我的工作在NSMutableArray与componentsJoinedByString

var array = ["1", "2", "3"]
let stringRepresentation = array.componentsJoinedByString("-") // "1-2-3"

斯威夫特3

["I Love","Swift"].joined(separator:" ") // previously joinWithSeparator(" ")

在Swift 2.2中，你可能不得不将数组转换为NSArray来使用componentsJoinedByString("，")

let stringWithCommas = (yourArray as NSArray).componentsJoinedByString(",")

当您想要将结构类型的列表转换为字符串时，请使用此方法

struct MyStruct {
  var name : String
  var content : String
}

let myStructList = [MyStruct(name: "name1" , content: "content1") , MyStruct(name: "name2" , content: "content2")]

然后像这样隐藏你的数组

let myString = myStructList.map({$0.name}).joined(separator: ",")

将产生===> "name1,name2"

Swift 2.0 Xcode 7.0 beta 6以上使用joinWithSeparator()代替join():

var array = ["1", "2", "3"]
let stringRepresentation = array.joinWithSeparator("-") // "1-2-3"

joinWithSeparator被定义为SequenceType的扩展

extension SequenceType where Generator.Element == String {
    /// Interpose the `separator` between elements of `self`, then concatenate
    /// the result.  For example:
    ///
    ///     ["foo", "bar", "baz"].joinWithSeparator("-|-") // "foo-|-bar-|-baz"
    @warn_unused_result
    public func joinWithSeparator(separator: String) -> String
}

对于任何元素类型

extension Array {

    func joined(glue:()->Element)->[Element]{
        var result:[Element] = [];
        result.reserveCapacity(count * 2);
        let last = count - 1;
        for (ix,item) in enumerated() {
            result.append(item);
            guard ix < last else{ continue }
            result.append(glue());
        }
        return result;
    }
}