Swift 2.0 Xcode 7.0 beta 6以上使用joinWithSeparator()代替join():

var array = ["1", "2", "3"]
let stringRepresentation = array.joinWithSeparator("-") // "1-2-3"

joinWithSeparator被定义为SequenceType的扩展

extension SequenceType where Generator.Element == String {
    /// Interpose the `separator` between elements of `self`, then concatenate
    /// the result.  For example:
    ///
    ///     ["foo", "bar", "baz"].joinWithSeparator("-|-") // "foo-|-bar-|-baz"
    @warn_unused_result
    public func joinWithSeparator(separator: String) -> String
}

对于swift 3:

func textField(textField: UITextField, shouldChangeCharactersInRange range: NSRange, replacementString string: String) -> Bool {
    if textField == phoneField
    {
        let newString = NSString(string: textField.text!).replacingCharacters(in: range, with: string)
        let components = newString.components(separatedBy: NSCharacterSet.decimalDigits.inverted)

        let decimalString = NSString(string: components.joined(separator: ""))
        let length = decimalString.length
        let hasLeadingOne = length > 0 && decimalString.character(at: 0) == (1 as unichar)

        if length == 0 || (length > 10 && !hasLeadingOne) || length > 11
        {
            let newLength = NSString(string: textField.text!).length + (string as NSString).length - range.length as Int

            return (newLength > 10) ? false : true
        }
        var index = 0 as Int
        let formattedString = NSMutableString()

        if hasLeadingOne
        {
            formattedString.append("1 ")
            index += 1
        }
        if (length - index) > 3
        {
            let areaCode = decimalString.substring(with: NSMakeRange(index, 3))
            formattedString.appendFormat("(%@)", areaCode)
            index += 3
        }
        if length - index > 3
        {
            let prefix = decimalString.substring(with: NSMakeRange(index, 3))
            formattedString.appendFormat("%@-", prefix)
            index += 3
        }

        let remainder = decimalString.substring(from: index)
        formattedString.append(remainder)
        textField.text = formattedString as String
        return false
    }
    else
    {
        return true
    }
}

当您想要将结构类型的列表转换为字符串时，请使用此方法

struct MyStruct {
  var name : String
  var content : String
}

let myStructList = [MyStruct(name: "name1" , content: "content1") , MyStruct(name: "name2" , content: "content2")]

然后像这样隐藏你的数组

let myString = myStructList.map({$0.name}).joined(separator: ",")

将产生===> "name1,name2"

你可以使用循环来完成这个任务。或者使用地图。

通过映射:

let array = ["one" , "two" , "three"]
    
array.map({$0}).joined(seperator : ",")

在分隔符中，你可以修改字符串。

Output-> ("one,two,three")

如果你想转换自定义对象数组为字符串或逗号分隔字符串(csv)，你可以使用

 var stringIds = (self.mylist.map{$0.id ?? 0}).map{String($0)}.joined(separator: ",")

归功于:莫迪 post:将int数组转换为逗号分隔的字符串

如果数组包含字符串，你可以使用String的join方法:

var array = ["1", "2", "3"]

let stringRepresentation = "-".join(array) // "1-2-3"

在Swift 2中:

var array = ["1", "2", "3"]

let stringRepresentation = array.joinWithSeparator("-") // "1-2-3"

如果您想使用特定的分隔符(连字符、空格、逗号等)，这可能很有用。

否则，你可以简单地使用description属性，它返回数组的字符串表示形式:

let stringRepresentation = [1, 2, 3].description // "[1, 2, 3]"

提示:任何实现Printable协议的对象都有一个description属性。如果你在自己的类/结构中采用该协议，你也可以使它们打印友好

在Swift 3中

join变为joined，示例[nil， "1"， "2"].flatMap({$0}).joined() joinWithSeparator变成了joined(separator:)(仅适用于字符串数组)

在Swift 4中

var array = ["1", "2", "3"]
array.joined(separator:"-")