我知道如何通过编程来做到这一点，但我相信有一种内置的方式……
我使用过的每种语言都有某种对象集合的默认文本表示，当您试图将Array与字符串连接起来或将其传递给print()函数等时，它会吐出这些文本表示。苹果的Swift语言是否有一种内置的方式，可以轻松地将数组转换为字符串，或者我们总是必须显式地对数组进行字符串化?
当前回答
如果你的问题是这样的: tobeFormattedString = ["a"， "b"， "c"] 输出= "abc"
String（tobeFormattedString）
其他回答
对于某些语言(如希伯来语或日语)，分隔符可能不是一个好主意。 试试这个:
// Array of Strings
let array: [String] = ["red", "green", "blue"]
let arrayAsString: String = array.description
let stringAsData = arrayAsString.data(using: String.Encoding.utf16)
let arrayBack: [String] = try! JSONDecoder().decode([String].self, from: stringAsData!)
对于其他数据类型，分别为:
// Set of Doubles
let set: Set<Double> = [1, 2.0, 3]
let setAsString: String = set.description
let setStringAsData = setAsString.data(using: String.Encoding.utf16)
let setBack: Set<Double> = try! JSONDecoder().decode(Set<Double>.self, from: setStringAsData!)
使用Swift 5，根据您的需要，您可以选择以下Playground示例代码之一来解决您的问题。
将字符数组转换为不带分隔符的字符串:
let characterArray: [Character] = ["J", "o", "h", "n"]
let string = String(characterArray)
print(string)
// prints "John"
将String数组转换为不带分隔符的String:
let stringArray = ["Bob", "Dan", "Bryan"]
let string = stringArray.joined(separator: "")
print(string) // prints: "BobDanBryan"
将字符串数组转换为单词之间带有分隔符的字符串:
let stringArray = ["Bob", "Dan", "Bryan"]
let string = stringArray.joined(separator: " ")
print(string) // prints: "Bob Dan Bryan"
将字符串数组转换为字符之间带有分隔符的字符串:
let stringArray = ["car", "bike", "boat"]
let characterArray = stringArray.flatMap { $0 }
let stringArray2 = characterArray.map { String($0) }
let string = stringArray2.joined(separator: ", ")
print(string) // prints: "c, a, r, b, i, k, e, b, o, a, t"
将float数组转换为数字之间带有分隔符的String:
let floatArray = [12, 14.6, 35]
let stringArray = floatArray.map { String($0) }
let string = stringArray.joined(separator: "-")
print(string)
// prints "12.0-14.6-35.0"
修改一个可选/非可选字符串数组
//Array of optional Strings
let array : [String?] = ["1",nil,"2","3","4"]
//Separator String
let separator = ","
//flatMap skips the nil values and then joined combines the non nil elements with the separator
let joinedString = array.flatMap{ $0 }.joined(separator: separator)
//Use Compact map in case of **Swift 4**
let joinedString = array.compactMap{ $0 }.joined(separator: separator
print(joinedString)
这里是flatMap, compactMap跳过数组中的nil值，并附加其他值以给出一个连接字符串。
Swift 2.0 Xcode 7.0 beta 6以上使用joinWithSeparator()代替join():
var array = ["1", "2", "3"]
let stringRepresentation = array.joinWithSeparator("-") // "1-2-3"
joinWithSeparator被定义为SequenceType的扩展
extension SequenceType where Generator.Element == String {
/// Interpose the `separator` between elements of `self`, then concatenate
/// the result. For example:
///
/// ["foo", "bar", "baz"].joinWithSeparator("-|-") // "foo-|-bar-|-baz"
@warn_unused_result
public func joinWithSeparator(separator: String) -> String
}
斯威夫特3
["I Love","Swift"].joined(separator:" ") // previously joinWithSeparator(" ")
