if re.search(r"\b(?<=\w)%s\b(?!\w)" % TEXTO, subject, re.IGNORECASE):

这将把TEXTO中的内容作为字符串插入到正则表达式中。

我需要搜索彼此相似的用户名，Ned Batchelder说的非常有用。然而，当我使用re.compile创建我的re搜索项时，我发现我有更清晰的输出:

pattern = re.compile(r"("+username+".*):(.*?):(.*?):(.*?):(.*)"
matches = re.findall(pattern, lines)

输出可以使用以下命令打印:

print(matches[1]) # prints one whole matching line (in this case, the first line)
print(matches[1][3]) # prints the fourth character group (established with the parentheses in the regex statement) of the first line.

我发现通过将多个较小的模式串在一起来构建正则表达式模式非常方便。

import re

string = "begin:id1:tag:middl:id2:tag:id3:end"
re_str1 = r'(?<=(\S{5})):'
re_str2 = r'(id\d+):(?=tag:)'
re_pattern = re.compile(re_str1 + re_str2)
match = re_pattern.findall(string)
print(match)

输出:

[('begin', 'id1'), ('middl', 'id2')]

from re import search, IGNORECASE

def is_string_match(word1, word2):
    #  Case insensitively function that checks if two words are the same
    # word1: string
    # word2: string | list

    # if the word1 is in a list of words
    if isinstance(word2, list):
        for word in word2:
            if search(rf'\b{word1}\b', word, IGNORECASE):
                return True
        return False

    # if the word1 is same as word2
    if search(rf'\b{word1}\b', word2, IGNORECASE):
        return True
    return False

is_match_word = is_string_match("Hello", "hELLO") 
True

is_match_word = is_string_match("Hello", ["Bye", "hELLO", "@vagavela"])
True

is_match_word = is_string_match("Hello", "Bye")
False

我同意以上所有观点，除非:

sys。argv[1]有点像Chicken\d{2}-\d{2}一个\s*重要的\s*锚

sys.argv[1] = "Chicken\d{2}-\d{2}An\s*important\s*anchor"

你不会想要使用re.escape，因为在这种情况下，你希望它表现得像一个正则表达式

TEXTO = sys.argv[1]

if re.search(r"\b(?<=\w)" + TEXTO + "\b(?!\w)", subject, re.IGNORECASE):
    # Successful match
else:
    # Match attempt failed

rx = r'\b(?<=\w){0}\b(?!\w)'.format(TEXTO)