试试这个:

 $_SERVER['REMOTE_ADDR'];

下面是一个很好的获取用户IP地址的干净代码示例。

$ip = $_SERVER['HTTP_CLIENT_IP'] 
   ? $_SERVER['HTTP_CLIENT_IP'] 
   : ($_SERVER['HTTP_X_FORWARDED_FOR'] 
        ? $_SERVER['HTTP_X_FORWARDED_FOR'] 
        : $_SERVER['REMOTE_ADDR']);

下面是一个使用elvis操作符的简短版本:

$_SERVER['HTTP_CLIENT_IP'] 
   ? : ($_SERVER['HTTP_X_FORWARDED_FOR'] 
   ? : $_SERVER['REMOTE_ADDR']);

下面是一个使用isset删除通知的版本(谢谢你，@shasi kanth):

$ip = isset($_SERVER['HTTP_CLIENT_IP']) 
    ? $_SERVER['HTTP_CLIENT_IP'] 
    : (isset($_SERVER['HTTP_X_FORWARDED_FOR']) 
      ? $_SERVER['HTTP_X_FORWARDED_FOR'] 
      : $_SERVER['REMOTE_ADDR']);

答案是使用$_SERVER变量。例如，$_SERVER["REMOTE_ADDR"]将返回客户端的IP地址。

用于获取IP地址的安全和警告感知代码段:

$ip = filter_input(INPUT_SERVER, 'HTTP_CLIENT_IP', FILTER_VALIDATE_IP)
    ?: filter_input(INPUT_SERVER, 'HTTP_X_FORWARDED_FOR', FILTER_VALIDATE_IP)
    ?: $_SERVER['REMOTE_ADDR']
    ?? '0.0.0.0'; // Or other value fits "not defined" in your logic

echo $_SERVER['REMOTE_ADDR'];

http://php.net/manual/en/reserved.variables.server.php

这是我使用的方法，它验证IPv4输入:

// Get user IP address
if ( isset($_SERVER['HTTP_CLIENT_IP']) && ! empty($_SERVER['HTTP_CLIENT_IP'])) {
    $ip = $_SERVER['HTTP_CLIENT_IP'];
} elseif ( isset($_SERVER['HTTP_X_FORWARDED_FOR']) && ! empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
    $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
} else {
    $ip = (isset($_SERVER['REMOTE_ADDR'])) ? $_SERVER['REMOTE_ADDR'] : '0.0.0.0';
}

$ip = filter_var($ip, FILTER_VALIDATE_IP);
$ip = ($ip === false) ? '0.0.0.0' : $ip;