当你也有struct数组时，你可以使用joined()来获得单个String。

struct Person{
    let name:String
    let contact:String
}

使用map() & joined()可以轻松生成字符串

PersonList.map({"\($0.name) - \($0.contact)"}).joined(separator: " | ")

输出:

Jhon - 123 | Mark - 456 | Ben - 789  

你可以使用循环来完成这个任务。或者使用地图。

通过映射:

let array = ["one" , "two" , "three"]
    
array.map({$0}).joined(seperator : ",")

在分隔符中，你可以修改字符串。

Output-> ("one,two,three")

当你也有struct数组时，你可以使用joined()来获得单个String。

struct Person{
    let name:String
    let contact:String
}

使用map() & joined()可以轻松生成字符串

PersonList.map({"\($0.name) - \($0.contact)"}).joined(separator: " | ")

输出:

Jhon - 123 | Mark - 456 | Ben - 789  

在Swift 2.2中，你可能不得不将数组转换为NSArray来使用componentsJoinedByString("，")

let stringWithCommas = (yourArray as NSArray).componentsJoinedByString(",")

let arrayTemp :[String] = ["Mani","Singh","iOS Developer"]
    let stringAfterCombining = arrayTemp.componentsJoinedByString(" ")
   print("Result will be >>>  \(stringAfterCombining)")

结果将>>> Mani Singh iOS开发者

修改一个可选/非可选字符串数组

//Array of optional Strings
let array : [String?] = ["1",nil,"2","3","4"]

//Separator String
let separator = ","

//flatMap skips the nil values and then joined combines the non nil elements with the separator
let joinedString = array.flatMap{ $0 }.joined(separator: separator)


//Use Compact map in case of **Swift 4**
    let joinedString = array.compactMap{ $0 }.joined(separator: separator

print(joinedString)

这里是flatMap, compactMap跳过数组中的nil值，并附加其他值以给出一个连接字符串。