条件:不修改原有列表;只使用JDK,没有外部库。单行程序或JDK 1.3版本的加分项。

有没有比这更简单的方法:

List<String> newList = new ArrayList<String>();
newList.addAll(listOne);
newList.addAll(listTwo);

当前回答

你可以使用Apache的common -collections库:

List<String> newList = ListUtils.union(list1, list2);

其他回答

import java.util.AbstractList;
import java.util.List;


/**
 * The {@code ConcatList} is a lightweight view of two {@code List}s.
 * <p>
 * This implementation is <em>not</em> thread-safe even though the underlying lists can be.
 * 
 * @param <E>
 *            the type of elements in this list
 */
public class ConcatList<E> extends AbstractList<E> {

    /** The first underlying list. */
    private final List<E> list1;
    /** The second underlying list. */
    private final List<E> list2;

    /**
     * Constructs a new {@code ConcatList} from the given two lists.
     * 
     * @param list1
     *            the first list
     * @param list2
     *            the second list
     */
    public ConcatList(final List<E> list1, final List<E> list2) {
        this.list1 = list1;
        this.list2 = list2;
    }

    @Override
    public E get(final int index) {
        return getList(index).get(getListIndex(index));
    }

    @Override
    public E set(final int index, final E element) {
        return getList(index).set(getListIndex(index), element);
    }

    @Override
    public void add(final int index, final E element) {
        getList(index).add(getListIndex(index), element);
    }

    @Override
    public E remove(final int index) {
        return getList(index).remove(getListIndex(index));
    }

    @Override
    public int size() {
        return list1.size() + list2.size();
    }

    @Override
    public boolean contains(final Object o) {
        return list1.contains(o) || list2.contains(o);
    }

    @Override
    public void clear() {
        list1.clear();
        list2.clear();
    }

    /**
     * Returns the index within the corresponding list related to the given index.
     * 
     * @param index
     *            the index in this list
     * 
     * @return the index of the underlying list
     */
    private int getListIndex(final int index) {
        final int size1 = list1.size();
        return index >= size1 ? index - size1 : index;
    }

    /**
     * Returns the list that corresponds to the given index.
     * 
     * @param index
     *            the index in this list
     * 
     * @return the underlying list that corresponds to that index
     */
    private List<E> getList(final int index) {
        return index >= list1.size() ? list2 : list1;
    }

}

稍微简单:

List<String> newList = new ArrayList<String>(listOne);
newList.addAll(listTwo);

我们可以用两种方法使用java8连接两个列表。

    List<String> list1 = Arrays.asList("S", "T");
    List<String> list2 = Arrays.asList("U", "V");

1)使用concat:

    List<String> collect2 = Stream.concat(list1.stream(), list2.stream()).collect(toList());
    System.out.println("collect2 = " + collect2); // collect2 = [S, T, U, V]

2)使用flatMap:

    List<String> collect3 = Stream.of(list1, list2).flatMap(Collection::stream).collect(toList());
    System.out.println("collect3 = " + collect3); // collect3 = [S, T, U, V]

另一个Java 8一行代码:

List<String> newList = Stream.of(listOne, listTwo)
                            .flatMap(Collection::stream)
                            .collect(Collectors.toList());

另外,由于Stream.of()是可变的,您可以连接任意多的列表。

List<String> newList = Stream.of(listOne, listTwo, listThree)
                            .flatMap(Collection::stream)
                            .collect(Collectors.toList());

你可以通过一个静态导入和一个helper类来实现

注意这个类的泛化可能还有待改进

public class Lists {

   private Lists() { } // can't be instantiated

   public static List<T> join(List<T>... lists) {
      List<T> result = new ArrayList<T>();
      for(List<T> list : lists) {
         result.addAll(list);
      }
      return results;
   }

}

然后你就可以做

import static Lists.join;
List<T> result = join(list1, list2, list3, list4);