给orWhere方法:

Model::where('votes', '>', 100)
        ->orWhere(function ($query) {
            $query->where('name', 'abcd')
                ->orWhere(function ($query) {
                    $query->where('name', 'cdef')
                        ->where('votes', '>', 50);
                });
        })
        ->get();

上面的例子将产生以下SQL语句:

select * from `users` where `votes` > 100 or (`name` = "abcd" or (`name` = "cdef" and `votes` > 50));

多指针where with whereNot和orWhereNot方法

whereNot和orWhereNot方法可用于对给定的查询约束组求反。例如,以下查询排除清仓或价格小于10的产品:

$products = Product::where([
        ['status', '=', '1'],
        ['is_feature', '1']
    ])
        ->whereNot(function ($query) {
            $query->where('clearance', true)
                ->orWhere('price', '<', 10);
        })
        ->get();

根据我的建议,如果你正在做筛选或搜索

那么你应该选择:

        $results = User::query();
        $results->when($request->that, function ($q) use ($request) {
            $q->where('that', $request->that);
        });
        $results->when($request->this, function ($q) use ($request) {
            $q->where('this', $request->that);
        });
        $results->when($request->this_too, function ($q) use ($request) {
            $q->where('this_too', $request->that);
        });
        $results->get();

多个where子句

    $query=DB::table('users')
        ->whereRaw("users.id BETWEEN 1003 AND 1004")
        ->whereNotIn('users.id', [1005,1006,1007])
        ->whereIn('users.id',  [1008,1009,1010]);
    $query->where(function($query2) use ($value)
    {
        $query2->where('user_type', 2)
            ->orWhere('value', $value);
    });

   if ($user == 'admin'){
        $query->where('users.user_name', $user);
    }

终于得到了结果

    $result = $query->get();

如果你的条件是这样的(匹配一个值),一个简单的更优雅的方式是:

$results = User::where([
         'this' => value,
         'that' => value,
         'this_too' => value,
          ...
      ])
    ->get();

但如果你需要OR子句,那么确保你对每个OR where()子句重复必须满足条件。

    $player = Player::where([
            'name' => $name,
            'team_id' => $team_id
        ])
        ->orWhere([
            ['nickname', $nickname],
            ['team_id', $team_id]
        ])

你可以这样做,这是最短的方法。

    $results = User::where(['this'=>1, 
              'that'=>1, 
               'this_too'=>1, 
               'that_too'=>1, 
              'this_as_well'=>1, 
               'that_as_well'=>1, 
                'this_one_too'=>1, 
               'that_one_too'=>1, 
              'this_one_as_well'=>1,
                'that_one_as_well'=>1])->get();